当BOOST_FUSION_ADAPT_STRUCT的参数数为2时，Boost融合编译失败
当BOOST_FUSION_ADAPT_STRUCT的参数数为2时，Boost融合编译失败
提问于 2012-04-02 05:53:49
为什么无法使用g++ -c filename.cpp进行编译：
#include <boost/config/warning_disable.hpp>
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/phoenix_core.hpp>
#include <boost/spirit/include/phoenix_operator.hpp>
#include <boost/spirit/include/phoenix_object.hpp>
#include <boost/fusion/include/adapt_struct.hpp>
#include <boost/fusion/include/io.hpp>
#include <boost/lambda/lambda.hpp>
#include <boost/spirit/include/phoenix_stl.hpp>
#include <boost/variant/variant.hpp>
#include <iostream>
namespace qi = boost::spirit::qi;
namespace ascii = boost::spirit::ascii;
namespace phoenix = boost::phoenix;
namespace lambda = boost::lambda;
using namespace std;
struct Intensity
{
int intensity_;
};
BOOST_FUSION_ADAPT_STRUCT(
Intensity,
(int, intensity_)
)
template <typename Iterator>
struct InternalParser : qi::grammar<Iterator, Intensity(), ascii::space_type>
{
InternalParser() : InternalParser::base_type(intensity)
{
intensity %= qi::int_;
}
qi::rule<Iterator, Intensity(), ascii::space_type> intensity;
};
typedef InternalParser<string::const_iterator> TheParser;
TheParser parser;但是如果我在结构强度中添加一个新的字段，它就会起作用：
#include <boost/config/warning_disable.hpp>
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/phoenix_core.hpp>
#include <boost/spirit/include/phoenix_operator.hpp>
#include <boost/spirit/include/phoenix_object.hpp>
#include <boost/fusion/include/adapt_struct.hpp>
#include <boost/fusion/include/io.hpp>
#include <boost/lambda/lambda.hpp>
#include <boost/spirit/include/phoenix_stl.hpp>
#include <boost/variant/variant.hpp>
#include <iostream>
namespace qi = boost::spirit::qi;
namespace ascii = boost::spirit::ascii;
namespace phoenix = boost::phoenix;
namespace lambda = boost::lambda;
using namespace std;
struct Intensity
{
int dummy_;
int intensity_;
};
BOOST_FUSION_ADAPT_STRUCT(
Intensity,
(int, dummy_)
(int, intensity_)
)
template <typename Iterator>
struct InternalParser : qi::grammar<Iterator, Intensity(), ascii::space_type>
{
InternalParser() : InternalParser::base_type(intensity)
{
intensity %= qi::int_ >> qi::int_;
}
qi::rule<Iterator, Intensity(), ascii::space_type> intensity;
};
typedef InternalParser<string::const_iterator> TheParser;
TheParser parser;G++版本: gcc版本4.4.6 20110731 (红帽4.4.6-3) (GCC)
Boost版本: 1.41.0
回答 1
Stack Overflow用户
回答已采纳
发布于 2012-04-02 15:51:56
这是boost 1.41.0中的一个bug。我用1.49.0编译了第一个例子，它工作了。
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原文链接：
https://stackoverflow.com/questions/9968658
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