blocks|key|4535745|text|不能将布尔值转换为int。这些是完全不同的类型。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4535746|但是您可以编写一个实用方法booleanToInt(boolean+b)，它将布尔值转换为整型。|offset|length|style|CODE|4535747|entityMap^0|0|D|N|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|K|8|@$D|L|E|M|F|G]]|9|@]|A|$]]|$1|H|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|I|$]]

You can't cast a boolean to an int. These are completely different types. 

But you can write a utility method <code>booleanToInt(boolean b)</code> which transforms a boolean into an int.

blocks|key|1500890|text|这不是本教程要求您做的事情。我想他们想让你用int替换boolean，用1替换true，用0替换false，就像这样：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1500891|int+p,+q;
System.out.println("P\tQ\tAND\tOR\tXOR\tNOT");
p+=+1;+q+=+1;
System.out.print(p+%2B+"\t"+%2B+q+%2B+"\t");
System.out.print((p&q)+%2B+"\t"+%2B+(p%7Cq)+%2B+"\t");
System.out.println((p%5Eq)+%2B+"\t"+%2B+(1-p));+//+EDIT:+was+!p|code-block|syntax|javascript|1500892|这将引导您理解整数0和1上的按位操作。|1500893|entityMap^0|M|3|R|7|10|1|13|4|19|1|1C|5|0|0|9|1|B|1|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]|$9|T|A|U|B|C]|$9|V|A|W|B|C]|$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|12|8|@$9|13|A|14|B|C]|$9|15|A|16|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|17|8|@]|D|@]|E|$]]]|N|$]]

This is not what the tutorial asks you to do. I think they want you to literally replace <code>boolean</code> with <code>int</code>, <code>true</code> with <code>1</code>, and <code>false</code> with <code>0</code>, like this:

<pre><code>int p, q;
System.out.println("P\tQ\tAND\tOR\tXOR\tNOT");
p = 1; q = 1;
System.out.print(p + "\t" + q + "\t");
System.out.print((p&amp;q) + "\t" + (p|q) + "\t");
System.out.println((p^q) + "\t" + (1-p)); // EDIT: was !p
</code></pre>

This will lead you to understanding of bitwise operations on integers <code>0</code> and <code>1</code>.

blocks|key|4535792|text|在Java中，不能将boolean直接转换为int类型。我将添加一个类似以下内容的方法|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4535793|public+int+getBoolValue(boolean+b)+{
+return+b+?+1+:+0|code-block|syntax|javascript|4535794|}|4535795|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You can't cast directly from a boolean to an int in Java. I would add a method along the lines of 

<pre><code>public int getBoolValue(boolean b) {
 return b ? 1 : 0
</code></pre>

}

blocks|key|481438|text|在java中，不能将int转换为boolean。考虑使用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|481439|boolean+x+=+p+&+q;
boolean+y+=+p+%7C+q;

(x+?+1+:+0)|code-block|syntax|javascript|481440|例如|481441|System.out.print((p&q)+%2B+"\t"+%2B+(p%7Cq)+%2B+"\t");|481442|可能会变成：|481443|System.out.print(x+%2B+"\t"+%2B+y+%2B+"\t");|481444|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

You cannot cast int to boolean in java. Think of using 

<pre class="lang-java prettyprint-override"><code>boolean x = p &amp; q;
boolean y = p | q;

(x ? 1 : 0)
</code></pre>

For example

<pre class="lang-java prettyprint-override"><code>System.out.print((p&amp;q) + "\t" + (p|q) + "\t");
</code></pre>

May become:

<pre class="lang-java prettyprint-override"><code>System.out.print(x + "\t" + y + "\t");
</code></pre>

blocks|key|1497336|text|看起来您只需要将变量声明为int，并将0和1赋值给p和q，并确保在所有情况下都使用java's+bitwise+operators+(乍一看，似乎是这样)。More+info+on+bitwise+operation+from+wikipedia。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1497337|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/tutorial/java/nutsandbolts/op3.html|1|http://en.wikipedia.org/wiki/Bitwise_operation^0|D|3|J|1|L|1|P|1|R|1|15|O|0|26|19|1|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]|$9|S|A|T|B|C]|$9|U|A|V|B|C]|$9|W|A|X|B|C]|$9|Y|A|Z|B|C]]|D|@$9|10|A|11|1|12]|$9|13|A|14|1|15]]|E|$]]|$1|F|3|-4|5|6|7|16|8|@]|D|@]|E|$]]]|G|$H|$5|I|J|K|E|$L|M]]|N|$5|I|J|K|E|$L|O]]]]

It looks like you just need to declare your variables as <code>int</code>s and assign <code>0</code> and <code>1</code> to <code>p</code> and <code>q</code>, and make sure you're using <a href="http://docs.oracle.com/javase/tutorial/java/nutsandbolts/op3.html" rel="nofollow">java's bitwise operators</a> in all cases (at first glance it looks like you are). <a href="http://en.wikipedia.org/wiki/Bitwise_operation" rel="nofollow">More info on bitwise operation from wikipedia</a>.

blocks|key|481466|text|只需使用三元运算符：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|481467|int+logicalInt+=+boolVal?+1+:+0;|code-block|syntax|javascript|481468|其中"boolVal“是您的布尔变量。|481469|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Just use the ternary operator:

<pre><code>int logicalInt = boolVal? 1 : 0;
</code></pre>

where "boolVal" is your boolean variable.

blocks|key|497856|text|可以将整数与按位运算符一起使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|497857|int+p,+q;

System.out.println("P\tQ\tAND\tOR\tXOR\tNOT");
p+=+1;
q+=+1;

