blocks|key|1000183|text|$('span').attr('st_url',+function(i,+url)+{
++++var+str+=+url.substr(url.lastIndexOf('/')+%2B+1)+%2B+'$';
++++return+url.replace(+new+RegExp(str),+''+);
});|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1000184|unstyled|1000185|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|H|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|I|8|@]|9|@]|A|$]]|$1|F|3|-4|5|E|7|J|8|@]|9|@]|A|$]]]|G|$]]

<pre><code>$('span').attr('st_url', function(i, url) {
 var str = url.substr(url.lastIndexOf('/') + 1) + '$';
 return url.replace( new RegExp(str), '' );
});
</code></pre>

<a href="http://jsfiddle.net/LNW4V/229/" rel="noreferrer">DEMO</a>

blocks|key|2722369|text|首先，您需要解析标记。接下来，尝试提取st_url的值，这是您的url。然后使用从提取的url的最后一个字符开始的循环，并省略它们，直到您看到'/‘。这就是你应该如何提取你想要的东西。请记住这一点，并尝试编写代码。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2722370|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

First you need to parse the tag. Next try to extract st_url value which is your url. Then use a loop from the last character of the extracted url and omit them until you see a '/'. This is how you should extract what you want. Keep this in mind and try to write the code .

blocks|key|2722375|text|你可以在这里看到它的工作原理：http://jsfiddle.net/xKxLR/|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2722376|var+url+=+"http://localhost:8888/careers/php-web-developer-2";
var+regex+=+new+RegExp('/[%5E/]*$');
console.log(url.replace(regex,+'/'));|code-block|syntax|javascript|2722377|entityMap|0|LINK|mutability|MUTABLE|url|http://jsfiddle.net/xKxLR/^0|F|Q|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

You can see it work here: <a href="http://jsfiddle.net/xKxLR/" rel="nofollow">http://jsfiddle.net/xKxLR/</a>

<pre><code>var url = "http://localhost:8888/careers/php-web-developer-2";
var regex = new RegExp('/[^/]*$');
console.log(url.replace(regex, '/'));
</code></pre>

blocks|key|2638512|text|你可以使用正则表达式来解析“url的最后一段”：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2638513|var+url="http://localhost:8888/careers/php-web-developer";

var+baseurl=url.replace(
++++new+RegExp("(.*/)[%5E/]%2B$"),
++++"$1")+);|code-block|syntax|javascript|2638514|RegExp基本上是说：“匹配任何内容，然后是一个斜杠，然后是所有非斜杠，直到字符串的末尾”。|2638515|replace函数接受匹配的部分，并将其替换为字符串的“任何内容，然后是斜杠”部分。|2638516|RegexBuddy有大量关于这一切的信息。|offset|length|2638517|entityMap|0|LINK|mutability|MUTABLE|url|http://www.regular-expressions.info/javascript.html^0|0|0|0|0|0|A|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Y|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|Z|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|10|8|@]|9|@$M|11|N|12|1|13]]|A|$]]|$1|O|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|P|$Q|$5|R|S|T|A|$U|V]]]]

You could use a regular expression to parse the 'last piece of the url':

<pre><code>var url="http://localhost:8888/careers/php-web-developer";

var baseurl=url.replace(
 new RegExp("(.*/)[^/]+$"),
 "$1") );
</code></pre>

The RegExp thing basically says: "match anything, then a slash and then all non-slashes till the end of the string".

The replace function takes that matching part, and replaces it with the "anything, then a slash" part of the string.

<a href="http://www.regular-expressions.info/javascript.html" rel="nofollow">RegexBuddy</a> has a great deal of information on all this.

blocks|key|1000278|text|使用这个。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1000279|$('span').attr('st_url',+function(i,+url)+{
++++var+to+=+url.lastIndexOf('/')+%2B1;

++++x+=++url.substring(0,to);
++++alert(x);
})​|code-block|syntax|javascript|1000280|你可以看到Demo|offset|length|1000281|entityMap|0|LINK|mutability|MUTABLE|url|http://jsfiddle.net/crwM4/1/^0|0|0|5|4|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

Use this. 

<pre><code>$('span').attr('st_url', function(i, url) {
 var to = url.lastIndexOf('/') +1;

 x = url.substring(0,to);
 alert(x);
})​
</code></pre>

You can see <a href="http://jsfiddle.net/crwM4/1/" rel="noreferrer">Demo</a>

blocks|key|1552355|text|像这样简单的：|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|1552356|var+to+=+url.lastIndexOf('/');
to+=+to+==+-1+?+url.length+:+to+%2B+1;
url+=+url.substring(0,+to);|code-block|syntax|javascript|1552357|entityMap^0|6|1|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

as simple as this:

<pre><code>var to = url.lastIndexOf('/');
to = to == -1 ? url.length : to + 1;
url = url.substring(0, to);
</code></pre>

blocks|key|2638568|text|下面是一种稍微简单一点的方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2638569|url+=+url.slice(0,+url.lastIndexOf('/'));|code-block|syntax|javascript|2638570|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Here is a slightly simpler way:

<pre><code>url = url.slice(0, url.lastIndexOf('/'));
</code></pre>

I need to remove the last part of the url from a span..

I have

<pre><code>&lt;span st_url="http://localhost:8888/careers/php-web-developer-2"
st_title="PHP Web Developer 2" class="st_facebook_large" displaytext="facebook"
st_processed="yes"&gt;&lt;/span&gt;&lt;/span&gt;
</code></pre>

And I need to take the <code>st_url</code> and remove the <code>php-web-developer-2</code> from it so it is just <code>http://localhost:8888/careers/</code>.

But I am not sure how to do that. <code>php-web-developer-2</code> will not always be that but it won't have any <code>/</code> in it. It will always be a <code>-</code> separated string.

Any Help!!??

Remove last element from url

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我需要从span中删除url的最后一部分..我有过<span st_url="http://localhost:8888/careers/php-web-developer-2"st_title="PHP Web Developer 2" class="st_facebook_large" displaytext="f...

问从url中删除最后一个元素
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