blocks|key|1551532|text|看起来像是家庭作业。因此，read+up+on+\b。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1551533|应该会让你走上正确的方向。|1551534|entityMap|0|LINK|mutability|MUTABLE|url|http://www.regular-expressions.info/wordboundaries.html^0|O|2|D|D|0|0|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@$9|S|A|T|1|U]]|E|$]]|$1|F|3|G|5|6|7|V|8|@]|D|@]|E|$]]|$1|H|3|-4|5|6|7|W|8|@]|D|@]|E|$]]]|I|$J|$5|K|L|M|E|$N|O]]]]

Looks like homework. As such, <a href="http://www.regular-expressions.info/wordboundaries.html" rel="nofollow">read up on <code>\b</code></a>.

Should set you in the right direction.

blocks|key|1550517|text|在zero-width+assertions上阅读。使用它们，您可以定义\s和\S之间的拆分位置，而无需实际匹配任何相邻字符。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1550518|编辑:这里是OP询问这些构造的another+question。|1550519|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/az24scfc.aspx#grouping_constructs|1|https://stackoverflow.com/questions/10869547/regular-expression-a-z^0|10|2|13|2|1|L|0|0|F|G|1|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]|$9|U|A|V|B|C]]|D|@$9|W|A|X|1|Y]]|E|$]]|$1|F|3|G|5|6|7|Z|8|@]|D|@$9|10|A|11|1|12]]|E|$]]|$1|H|3|-4|5|6|7|13|8|@]|D|@]|E|$]]]|I|$J|$5|K|L|M|E|$N|O]]|P|$5|K|L|M|E|$N|Q]]]]

Read up on the <a href="http://msdn.microsoft.com/en-us/library/az24scfc.aspx#grouping_constructs" rel="nofollow noreferrer">zero-width assertions</a>. With them you can define a split position between e.g. <code>\s</code> and <code>\S</code> without actually matching either adjacent character.

edit:
Here's <a href="https://stackoverflow.com/questions/10869547/regular-expression-a-z">another question</a> where the OP asked about those constructs.

blocks|key|2718655|text|使用如下所示的正则表达式拆分：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2718656|(?<=[\S\n])(?=\s)|code-block|syntax|javascript|2718657|类似于：|2718658|var+substrings+=+Regex.Split(input,+@"(?<=[\S\n])(?=\s)");|2718659|这根本不会删除任何空格，但这不是必需的，所以应该没问题。|2718660|如果你真的想删除\n之间的空格，你可以像这样拆分：|offset|length|style|CODE|2718661|(?<=[\S\n])(?=\s)(?:[+\t]%2B(?=\n))?|2718662|entityMap^0|0|0|0|0|0|8|2|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|Z|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|10|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|11|8|@$O|12|P|13|Q|R]]|9|@]|A|$]]|$1|S|3|T|5|D|7|14|8|@]|9|@]|A|$E|F]]|$1|U|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|V|$]]

Split with a regex like this:

<pre><code>(?&lt;=[\S\n])(?=\s)
</code></pre>

Something like:

<pre><code>var substrings = Regex.Split(input, @"(?&lt;=[\S\n])(?=\s)");
</code></pre>

This will not remove any spaces at all, but that was not required so should be fine.

If you really want the spaces between <code>\n</code>s to be removed, you could split with something like:

<pre><code>(?&lt;=[\S\n])(?=\s)(?:[ \t]+(?=\n))?
</code></pre>

I want to split the string and create a collection, with the following rules:
The string should be splitted into words.

1) If the string contains '\n' it should be considered as a seperate '\n' word. 
2) If the string contains more than one '\n' it should considered it as more than on '\n' words. 
3) No space should be removed from the string. Only exception is, if space comes between two \n it can be ignored.

PS: I tried a lot with string split, first split-ted \n characters and created a collection, downside is, if I have two \n consecutively, I'm unable to create two dummy words into the collection. Any help would be greatly appreciated.

<img src="https://i.stack.imgur.com/KCMd0.png" alt="enter image description here">

Is there anyway to do this using regex?

How to split string preserving spaces and any number of \n characters

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想拆分字符串并创建一个集合，规则如下:字符串应该拆分成单词。1)如果字符串包含'\n‘，则应将其视为单独的'\n’字。2)如果字符串包含多个'\n‘，则应将其视为多于'\n’个单词。3)不能从字符串中删除空格。唯一的例外是，如果空格在两个之间，\n它可以被忽略。PS:我尝试了很多字符串拆分，首先拆分\n字符并创建了一...

问如何在保留空格和任意数量的\n字符的情况下拆分字符串
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