System.out.print(p+%2B+"\t"+%2B+q+%2B+"\t");
System.out.print((p+&+q)+%2B+"\t"+%2B+(p+%7C+q)+%2B+"\t");
System.out.println((p+%5E+q)+%2B+"\t"+%2B+(1-p));

p+=+1;
q+=+0;
System.out.print(p+%2B+"\t"+%2B+q+%2B+"\t");
System.out.print((p+&+q)+%2B+"\t"+%2B+(p+%7C+q)+%2B+"\t");
System.out.println((p+%5E+q)+%2B+"\t"+%2B+(1-p));

p+=+0;
q+=+1;
System.out.print(p+%2B+"\t"+%2B+q+%2B+"\t");
System.out.print((p+&+q)+%2B+"\t"+%2B+(p+%7C+q)+%2B+"\t");
System.out.println((p+%5E+q)+%2B+"\t"+%2B+(1-p));

p+=+0;
q+=+0;
System.out.print(p+%2B+"\t"+%2B+q+%2B+"\t");
System.out.print((p+&+q)+%2B+"\t"+%2B+(p+%7C+q)+%2B+"\t");
System.out.println((p+%5E+q)+%2B+"\t"+%2B+(1-p));|code-block|syntax|javascript|497858|返回：|497859|P+++Q+++AND+OR++XOR+NOT
1+++1+++1+++1+++0+++0
1+++0+++0+++1+++1+++0
0+++1+++0+++1+++1+++1
0+++0+++0+++0+++0+++1|497860|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

You can use integers together with bitwise operators:

<pre class="lang-java prettyprint-override"><code>int p, q;

System.out.println("P\tQ\tAND\tOR\tXOR\tNOT");
p = 1;
q = 1;

System.out.print(p + "\t" + q + "\t");
System.out.print((p &amp; q) + "\t" + (p | q) + "\t");
System.out.println((p ^ q) + "\t" + (1-p));

p = 1;
q = 0;
System.out.print(p + "\t" + q + "\t");
System.out.print((p &amp; q) + "\t" + (p | q) + "\t");
System.out.println((p ^ q) + "\t" + (1-p));

p = 0;
q = 1;
System.out.print(p + "\t" + q + "\t");
System.out.print((p &amp; q) + "\t" + (p | q) + "\t");
System.out.println((p ^ q) + "\t" + (1-p));

p = 0;
q = 0;
System.out.print(p + "\t" + q + "\t");
System.out.print((p &amp; q) + "\t" + (p | q) + "\t");
System.out.println((p ^ q) + "\t" + (1-p));
</code></pre>

Returns:

<pre><code>P Q AND OR XOR NOT
1 1 1 1 0 0
1 0 0 1 1 0
0 1 0 1 1 1
0 0 0 0 0 1
</code></pre>

blocks|key|497881|text|这是我的解决方案//逻辑表，使用1和0|type|unstyled|depth|inlineStyleRanges|entityRanges|data|497882|类LogicOpTable+{|497883|public+static+void+main(String+args[])+{

+++int+p,+q;

+++System.out.println("P\tQ\t"%2B
+++++++++++++"AND\tOR\tXOR\tNOT");
+++for+(p+=+1;+p+>=+0;+p--)+{
++++for+(q+=+1;+q+>=+0;+q--)+{

+++System.out.println(p+%2B+"\t"+%2B+q+%2B+"\t"+%2B
+++++++++++++(p+&+q)+%2B+"\t"+%2B+(p+%7C+q)+%2B+
+++++++++++++++++++++"\t"+%2B+(p+%5E+q)+%2B+"\t"+%2B+(1+-+p));
+++++}
++}+++++++++++++++|code-block|syntax|javascript|497884|}}|497885|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|N|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|O|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

This was my solution
//Logic table using 1 and 0

class LogicOpTable {

<pre><code>public static void main(String args[]) {

 int p, q;

 System.out.println("P\tQ\t"+
 "AND\tOR\tXOR\tNOT");
 for (p = 1; p &gt;= 0; p--) {
 for (q = 1; q &gt;= 0; q--) {

 System.out.println(p + "\t" + q + "\t" +
 (p &amp; q) + "\t" + (p | q) + 
 "\t" + (p ^ q) + "\t" + (1 - p));
 }
 } 
</code></pre>

}
}

I am going through a tutorial where so far it gives you the code below:

<pre><code>boolean p, q;

 System.out.println("P\tQ\tAND\tOR\tXOR\tNOT");
 p = true; q = true;

 System.out.print(p + "\t" + q + "\t");
 System.out.print((p&amp;q) + "\t" + (p|q) + "\t");
 System.out.println((p^q) + "\t" + (!p));

 p = true; q = false;
 System.out.print(p + "\t" + q + "\t");
 System.out.print((p&amp;q) + "\t" + (p|q) + "\t");
 System.out.println((p^q) + "\t" + (!p));

 p = false; q = true;
 System.out.print(p + "\t" + q + "\t");
 System.out.print((p&amp;q) + "\t" + (p|q) + "\t");
 System.out.println((p^q) + "\t" + (!p));

 p = false; q = false;
 System.out.print(p + "\t" + q + "\t");
 System.out.print((p&amp;q) + "\t" + (p|q) + "\t");
 System.out.println((p^q) + "\t" + (!p));
</code></pre>

The task is to modify the program so that it uses <code>1's</code> and <code>0's</code> instead of <code>true</code> and <code>false</code>.

Im not sure if this is ment to be done by Casting Incompatible Types but I think that is the way to go as that is the section before it.

Can anyone give some advice and explanation as to why it works?

Casting Boolean To Int

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在看一个教程，到目前为止，它给出了以下代码：boolean p, q;    System.out.println("P\tQ\tAND\tOR\tXOR\tNOT");    p = true; q = true;    System.out.print(p + "\t" + q + "\t");    Syst...

问将布尔值转换为Int
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问将布尔值转换为IntEN