如何在NSUserDefault中存储CCSprite
如何在NSUserDefault中存储CCSprite
提问于 2012-01-21 22:18:26
在使用CCSprite子类生物时，我遇到了一个奇怪的问题。
让我们，我的对象是生物*生物；
类生物声明-
@interface Creature : CCSprite <NSCoding>{
int creatureAge;
NSString *creatureName;
}实现
+(id)initializeCreatureWithType:(int)type
{
Creature *creature = nil;
creature = [[[super alloc] initWithFile:[NSString stringWithFormat:@"ch%i_default.png",type]]autorelease];
return creature;
}问题是当我在NSUserDefault中存储我的生物类对象‘生物’时-
- (void)encodeWithCoder:(NSCoder *)encoder {
[encoder encodeObject:self.creatureName forKey:@"creatureName"];
[encoder encodeInt:self.creatureAge forKey:@"creatureAge"];
}把它解码成-
- (id)initWithCoder:(NSCoder *)decoder {
if((self = [super init])) {
self.creatureName = [decoder decodeObjectForKey:@"creatureName"];
self.creatureAge= [decoder decodeIntForKey:@"creatureAge"];
}然后使用以下命令保存生物对象-
NSUserDefaults *defaults = [NSUserDefaults standardUserDefaults];
NSData *myEncodedObject = [NSKeyedArchiver archivedDataWithRootObject:creature];
[defaults setObject:myEncodedObject forKey:@"my_pet"];以及负载-
NSUserDefaults *defaults = [NSUserDefaults standardUserDefaults];
NSData *myEncodedObject = [defaults objectForKey:@"my_pet"];
Creature* newcreature = (Creature *)[NSKeyedUnarchiver unarchiveObjectWithData: myEncodedObject];问题是，当我加载它时，我得到了先前存储的生物的属性值，但分配给先前生物的图像可能没有复制。因为如果我将新的生物添加到任何CCLayer中，它不会显示任何图像，尽管它获得了前一个生物的属性值。
我现在该怎么做才能让这个新生物有图像呢？是否需要添加镜像名称作为单独的属性？
回答 1
Stack Overflow用户
回答已采纳
发布于 2012-01-21 22:36:29
您也可以简单地存储类型，然后像这样做：
@interface Creature : CCSprite {
int creatureType;
int creatureAge;
NSString *creatureName;
}
+ (id)creatureWithType:(int)type;
- (id)initWithCreatureType:(int)type;
@end
@implementation Creature
+ (id)creatureWithType:(int)type
{
return [[[[self class] alloc] initWithCreatureType:type] autorelease];
}
- (id)initWithCreatureType:(int)type
{
self = [super initWithFile:[NSString stringWithFormat:@"ch%i_default.png", type]];
if (!self) return nil;
creatureType = type;
return self;
}
- (id)initWithCoder:(NSCoder *)decoder {
int type = [decoder decodeIntForKey:@"creatureType"];
self = [self initWithCreatureType:type];
if (!self) return nil;
self.creatureName = [decoder decodeObjectForKey:@"creatureName"];
self.creatureAge= [decoder decodeIntForKey:@"creatureAge"];
return self;
}
- (void)encodeWithCoder:(NSCoder *)encoder
{
[encoder encodeInt:creatureType forKey:@"creatureType"];
[encoder encodeObject:self.creatureName forKey:@"creatureName"];
[encoder encodeInt:self.creatureAge forKey:@"creatureAge"];
}
@end您可能还希望通过属性公开creatureType。请注意，使用名称creatureWithType:而不是initializeCreatureWithType:是“更多可可”。
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/8953661
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