blocks|key|4756383|text|也许您只是在寻找file.remove和list.files的组合？可能是这样的：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|4756384|do.call(file.remove,+list(list.files("C:/Temp",+full.names+=+TRUE)))|code-block|syntax|javascript|4756385|我猜您可以使用grep或grepl将文件列表过滤到名称与特定模式匹配的文件，不是吗？|4756386|entityMap^0|8|B|K|A|0|0|7|4|C|5|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|T|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|U|8|@$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|N|$]]

Maybe you're just looking for a combination of <code>file.remove</code> and <code>list.files</code>? Maybe something like:

<pre><code>do.call(file.remove, list(list.files("C:/Temp", full.names = TRUE)))
</code></pre>

And I guess you can filter the list of files down to those whose names match a certain pattern using <code>grep</code> or <code>grepl</code>, no?

blocks|key|1607513|text|对于已知路径中的所有文件，您可以：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1607514|unlink("path/*")|code-block|syntax|javascript|1607515|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

For all files in a known path you can:

<pre><code>unlink("path/*")
</code></pre>

blocks|key|4756418|text|dir_to_clean+<-+tempdir()+#or+wherever

#create+some+junk+to+test+it+with
file.create(file.path(
++dir_to_clean,+
++paste("test",+1:5,+"txt",+sep+=+".")
))

#Now+remove+them+(no+need+for+messing+about+with+do.call)
file.remove(dir(++
++dir_to_clean,+
++pattern+=+"%5Etest\\.[0-9]\\.txt$",+
++full.names+=+TRUE
))|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4756419|您还可以使用unlink作为file.remove的替代方案。|unstyled|offset|length|style|CODE|4756420|entityMap^0|0|6|6|E|B|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|N|8|@$G|O|H|P|I|J]|$G|Q|H|R|I|J]]|9|@]|A|$]]|$1|K|3|-4|5|F|7|S|8|@]|9|@]|A|$]]]|L|$]]

<pre><code>dir_to_clean &lt;- tempdir() #or wherever

#create some junk to test it with
file.create(file.path(
 dir_to_clean, 
 paste("test", 1:5, "txt", sep = ".")
))

#Now remove them (no need for messing about with do.call)
file.remove(dir( 
 dir_to_clean, 
 pattern = "^test\\.[0-9]\\.txt$", 
 full.names = TRUE
))
</code></pre>

You can also use <code>unlink</code> as an alternative to <code>file.remove</code>.

blocks|key|591443|text|使用dir和grep的组合，这并不是很糟糕。这可能会变成一个函数，它还会告诉你哪些文件将被删除，如果不是你所期望的，你就有机会中止。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|591444|#+Which+directory?
mydir+<-+"C:/Test"
#+What+phrase+do+you+want+contained+in
#+the+files+to+be+deleted?
deletephrase+<-+"deleteme"

#+Look+at+directory
dir(mydir)
#+Figure+out+which+files+should+be+deleted
id+<-+grep(deletephrase,+dir(mydir))
#+Get+the+full+path+of+the+files+to+be+deleted
todelete+<-+dir(mydir,+full.names+=+TRUE)[id]
#+BALEETED
unlink(todelete)|code-block|syntax|javascript|591445|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Using a combination of dir and grep this isn't too bad. This could probably be turned into a function that also tells you which files are to be deleted and gives you a chance to abort if it's not what you expected.

<pre><code># Which directory?
mydir &lt;- "C:/Test"
# What phrase do you want contained in
# the files to be deleted?
deletephrase &lt;- "deleteme"

# Look at directory
dir(mydir)
# Figure out which files should be deleted
id &lt;- grep(deletephrase, dir(mydir))
# Get the full path of the files to be deleted
todelete &lt;- dir(mydir, full.names = TRUE)[id]
# BALEETED
unlink(todelete)
</code></pre>

blocks|key|1611772|text|删除文件夹中的所有内容，但将文件夹保留为空|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1611773|unlink("path/*",+recursive+=+T,+force+=+T)|code-block|syntax|javascript|1611774|删除文件夹中的所有内容，同时删除文件夹|1611775|unlink("path",+recursive+=+T,+force+=+T)|1611776|使用force+=+T覆盖任何只读/隐藏/等问题。|offset|length|style|CODE|1611777|entityMap^0|0|0|0|0|2|9|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|W|8|@$M|X|N|Y|O|P]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

To delete everything inside the folder, but keep the folder empty
<pre><code>unlink(&quot;path/*&quot;, recursive = T, force = T)
</code></pre>
To delete everything inside the folder, and also delete the folder
<pre><code>unlink(&quot;path&quot;, recursive = T, force = T)
</code></pre>
Use <code>force = T</code>, to overwrite any read-only/hidden/etc. issues.

blocks|key|1611748|text|我很喜欢here::here在文件夹中找到我的方法(特别是当我在Rmarkdown笔记本的内联评估和编织版本之间切换时)……还有另一种解决方案：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1611749|++++#+Batch+remove+files
++++#+Match+files+in+chosen+directory+with+specified+regex
++++files+<-+dir(here::here("your_folder"),+"your_pattern")+

++++#+Remove+matched+files
++++unlink(paste0(here::here("your_folder"),+files))|code-block|syntax|javascript|1611750|entityMap^0|4|A|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

I quite like <code>here::here</code> for finding my way through folders (especially if I'm switching between inline evaluation and knit versions of an Rmarkdown notebook)... yet another solution: 

<pre><code> # Batch remove files
 # Match files in chosen directory with specified regex
 files &lt;- dir(here::here("your_folder"), "your_pattern") 

 # Remove matched files
 unlink(paste0(here::here("your_folder"), files))
</code></pre>

Is there any way to automatically delete all files or folders with few R command lines?
I am aware of the <code>unlink()</code> or <code>file.remove()</code> functions, but for those you need to define a character vector with exactly all the names of the files you want to delete. I am looking more for something that lists all the files or folders within a specific path (e.g. 'C:/Temp') and then delete all files with a certain name (regardless of its extension).

Any help is very much appreciated!

Automatically Delete Files/Folders

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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有没有办法用很少的R命令行自动删除所有的文件或文件夹？我知道unlink()或file.remove()函数，但对于这些函数，您需要定义一个字符向量，其中包含要删除的所有文件的名称。我正在寻找更多的东西，列出了特定路径下的所有文件或文件夹(例如'C:/Temp')，然后删除具有特定名称的所有文件(不管其扩展名)。任何帮助都是非常感谢的！

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