这就是我得到的。
<script type="text/javascript">
function show_confirm(id)
{
var r=confirm("Are you sure you want to duplicate this record?");
if (r==true)
{
window.open ("http://domain.com/process.php?duplicate=id","mywindow");
}
else
{
alert("Record Not Duplicated.");
}
}
</script>然后在下面:
$query = "SELECT * FROM contacts";
$result = mysql_query($query);
while($row = mysql_fetch_row($result)){
$id = $row[0];
$company = $row[3];
$firstName = $row[4];
$protection = $row[20];
echo '<tr>';
echo '<td width="120" align="middle"><font color="black"><b>' . $company . '</b></font></td>';
echo '<td width="120" align="middle"><font color="black"><b>' . $firstName . '</b></font></td>';
echo "<td width='120' align='middle'><a style='text-decoration: none;' href='http://domain.com/index.php?id=14&edit=" . $id . "'><span style='font-family:Helvetica; color:black;'>Edit</span></a>";
echo "<td width='120' align='middle'><input type='button' onclick='show_confirm($id)' value='Duplicate' />";
echo "</td>";
echo '</tr>';
}
?>问题是:
echo "<td width='120' align='middle'><input type='button' onclick='show_confirm($id)' value='Duplicate' />";这应该是一个按钮,当用户单击它时,它会显示"are you sure you want to duplicate?",如果用户单击yes,它就会显示http://domain.com/process.php?duplicate=(whatever the ID is)
问题是我的变量(在php中) $id没有被传递给javascript window.open。我需要在javascript中传递行中的$id。我试着写它,但它不起作用。甚至看不到变量。我尝试过手动输入<?php echo $id; ?>,但效果不佳。
谢谢
发布于 2012-01-26 00:49:59
window.open ("http://domain.com/process.php?duplicate=id","mywindow");URL是字符串"http://domain.com/process.php?duplicate=id"。您需要将变量连接到字符串。LIke此命令:
"http://domain.com/process.php?duplicate="+id它应该看起来像这样:
window.open ("http://domain.com/process.php?duplicate="+id,"mywindow");https://stackoverflow.com/questions/9006527
复制相似问题