blocks|key|598385|text|您是否可以尝试使用TYPE_TEXT_VARIATION_NORMAL，而不是显示密码|type|unstyled|depth|inlineStyleRanges|entityRanges|data|598386|public+void+ShowPassword()+{
password.setInputType((cb.isChecked())+?+
InputType.TYPE_TEXT_VARIATION_NORMAL+:+InputType.TYPE_TEXT_VARIATION_PASSWORD;
}|code-block|syntax|javascript|598387|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

instead of visible password, can you try with TYPE_TEXT_VARIATION_NORMAL

<pre><code>public void ShowPassword() {
password.setInputType((cb.isChecked()) ? 
InputType.TYPE_TEXT_VARIATION_NORMAL : InputType.TYPE_TEXT_VARIATION_PASSWORD;
}
</code></pre>

blocks|key|733486|text|我不知道确切的细节，但这段代码应该可以工作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|733487|checkbox.setOnCheckedChangeListener(new+OnCheckedChangeListener()+{
++++++++++++@Override
++++++++++++public+void+onCheckedChanged(CompoundButton+buttonView,+boolean+isChecked)+{
++++++++++++++++if(!isChecked)+{
++++++++++++++++++++password.setInputType(InputType.TYPE_TEXT_VARIATION_PASSWORD);
++++++++++++++++}+else+{
++++++++++++++++++++password.setInputType(129);
++++++++++++++++}
++++++++++++}
++++++++});|code-block|syntax|javascript|733488|129是在设置android:inputType="textPassword"时设置的输入类型|offset|length|style|CODE|733489|编辑：|733490|正如@user370305的答案中所提到的，129是执行逐位或操作时的值|733491|password.setInputType(InputType.TYPE_CLASS_TEXT+%7C+InputType.TYPE_TEXT_VARIATION_PASSWORD);|733492|entityMap^0|0|0|0|3|7|W|0|0|M|3|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@$I|X|J|Y|K|L]|$I|Z|J|10|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|11|8|@]|9|@]|A|$]]|$1|O|3|P|5|6|7|12|8|@$I|13|J|14|K|L]]|9|@]|A|$]]|$1|Q|3|R|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|S|3|-4|5|6|7|16|8|@]|9|@]|A|$]]]|T|$]]

I don't know exactly the specifics, but this code should work:

<pre><code>checkbox.setOnCheckedChangeListener(new OnCheckedChangeListener() {
 @Override
 public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
 if(!isChecked) {
 password.setInputType(InputType.TYPE_TEXT_VARIATION_PASSWORD);
 } else {
 password.setInputType(129);
 }
 }
 });
</code></pre>

<code>129</code> is the input type set when setting <code>android:inputType="textPassword"</code>

edit:

as mentioned in @user370305's answer, <code>129</code> is the value of the bitwise or operation when you do

<pre><code>password.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);
</code></pre>

blocks|key|733536|text|这不是一个答案，|type|unstyled|depth|inlineStyleRanges|entityRanges|data|733537|答案已经给出并接受..|733538|我只想澄清关于129的事情|offset|length|style|CODE|733539|password.setInputType(129);|code-block|syntax|javascript|733540|实际上，|733541|password.setInputType(InputType.TYPE_CLASS_TEXT+%7C+InputType.TYPE_TEXT_VARIATION_PASSWORD);|733542|'%7C‘不是管道，它是bitwise+OR。它需要两个二进制数并且如果相等值的任一位是1，|BOLD|733543|这与输入类型有何关系:每个InputTypes实际上都只是int。TYPE_CLASS_TEXT+is+1和TYPE_TEXT_VARIATION_PASSWORD+is+128+(or+10000000)。|733544|对它们执行bitwise+OR：|733545|00000001

10000000

------------

10000001+which+is+129.|733546|尝试输入input.setInputType(129);，您将看到它可以工作。:)|733547|entityMap^0|0|0|7|3|0|0|0|0|0|7|A|A|0|X|K|1I|1D|0|5|A|0|0|4|O|0^^$0|@$1|2|3|4|5|6|7|15|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|16|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|17|8|@$F|18|G|19|H|I]]|9|@]|A|$]]|$1|J|3|K|5|L|7|1A|8|@]|9|@]|A|$M|N]]|$1|O|3|P|5|6|7|1B|8|@]|9|@]|A|$]]|$1|Q|3|R|5|L|7|1C|8|@]|9|@]|A|$M|N]]|$1|S|3|T|5|6|7|1D|8|@$F|1E|G|1F|H|U]|$F|1G|G|1H|H|I]]|9|@]|A|$]]|$1|V|3|W|5|6|7|1I|8|@$F|1J|G|1K|H|I]|$F|1L|G|1M|H|I]]|9|@]|A|$]]|$1|X|3|Y|5|6|7|1N|8|@$F|1O|G|1P|H|I]]|9|@]|A|$]]|$1|Z|3|10|5|L|7|1Q|8|@]|9|@]|A|$M|N]]|$1|11|3|12|5|6|7|1R|8|@$F|1S|G|1T|H|I]]|9|@]|A|$]]|$1|13|3|-4|5|6|7|1U|8|@]|9|@]|A|$]]]|14|$]]

This is not an answer,

Answer already given and accepted..

