blocks|key|5320187|text|看看XPath和它的java实现JXPath。另一种可能的方法是使用JAXB解析XML，并使用LambdaJ操作对象列表。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|5320188|entityMap|0|LINK|mutability|MUTABLE|url|http://commons.apache.org/jxpath/^0|G|6|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

Take a look on XPath and its java implementation <a href="http://commons.apache.org/jxpath/" rel="nofollow">JXPath</a>. Other possible approach is parsing XML using JAXB and operating objects list using LambdaJ.

blocks|key|1893859|text|我建议您在javax.xml.xpath包中使用XPath：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1893860|final+InputStream+is+=+new+FileInputStream('your.xml');

final+DocumentBuilderFactory+factory+=+DocumentBuilderFactory.newInstance();
final+DocumentBuilder+builder+=+factory.newDocumentBuilder();
final+Document+doc+=+builder.parse(is);
final+XPathFactory+xPathfactory+=+XPathFactory.newInstance();
final+XPath+xpath+=+xPathfactory.newXPath();
final+XPathExpression+expr+=+xpath.compile("/city/stock/name[text()='Sony']");|code-block|syntax|javascript|1893861|然后：|1893862|final+NodeList+nl+=+(NodeList)+expr.evaluate(doc,+XPathConstants.NODESET);|1893863|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/6/docs/api/javax/xml/xpath/XPath.html|1|http://www.w3.org/TR/xpath/^0|5|F|0|O|5|1|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@$A|X|B|Y|1|Z]|$A|10|B|11|1|12]]|C|$]]|$1|D|3|E|5|F|7|13|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|14|8|@]|9|@]|C|$]]|$1|K|3|L|5|F|7|15|8|@]|9|@]|C|$G|H]]|$1|M|3|-4|5|6|7|16|8|@]|9|@]|C|$]]]|N|$O|$5|P|Q|R|C|$S|T]]|U|$5|P|Q|R|C|$S|V]]]]

I recommend you to use <a href="http://www.w3.org/TR/xpath/" rel="nofollow">XPath</a> with <a href="http://docs.oracle.com/javase/6/docs/api/javax/xml/xpath/XPath.html" rel="nofollow">javax.xml.xpath</a> package:

<pre><code>final InputStream is = new FileInputStream('your.xml');

final DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
final DocumentBuilder builder = factory.newDocumentBuilder();
final Document doc = builder.parse(is);
final XPathFactory xPathfactory = XPathFactory.newInstance();
final XPath xpath = xPathfactory.newXPath();
final XPathExpression expr = xpath.compile("/city/stock/name[text()='Sony']");
</code></pre>

and then:

<pre><code>final NodeList nl = (NodeList) expr.evaluate(doc, XPathConstants.NODESET);
</code></pre>

blocks|key|5320234|text|还有一个带有强大的XPath导航功能的dom4j库：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|5320235|import+org.dom4j.Document;
import+org.dom4j.io.SAXReader;

SAXReader+reader+=+new+SAXReader();
Document+document+=+reader.read("test.xml");
List+list+=+document.selectNodes("/city/stock/name[text()='Sony']");
for+(Iterator+iter+=+list.iterator();+iter.hasNext();+)+{
++++//+TODO:+place+you+logic+here
}|code-block|syntax|javascript|5320236|更多的例子是here|5320237|entityMap|0|LINK|mutability|MUTABLE|url|http://dom4j.sourceforge.net/|1|http://dom4j.sourceforge.net/dom4j-1.6.1/guide.html^0|J|5|0|0|0|6|4|1|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@$A|V|B|W|1|X]]|C|$]]|$1|D|3|E|5|F|7|Y|8|@]|9|@]|C|$G|H]]|$1|I|3|J|5|6|7|Z|8|@]|9|@$A|10|B|11|1|12]]|C|$]]|$1|K|3|-4|5|6|7|13|8|@]|9|@]|C|$]]]|L|$M|$5|N|O|P|C|$Q|R]]|S|$5|N|O|P|C|$Q|T]]]]

There is also <a href="http://dom4j.sourceforge.net/" rel="nofollow">dom4j</a> library which has powerful navigation with XPath:

<pre><code>import org.dom4j.Document;
import org.dom4j.io.SAXReader;

SAXReader reader = new SAXReader();
Document document = reader.read("test.xml");
List list = document.selectNodes("/city/stock/name[text()='Sony']");
for (Iterator iter = list.iterator(); iter.hasNext(); ) {
 // TODO: place you logic here
}
</code></pre>

More examples are <a href="http://dom4j.sourceforge.net/dom4j-1.6.1/guide.html" rel="nofollow">here</a>

blocks|key|871781|text|使用一行代码尝试jcabi-xml+(请参阅此blog+post)：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|871782|Collection<XML>+found+=+new+XMLDocument("your+document+here").nodes(
++"/city/stock/name[text()='Sony']"
);|code-block|syntax|javascript|871783|entityMap|0|LINK|mutability|MUTABLE|url|http://xml.jcabi.com/|1|http://www.yegor256.com/2014/04/24/java-xml-parsing-and-traversing.html^0|8|9|0|N|9|1|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]|$A|W|B|X|1|Y]]|C|$]]|$1|D|3|E|5|F|7|Z|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|10|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]|Q|$5|L|M|N|C|$O|R]]]]

Try <a href="http://xml.jcabi.com" rel="nofollow">jcabi-xml</a> (see this <a href="http://www.yegor256.com/2014/04/24/java-xml-parsing-and-traversing.html" rel="nofollow">blog post</a>) with a one-liner:

<pre><code>Collection&lt;XML&gt; found = new XMLDocument("your document here").nodes(
 "/city/stock/name[text()='Sony']"
);
</code></pre>

I have such XML structure, when I use NodeList nList = doc.getElementsByTagName("stock"); it return me 3 stocks, 2 main stock tags and one which is under substocks. I want to get only two stock which is on upper level and ignore all which is under substock tags.

Is it possible in Java to make something like LINQ query in C#, say return me elements only where name is equals to "Sony". 

Thanks!

<pre><code>&lt;city&gt;
 &lt;stock&gt;
 &lt;name&gt;Sony&lt;/name&gt;
 &lt;/stock&gt;
 &lt;stock&gt;
 &lt;name&gt;Panasonic&lt;/name&gt;
 &lt;substocks&gt;
 &lt;stock&gt;
 &lt;name&gt;Panasonic Shop 2&lt;/name&gt;
 &lt;/stock&gt;
 &lt;/substocks&gt;
 &lt;/stock&gt;
&lt;/city&gt;
</code></pre>

Java XML Parse/Query

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有这样的XML结构，当我使用NodeList nList =doc.getElementsByTagName(“stock”)时，它返回3个股票，2个主股票标签和一个子股票标签。我只想得到两只股票，这是在较高的水平，并忽略所有的子股票标签。有没有可能在Java中用C#做一些像LINQ query这样的东西，比如只返回...

问Java XML解析/查询
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