如何在更新到CppUnit 1.12时替换来自CppUnit 1.9的过时的getRegistryList()？
如何在更新到CppUnit 1.12时替换来自CppUnit 1.9的过时的getRegistryList()？
提问于 2012-03-13 05:54:08
我移植的代码有很多基于CppUnit 1.9.11左右的测试套件。我的测试运行器可以使用以下命令打印所有命名的测试套件(弃用？)成语：
cout << "\n Usage: UnitTest testSuiteName ...\n\n";
cout << " Tests available: \n";
CppUnit::TestFactoryRegistry registry("All Tests");
CppUnit::Test* test = registry.getRegistry().makeTest();
CppUnit::Registries registryList = registry.getRegistryList();
CppUnit::Registries::iterator it;
for (it = registryList.begin(); it != registryList.end(); ++it)
{
cout << " - " << it->first << endl;
}显然，CppUnit 1.12中不存在getRegistryList()。有没有一个等价的习惯用法来获得所有注册的、命名的测试套件？
回答 1
Stack Overflow用户
回答已采纳
发布于 2012-03-17 02:18:22
回答我自己的问题：
cout << "\n Usage: UnitTest TestNames\n\n";
cout << " Tests available: \n";
CppUnit::TestFactoryRegistry ®istry =
CppUnit::TestFactoryRegistry::getRegistry(); // "All Tests"
CppUnit::Test *test = registry.makeTest();
CppUnit::TestSuite *s = dynamic_cast<CppUnit::TestSuite*>(test);
if (!s) {
cerr << "can't get TestSuite" << endl;
} else {
typedef CppUnitVector<CppUnit::Test *> container_type;
const container_type &tests( s->getTests() );
container_type::const_iterator ii;
for (ii=tests.begin(); ii != tests.end(); ++ii) {
const CppUnit::Test *t = (*ii);
cout << " - " << t->getName() << endl;
}
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/9675358
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