I just want to clarify about <code>129</code>

<pre><code>password.setInputType(129);
</code></pre>

is Actually,

<pre><code>password.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);
</code></pre>

'|' is not a pipe, it's a <code>bitwise OR</code>. It takes two binary numbers and if either of the bits of equal value are 1,

How this relates to the input type: Each of the InputTypes are actually just ints. 
<code>TYPE_CLASS_TEXT is 1</code>, and <code>TYPE_TEXT_VARIATION_PASSWORD is 128 (or 10000000)</code>.

Perform a <code>bitwise OR</code> on them:

<pre><code>00000001

10000000

------------

10000001 which is 129.
</code></pre>

Try entering <code>input.setInputType(129);</code> instead, you'll see it'll work. :)

blocks|key|4770845|text|好的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4770846|要显示可读文本，请执行以下操作：|4770847|setInputType(InputType.TYPE_CLASS_TEXT+%7C+InputType.TYPE_TEXT_VARIATION_PASSWORD)|code-block|syntax|javascript|4770848|要“星号”密码，请执行以下操作：|4770849|setInputType(InputType.TYPE_TEXT_VARIATION_PASSWORD)|4770850|但是为什么呢？Type_Text_Variation_Password将其设置为stars，但为什么只添加Type_Claas_Text才能恢复visibel密码？|offset|length|style|CODE|4770851|我本以为Type_Text_Variation_VISIBLE_Password会起作用..。|4770852|entityMap^0|0|0|0|0|0|7|S|1H|F|0|4|10|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|Z|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|10|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|11|8|@$O|12|P|13|Q|R]|$O|14|P|15|Q|R]]|9|@]|A|$]]|$1|S|3|T|5|6|7|16|8|@$O|17|P|18|Q|R]]|9|@]|A|$]]|$1|U|3|-4|5|6|7|19|8|@]|9|@]|A|$]]]|V|$]]

okay:

To show readeable text: 

<pre><code>setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD)
</code></pre>

To "star" the password: 

<pre><code>setInputType(InputType.TYPE_TEXT_VARIATION_PASSWORD)
</code></pre>

But why? The <code>Type_Text_Variation_Password</code> set it to stars, but why does only adding <code>Type_Claas_Text</code> revive the visibel password? 
I would have thought that <code>Type_Text_Variation_VISIBLE_Password</code> comes into play ...

blocks|key|598452|text|public+void+onCheckBox(View+v2)
{



++++CheckBox+cb+=+(CheckBox)this.findViewById(R.id.pass_Check);
++++EditText+et1=(EditText)this.findViewById(R.id.edt_Pass);
++++++++if(cb.isChecked())
++++++++{
++++++++et1.setInputType(InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD);
++++++++}
++++++++else+
++++++++{
++++++++et1.setInputType(129);
++++++++}

}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|598453|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>public void onCheckBox(View v2)
{



 CheckBox cb = (CheckBox)this.findViewById(R.id.pass_Check);
 EditText et1=(EditText)this.findViewById(R.id.edt_Pass);
 if(cb.isChecked())
 {
 et1.setInputType(InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD);
 }
 else 
 {
 et1.setInputType(129);
 }

}
</code></pre>

blocks|key|733623|text|我想你用错了函数。我做到了这一点，而且工作得很完美：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|733624|passwordEditView+=+(EditText)+rootView.findViewById(R.id.password);
final+CheckBox+showPasswordCheckBox+=+(CheckBox)+rootView.findViewById(R.id.checkbox);
showPasswordCheckBox.setOnClickListener(new+View.OnClickListener()+{
++++@Override
++++public+void+onClick(View+view)+{
++++++++if+(showPasswordCheckBox.isChecked()){
++++++++++++passwordEditView.setTransformationMethod(null);
++++++++}else{
++++++++++++passwordEditView.setTransformationMethod(new+PasswordTransformationMethod());
+++++++}
++++}
});|code-block|syntax|javascript|733625|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I think you are using the wrong function. I make that way and work perfectly:

