blocks|key|2181144|text|通过为ajax调用设置async:+false，可以使ajax调用同步。您已经拥有了用于捕获所有异常的error函数。所以我相信这应该足够了|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2181145|+++++++++++$.ajax({
++++++++++++type:+"GET",
++++++++++++url:+"/abc/GetNodesById",
++++++++++++contentType:+"application/json;+charset=utf-8",
++++++++++++dataType:+"json",
++++++++++++data:+{+"nodeId":+''+},
++++++++++++async:+false,
++++++++++++cache:+false,
++++++++++++success:+function+(data)+{
++++++++++++++//Do+Work
++++++++++++}
++++++++++++error+:+function(jqXHR,+textStatus,+errorThrown){
++++++++++++++++//+Handle+Error
++++++++++++++++//+Return+False+
++++++++++++}
++++++});|code-block|syntax|javascript|2181146|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

you can make the ajax call synchronous one by setting async: false for the ajax call. You are already having the error function to catch all exceptions. So I believe that should do

<pre><code> $.ajax({
 type: "GET",
 url: "/abc/GetNodesById",
 contentType: "application/json; charset=utf-8",
 dataType: "json",
 data: { "nodeId": '' },
 async: false,
 cache: false,
 success: function (data) {
 //Do Work
 }
 error : function(jqXHR, textStatus, errorThrown){
 // Handle Error
 // Return False 
 }
 });
</code></pre>

blocks|key|2175956|text|是的，jQuery.ajax是异步的，所以你需要使用类似这样的东西：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2175957|function+findUserInfos(datas){
++var+userID=datas.shift();+//remove+and+return+the+first+element

++var+req+=+$.ajax({
++++url:+"http://twitter.com/users/show.json?suppress_response_codes&id=xx!5@x!!x",
++++dataType+:+"jsonp"
++});

++req.success(function(msg)+{
++++console.log('Yes!+Success!');
++++findUserInfos(datas)
++});

++req.error(function(msg)+{
++++console.log('Error');
++});
}+++

findUserInfos(d);|code-block|syntax|javascript|2175958|一旦出现错误，它就会崩溃，因为我们只有在成功中才能继续。|2175959|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Yes, jQuery.ajax is asynchronous, so you need to use something like:

<pre><code>function findUserInfos(datas){
 var userID=datas.shift(); //remove and return the first element

 var req = $.ajax({
 url: "http://twitter.com/users/show.json?suppress_response_codes&amp;id=xx!5@x!!x",
 dataType : "jsonp"
 });

 req.success(function(msg) {
 console.log('Yes! Success!');
 findUserInfos(datas)
 });

 req.error(function(msg) {
 console.log('Error');
 });
} 

findUserInfos(d);
</code></pre>

It will broke, as soon as there is an error, since we continue only in the success.

blocks|key|214092|text|要中断循环，请返回false|type|unstyled|depth|inlineStyleRanges|entityRanges|data|214093|如果在错误处理程序中抛出错误：|214094|throw+'Error:+'+%2B+userID;|code-block|syntax|javascript|214095|然后，您可以编写|214096|jQuery.each(d,+function()+{
++++try+{
++++++++findUserInfo(this);
++++}+catch(err)+{
++++++return+false;
++++}
+});|214097|编辑:正如其他人所说，最好从成功处理程序返回true，从错误处理程序返回false，然后在循环内调用return+findUserInfo(this)；。当然，如果同步进行ajax调用，则可能会冻结浏览器。|214098|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|R|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|S|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|U|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

To break from the loop, return false

If you throw an error inside your error handler:

<pre><code>throw 'Error: ' + userID;
</code></pre>

You can then write

<pre><code>jQuery.each(d, function() {
 try {
 findUserInfo(this);
 } catch(err) {
 return false;
 }
 });
</code></pre>

Edit: As commented by others, It would be better to return true from your success handler and false from your error one, and then calling return findUserInfo(this); inside the loop.
Of course, if you make your ajax calls synchronously you risk freezing the browser.

