blocks|key|3049919|text|您需要跟踪所有线程，并在每个线程上使用Thread.Join。它会一直等到指定的线程终止，然后继续执行。如下所示：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3049920|var+threads+=+new+List<Thread>();
for+(int+i+=+0;+i+<+15;+i%2B%2B)
{
++++Thread+nova+=+new+Thread(Method);
++++nova.Start();
++++threads.Add(nova);
}
foreach+(var+thread+in+threads)
++++thread.Join();
listBox1.Items.Add("Some+text");|code-block|syntax|javascript|3049921|entityMap^0|J|B|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

You need to keep track of all the threads, and use <code>Thread.Join</code> on each one. This waits until the specified thread terminates, and then continues executing. Like this:

<pre><code>var threads = new List&lt;Thread&gt;();
for (int i = 0; i &lt; 15; i++)
{
 Thread nova = new Thread(Method);
 nova.Start();
 threads.Add(nova);
}
foreach (var thread in threads)
 thread.Join();
listBox1.Items.Add("Some text");
</code></pre>

blocks|key|2961831|text|您可以使用thread.join等待线程结束。有关如何使用它的页面，请参阅http://www.dotnetperls.com/thread-join。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2961832|entityMap|0|LINK|mutability|MUTABLE|url|http://www.dotnetperls.com/thread-join^0|11|12|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

You can use thread.join to wait for threads to end. See <a href="http://www.dotnetperls.com/thread-join" rel="nofollow">http://www.dotnetperls.com/thread-join</a> for an page on how to use it.

blocks|key|3049975|text|你可以有两个线程，第二个线程等待第一个线程发出触发信号。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3049976|private+void+Foo()
{
++var+signals+=+new+List<ManualResetEvent>();

++for+(int+i+=+0;+i+<+15;+i%2B%2B)
++{
++++var+signal+=+new+ManualResetEvent(false);
++++signals.Add(signal);
++++var+thread+=+new+Thread(()+=>+{+Method();+signal.Set();+});
++++thread.Start();
++}

++var+completionTask+=+new+Thread(()+=>
++{
++++WaitHandle.WaitAll(signals.ToArray());
++++CompletionWork();
++});
++completionTask.Start();

}

private+void+Method()
{
}

private+void+CompletionWork()
{
}|code-block|syntax|javascript|3049977|现在.Net+4.0+(及更高版本)中更好的解决方案是使用任务，并使用ContinueWith调用方法|offset|length|style|CODE|3049978|private+void+Foo()
{
++var+childThreads+=+new+List<Task>();
++for+(int+i+=+0;+i+<+15;+i%2B%2B)
++{
++++var+task+=+new+Task(Method);
++++task.Start();
++++childThreads.Add(task);
++}

++var+completionTask+=+new+Task(()+=>+
++{+
++++Task.WaitAll(childThreads.ToArray());
++}).ContinueWith(t+=>+CompletionWork());

}

private+void+Method()
{
}

private+void+CompletionWork()
{
}|3049979|join应答也可以，但需要包含线程阻塞。如果你不想让GUI阻塞，在第一个线程周围产生一个额外的线程。|3049980|entityMap^0|0|0|Z|C|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@$I|V|J|W|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|X|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|Y|8|@]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

You could have two threads, the 2nd one waiting on a signal to fire from the first.

<pre><code>private void Foo()
{
 var signals = new List&lt;ManualResetEvent&gt;();

 for (int i = 0; i &lt; 15; i++)
 {
 var signal = new ManualResetEvent(false);
 signals.Add(signal);
 var thread = new Thread(() =&gt; { Method(); signal.Set(); });
 thread.Start();
 }

 var completionTask = new Thread(() =&gt;
 {
 WaitHandle.WaitAll(signals.ToArray());
 CompletionWork();
 });
 completionTask.Start();

}

private void Method()
{
}

private void CompletionWork()
{
}
</code></pre>

The better solution now with .Net 4.0 (and later) is to use Tasks, and invoke a method using <code>ContinueWith</code>

<pre><code>private void Foo()
{
 var childThreads = new List&lt;Task&gt;();
 for (int i = 0; i &lt; 15; i++)
 {
 var task = new Task(Method);
 task.Start();
 childThreads.Add(task);
 }

 var completionTask = new Task(() =&gt; 
 { 
 Task.WaitAll(childThreads.ToArray());
 }).ContinueWith(t =&gt; CompletionWork());

}

private void Method()
{
}

private void CompletionWork()
{
}
</code></pre>

The join answers also work, but require the containing thread to block. If you don't want the GUI to block, Spawn an additional thread around the 1st.

blocks|key|1715563|text|我建议使用TPL来完成这项工作。你不需要产生这么多的线程。默认情况下，TPL将使用线程池：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1715564|using+System;
using+System.Threading.Tasks;

namespace+ConsoleApplication1
{
++++class+Program
++++{
++++++++private+const+int+TaskCount+=+15;

++++++++static+void+Main(string[]+args)
++++++++{
++++++++++++var+tasks+=+new+Task[TaskCount];
++++++++++++for+(var+index+=+0;+index+<+TaskCount;+index%2B%2B)
++++++++++++{
++++++++++++++++tasks[index]+=+Task.Factory.StartNew(Method);
++++++++++++}
++++++++++++Task.WaitAll(tasks);

++++++++++++Console.WriteLine("Some+text");
++++++++}

++++++++private+static+void+Method()
++++++++{
++++++++++++for+(int+i+=+0;+i+<+15;+i%2B%2B)
++++++++++++{
++++++++++++++++Console.WriteLine(i);
++++++++++++}
++++++++}
++++}
}|code-block|syntax|javascript|1715565|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I suggest to use TPL to get this done. You won't need to spawn so many threads. By default TPL will use thread pool for that:

<pre><code>using System;
using System.Threading.Tasks;

namespace ConsoleApplication1
{
 class Program
 {
 private const int TaskCount = 15;

 static void Main(string[] args)
 {
 var tasks = new Task[TaskCount];
 for (var index = 0; index &lt; TaskCount; index++)
 {
 tasks[index] = Task.Factory.StartNew(Method);
 }
 Task.WaitAll(tasks);

 Console.WriteLine("Some text");
 }

 private static void Method()
 {
 for (int i = 0; i &lt; 15; i++)
 {
 Console.WriteLine(i);
 }
 }
 }
}
</code></pre>

<pre><code> private void button1_Click(object sender, EventArgs e)
 {
 for (int i = 0; i &lt; 15; i++)
 {
 Thread nova = new Thread(Method);
 nova.Start();
 }
 listBox1.Items.Add("Some text");
 }

 private void Method()
 {
 for (int i = 0; i &lt; 15; i++)
 {
 Console.WriteLine(i);
 }

 }
</code></pre>

This code does write: Some text and then numbers 111222333.....
I would like that it writes 111122223333.... and then on the end Some text. 
is it possible to do that with threads (parent thread wait for child threads)? or do i have to use something else?

Wait for threads to complete

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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private void button1_Click(object sender, EventArgs e) { for (int i = 0; i < 15; i++) { Thread nova = new Thread(Method); ...

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