<pre><code>passwordEditView = (EditText) rootView.findViewById(R.id.password);
final CheckBox showPasswordCheckBox = (CheckBox) rootView.findViewById(R.id.checkbox);
showPasswordCheckBox.setOnClickListener(new View.OnClickListener() {
 @Override
 public void onClick(View view) {
 if (showPasswordCheckBox.isChecked()){
 passwordEditView.setTransformationMethod(null);
 }else{
 passwordEditView.setTransformationMethod(new PasswordTransformationMethod());
 }
 }
});
</code></pre>

blocks|key|598928|text|这可能会帮助你交配|type|unstyled|depth|inlineStyleRanges|entityRanges|data|598929|checkBox.setOnCheckedChangeListener(new+OnCheckedChangeListener()+{

++++public+void+onCheckedChanged(CompoundButton+buttonView,+boolean+isChecked)+{
++++++++//+checkbox+status+is+changed+from+uncheck+to+checked.
++++++++if+(!isChecked)+{
++++++++++++//+show+password
++++++++++++editText.setTransformationMethod(PasswordTransformationMethod.getInstance());
++++++++}+else+{
++++++++++++//+hide+password
++++++++++++editText.setTransformationMethod(HideReturnsTransformationMethod.getInstance());
++++++++}
++++}
});|code-block|syntax|javascript|598930|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This might help you mate

<pre><code>checkBox.setOnCheckedChangeListener(new OnCheckedChangeListener() {

 public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
 // checkbox status is changed from uncheck to checked.
 if (!isChecked) {
 // show password
 editText.setTransformationMethod(PasswordTransformationMethod.getInstance());
 } else {
 // hide password
 editText.setTransformationMethod(HideReturnsTransformationMethod.getInstance());
 }
 }
});
</code></pre>

blocks|key|1618984|text|在OnCheckedChangedListener中调用此方法|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1618985|+public+static+void+toggleShowPassword(boolean+show,+EditText+editText)+{
++++if+(show)
++++++++editText.setInputType(InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD);
++++else
++++++++editText.setInputType(InputType.TYPE_CLASS_TEXT+%7C+InputType.TYPE_TEXT_VARIATION_PASSWORD);
++++editText.setSelection(editText.length());
}|code-block|syntax|javascript|1618986|EditText游标在更改InputType后重置其位置，这就是我们添加最后一行editText.setSelection(editText.length())的原因|1618987|entityMap^0|1|O|0|0|0|8|D|9|14|14|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|N|$]]

Call this method inside your <code>OnCheckedChangedListener</code>

<pre><code> public static void toggleShowPassword(boolean show, EditText editText) {
 if (show)
 editText.setInputType(InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD);
 else
 editText.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);
 editText.setSelection(editText.length());
}
</code></pre>

The <code>EditText</code> cursor resets its position after changing the <code>InputType</code> that's why we add the last line <code>editText.setSelection(editText.length())</code>

blocks|key|4770977|text|添加了密码可见性切换功能，以支持库版本24.2.0，使您可以直接从密码字段切换密码，而不需要CheckBox。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4770978|您可以通过在TextInputEditText上设置口令来实现这一点。下面是如何做到这一点的：|offset|length|style|CODE|4770979|<android.support.design.widget.TextInputLayout
++++++++android:layout_width="match_parent"
++++++++android:layout_height="wrap_content">

++++++++<android.support.design.widget.TextInputEditText
++++++++++++android:layout_width="match_parent"
++++++++++++android:layout_height="wrap_content"
++++++++++++android:hint="@string/password"
++++++++++++android:inputType="textPassword"/>
</android.support.design.widget.TextInputLayout>|code-block|syntax|javascript|4770980|entityMap^0|0|6|H|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|P|8|@$D|Q|E|R|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|S|8|@]|9|@]|A|$K|L]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

The Password Visibility Toggle feature has been added to support library version 24.2.0 enabling you to toggle the password straight from the password field without the need for a CheckBox.

You can make that work basically by setting an inputType of password on the <code>TextInputEditText</code>. Here's how to do that:

<pre><code>&lt;android.support.design.widget.TextInputLayout
 android:layout_width="match_parent"
 android:layout_height="wrap_content"&gt;

 &lt;android.support.design.widget.TextInputEditText
 android:layout_width="match_parent"
 android:layout_height="wrap_content"
 android:hint="@string/password"
 android:inputType="textPassword"/&gt;
&lt;/android.support.design.widget.TextInputLayout&gt;
</code></pre>

blocks|key|1619029|text|使用app:passwordToggleEnabled+=+true；可从Android支持库版本24.2.0获得。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1619030|++<android.support.design.widget.TextInputLayout
++++android:id="@%2Bid/input_layout_password"
++++android:layout_width="match_parent"
++++android:layout_height="wrap_content"
++++android:visibility="gone"
++++app:passwordToggleEnabled="true"
++++tools:visibility="visible"
++++android:layout_marginBottom="@dimen/space_medium">

++++<android.support.design.widget.TextInputEditText
++++++++android:id="@%2Bid/input_password"
++++++++android:layout_width="match_parent"
++++++++android:layout_height="wrap_content"
++++++++android:inputType="textPassword"
++++++++android:imeOptions="actionDone"
++++++++android:imeActionLabel="@string/btn_sign_in"
++++++++android:hint="@string/hint_password"+/>

</android.support.design.widget.TextInputLayout>|code-block|syntax|javascript|1619031|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

use app:passwordToggleEnabled = true; available from Android support library version 24.2.0.