blocks|key|214140|text|如何将所有ID存储为数组，将它们传输到服务器，然后检查给定的结果！？这节省了大量的请求。您可以将ID收集为数组，并通过POST+["id1","id2",...].join(",")传输它们|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|214141|或者你提前获取所有东西，然后在获取之后开始循环...|214142|正如你已经说过的，由于异步的性质，不可能打破循环...async:+false；也可以提供帮助，但它会阻止UI更新(这将使浏览器因许多请求而保持忙碌)|214143|entityMap^0|1S|R|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|O|8|@]|D|@]|E|$]]|$1|H|3|I|5|6|7|P|8|@]|D|@]|E|$]]|$1|J|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|K|$]]

How about storing all the IDs as an array, transporting them to the server and then checking a given result!? That saves a lot of requests. You could collect the IDs as an array and transport them via POST <code>["id1","id2",...].join(",")</code>

Or you fetch everything in advance and start your loop after fetching...

breaking out the loop is not possible due to the asynchronous nature as you already stated... async: false; could help as well, but it prevents the UI from updating (which will keep the browser busy due to many requests)

blocks|key|214165|text|设置async:false是一个糟糕的想法。它会导致浏览器在进行ajax调用时挂起。Frame.js的设计目的是解决这样的问题：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|214166|jQuery.each(d,+function()+{
++++findUserInfo(this);
});

Frame.useTimeout+=+false;+//+turn+off+Frame's+error+recovery

function+findUserInfo(userID){

++++Frame(function(next){

++++++++var+req+=+$.ajax({
++++++++url:+"http://twitter.com/users/show.json?suppress_response_codes&id=xx!5@x!!x",
++++++++dataType+:+"jsonp"

++++++++});

++++++++req.success(function(msg)+{
++++++++++++console.log('Yes!+Success!');
++++++++++++next();
++++++++});

++++++++req.error(function(msg)+{
++++++++++++console.log('Error');
++++++++++++//+don't+call+next+and+Frame+will+stop
++++++++});

++++});

}++
Frame.init();|code-block|syntax|javascript|214167|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/bishopZ/Frame.js^0|16|8|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

Setting async:false is a terrible idea. It causes the browser to hang while the ajax call is made. <a href="https://github.com/bishopZ/Frame.js" rel="nofollow">Frame.js</a> was designed to solve problems like this:

<pre><code>jQuery.each(d, function() {
 findUserInfo(this);
});

Frame.useTimeout = false; // turn off Frame's error recovery

function findUserInfo(userID){

 Frame(function(next){

 var req = $.ajax({
 url: "http://twitter.com/users/show.json?suppress_response_codes&amp;id=xx!5@x!!x",
 dataType : "jsonp"

 });

 req.success(function(msg) {
 console.log('Yes! Success!');
 next();
 });

 req.error(function(msg) {
 console.log('Error');
 // don't call next and Frame will stop
 });

 });

} 
Frame.init();
</code></pre>

Have a look at the code below. The question is simple , how do I break from this for loop if the method findUserInfo ajax code returns an error. In short how can I break from this for loop whenever I wish to ? Is is because ajax call is asynchronous ?

<pre><code> jQuery.each(d, function() {
 findUserInfo(this);
 });

function findUserInfo(userID){


var req = $.ajax({
url: "http://twitter.com/users/show.json?suppress_response_codes&amp;id=xx!5@x!!x",
dataType : "jsonp"

});

req.success(function(msg) {
 console.log('Yes! Success!');

});

req.error(function(msg) {
 console.log('Error');
});


} 
</code></pre>

Break from jquery for loop when doing an ajax call return error

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

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看一下下面的代码。问题很简单，如果方法findUserInfo ajax代码返回错误，我该如何中断此for循环。简而言之，我怎么才能在我想要的时候从这个for循环中解脱出来呢？是因为ajax调用是异步的吗？ jQuery.each(d, function() {    findUserInfo(this); });fu...

问在执行ajax调用返回错误时中断jquery for循环
EN

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问在执行ajax调用返回错误时中断jquery for循环EN