blocks|key|309677|text|你可以在下面的代码中比较javascript中的日期|type|unstyled|depth|inlineStyleRanges|entityRanges|data|309678|var+x=new+Date();
x.setFullYear(2100,0,14);
var+today+=+new+Date();

if+(x>today)
{
++alert("Today+is+before+14th+January+2100");
}
else
{
++alert("Today+is+after+14th+January+2100");
}|code-block|syntax|javascript|309679|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

you can compare date in javascript
check following code

<pre><code>var x=new Date();
x.setFullYear(2100,0,14);
var today = new Date();

if (x&gt;today)
{
 alert("Today is before 14th January 2100");
}
else
{
 alert("Today is after 14th January 2100");
}
</code></pre>

blocks|key|155104|text|您需要使用Date对象函数来提取小时、分钟和秒，以便从日期中仅获取时间：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|155105|var+currentDate+=+new+Date();
var+hours+=+currentDate.getHours();
var+minutes+=+currentDate.getMinutes();
var+seconds+=+currentDate.getSeconds();|code-block|syntax|javascript|155106|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You'll need to use the Date object functions to pull out the hours minutes and seconds to get just the time from a Date:

<pre><code>var currentDate = new Date();
var hours = currentDate.getHours();
var minutes = currentDate.getMinutes();
var seconds = currentDate.getSeconds();
</code></pre>

blocks|key|4196207|text|使用DateJS时，您可以使用以下方法compareTo|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4196208|var+past+=+Date.today().add(-6).days();
var+future+=+Date.today().add(6).days();

Date.today().compareTo(future);+++++++++++++++++//+-1
Date.today().compareTo(new+Date().clearTime());+//+0
Date.today().compareTo(past);+++++++++++++++++++//+1|code-block|syntax|javascript|4196209|如果您不想使用整个库，这里是DateJS中静态compare方法的源代码|style|CODE|4196210|Date.compare+=+function+(date1,+date2)+{
++++if+(isNaN(date1)+%7C%7C+isNaN(date2))+{+
++++++++throw+new+Error(date1+%2B+"+-+"+%2B+date2);+
++++}+else+if+(date1+instanceof+Date+&&+date2+instanceof+Date)+{
++++++++return+(date1+<+date2)+?+-1+:+(date1+>+date2)+?+1+:+0;
++++}+else+{+
++++++++throw+new+TypeError(date1+%2B+"+-+"+%2B+date2);+
++++}
};|4196211|这对于时间也有效，因为两个日期(yyyy-MM-dd)是相同的|4196212|entityMap|0|LINK|mutability|MUTABLE|url|http://www.datejs.com/|1|http://code.google.com/p/datejs/wiki/APIDocumentation#compareTo^0|2|6|0|J|9|1|0|0|N|7|0|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@$A|11|B|12|1|13]|$A|14|B|15|1|16]]|C|$]]|$1|D|3|E|5|F|7|17|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|18|8|@$A|19|B|1A|K|L]]|9|@]|C|$]]|$1|M|3|N|5|F|7|1B|8|@]|9|@]|C|$G|H]]|$1|O|3|P|5|6|7|1C|8|@]|9|@]|C|$]]|$1|Q|3|-4|5|6|7|1D|8|@]|9|@]|C|$]]]|R|$S|$5|T|U|V|C|$W|X]]|Y|$5|T|U|V|C|$W|Z]]]]

Using <a href="http://www.datejs.com/" rel="nofollow">DateJS</a> you can use the following method <a href="http://code.google.com/p/datejs/wiki/APIDocumentation#compareTo" rel="nofollow">compareTo</a>

<pre><code>var past = Date.today().add(-6).days();
var future = Date.today().add(6).days();

Date.today().compareTo(future); // -1
Date.today().compareTo(new Date().clearTime()); // 0
Date.today().compareTo(past); // 1
</code></pre>

if you do not want to use a whole library here is the source code for the static <code>compare</code> method in DateJS

<pre><code>Date.compare = function (date1, date2) {
 if (isNaN(date1) || isNaN(date2)) { 
 throw new Error(date1 + " - " + date2); 
 } else if (date1 instanceof Date &amp;&amp; date2 instanceof Date) {
 return (date1 &lt; date2) ? -1 : (date1 &gt; date2) ? 1 : 0;
 } else { 
 throw new TypeError(date1 + " - " + date2); 
 }
};
</code></pre>

This will work for time as well asuming that both dates (yyyy-MM-dd) are the same

blocks|key|1330675|text|比方说，比方说选择的时间|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1330676|var+startTime+=+"09:15";
var+endTime+="10:15";

if(parseInt(startTime.split(":")[0],10)+>+parseInt(endTime.split(":")[0],10))
alert("Start+Time+should+not+be+greater+than+end+time");
else
alert("Valid+Time");|code-block|syntax|javascript|1330677|希望这能有所帮助。|1330678|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

For example lets say the time picked for example

<pre><code>var startTime = "09:15";
var endTime ="10:15";

if(parseInt(startTime.split(":")[0],10) &gt; parseInt(endTime.split(":")[0],10))
alert("Start Time should not be greater than end time");
else
alert("Valid Time");
</code></pre>

Hope this helps.

I want to compare only time on client side, means the start time should not be greater than end time. I have searched on net but not able resolve this problem. Please help me as soon as possible. Thanks in advance.

how to compare only time in javascript?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我只想比较客户端的时间，这意味着开始时间不应该大于结束时间。我已经在网上搜索过了，但是没能解决这个问题。请尽快帮助我。提前谢谢。

问如何在javascript中只比较时间？
EN

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问如何在javascript中只比较时间？EN