<pre><code> &lt;android.support.design.widget.TextInputLayout
 android:id="@+id/input_layout_password"
 android:layout_width="match_parent"
 android:layout_height="wrap_content"
 android:visibility="gone"
 app:passwordToggleEnabled="true"
 tools:visibility="visible"
 android:layout_marginBottom="@dimen/space_medium"&gt;

 &lt;android.support.design.widget.TextInputEditText
 android:id="@+id/input_password"
 android:layout_width="match_parent"
 android:layout_height="wrap_content"
 android:inputType="textPassword"
 android:imeOptions="actionDone"
 android:imeActionLabel="@string/btn_sign_in"
 android:hint="@string/hint_password" /&gt;

&lt;/android.support.design.widget.TextInputLayout&gt;
</code></pre>

blocks|key|599035|text|如果你使用的是Xamarin+(现在被称为Visual+Studio+Mac+)，你可以这样实现(我使用了一个开关)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|599036|+///+<summary>
+///+Toggles+the+password.
+///+</summary>
+///+<param+name="field">Field.</param>
+///+<param+name="isChecked">If+set+to+<c>true</c>+is+checked.</param>
+private+void+TogglePassword(TextView+field,+bool+isChecked)
+{
++++++///+masks+with+password+character
++++++if+(isChecked)
++++++{
+++++++++++field.TransformationMethod+=+new+PasswordTransformationMethod();
++++++}
++++++///+unmasks+password
++++++else
++++++{
+++++++++++field.TransformationMethod+=+null;
++++++}|code-block|syntax|javascript|599037|然后在您的交换机.click上执行以下操作|599038|switch.Click+%2B=+delegate+{
++++++++++++TogglePassword(textView,+switch.Checked);
++++++++};|599039|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

on the off chance that you are using Xamarin (Visual Studio Mac as it's now called) you can achieve it this way (I used a Switch)

<pre><code> /// &lt;summary&gt;
 /// Toggles the password.
 /// &lt;/summary&gt;
 /// &lt;param name="field"&gt;Field.&lt;/param&gt;
 /// &lt;param name="isChecked"&gt;If set to &lt;c&gt;true&lt;/c&gt; is checked.&lt;/param&gt;
 private void TogglePassword(TextView field, bool isChecked)
 {
 /// masks with password character
 if (isChecked)
 {
 field.TransformationMethod = new PasswordTransformationMethod();
 }
 /// unmasks password
 else
 {
 field.TransformationMethod = null;
 }
</code></pre>

Then on your Switch .click do something like this

<pre><code>switch.Click += delegate {
 TogglePassword(textView, switch.Checked);
 };
</code></pre>

blocks|key|4771054|text|这会起作用的-|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4771055|public+void+ShowPassword()+{
++++if+(cb.isChecked())+{
++++++++password.setInputType(InputType.TYPE_CLASS_TEXT);
++++}+else+{
++++++++password.setInputType(InputType.TYPE_CLASS_TEXT+%7C+InputType.TYPE_TEXT_VARIATION_PASSWORD);
++++}
}|code-block|syntax|javascript|4771056|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This will work - 

<pre><code>public void ShowPassword() {
 if (cb.isChecked()) {
 password.setInputType(InputType.TYPE_CLASS_TEXT);
 } else {
 password.setInputType(InputType.TYPE_CLASS_TEXT | InputType.TYPE_TEXT_VARIATION_PASSWORD);
 }
}
</code></pre>

I use an EditText to enter password.
And a CheckBox to show password or not.
Below function is the part:

<pre><code>public void ShowPassword() {
 if (cb.isChecked()) {
 password.setInputType(InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD);
 } else {
 password.setInputType(InputType.TYPE_TEXT_VARIATION_PASSWORD);
 }
}
</code></pre>

When it checked, it show password.
But when it not checked, it does show stars.
How to modify it to show star while the cb is not checked?

Show the password with EditText

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我使用EditText输入密码。以及显示密码或不显示密码的CheckBox。下面的函数是这个部分：public void ShowPassword() {    if (cb.isChecked()) {        password.setInputType(InputType.TYPE_TEXT_VARIATIO...

问使用EditText显示密码
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问使用EditText显示密码EN