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社区首页 >问答首页 >如何在mysql中匹配

如何在mysql中匹配
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Stack Overflow用户
提问于 2012-07-17 03:03:39
回答 5查看 370关注 0票数 3

我有两个表,一个是候选人和他们的技能,另一个是工作和工作所需的技能,如下所示:

CSID =应聘者技能ID (主键)

CID =候选人ID (FK)

S_CODE =技能代码(FK)

这是candidate_skill表

代码语言:javascript
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+------------+---------+---------+
| CSID       | CID     |  S_CODE |
+------------+---------+---------+
| 1          | 1       | 5       |
| 2          | 1       | 9       |
| 3          | 2       | 5       |
| 4          | 2       | 10      |
+------------+---------+---------+

SJID =技能作业ID (主键)

JID =作业ID (FK)

S_CODE =技能代码(FK)

下面是skill_job表:

代码语言:javascript
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+------------+---------+---------+
| SJID       | JID     |  S_CODE |
+------------+---------+---------+
| 12         | 50      | 5       |
| 13         | 50      | 9       |
| 14         | 51      | 1       |
| 15         | 52      | 10      |
+------------+---------+---------+

因此,在本例中,职位50的唯一候选人将是1,因为技能代码(S_CODE)都是5和9,但我也希望候选人2与52匹配,因为它具有所需的工作技能和额外的技能。我已经尝试了几种方法来匹配工作和候选人,但我失败了,这种方法的一个例子是下面的代码:

代码语言:javascript
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    SELECT * , COUNT(skill_job.S_CODE) AS cnt FROM candidate_skill,
 skill_job WHERE candidate_skill.S_CODE = skill_job.S_CODE HAVING (cnt >=2)

问题是,这只将找到的候选人限制为一个,如果我删除COUNT子句,它将列出所有只与一项技能匹配的候选人,因此候选人2也将与职位50匹配。

下面是来自phpmyadmin的表的mysql代码:

代码语言:javascript
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    -- phpMyAdmin SQL Dump
-- version 3.4.5
-- http://www.phpmyadmin.net
--
-- Host: localhost
-- Generation Time: Jul 16, 2012 at 09:27 PM
-- Server version: 5.5.16
-- PHP Version: 5.3.8

SET SQL_MODE="NO_AUTO_VALUE_ON_ZERO";
SET time_zone = "+00:00";


/*!40101 SET @OLD_CHARACTER_SET_CLIENT=@@CHARACTER_SET_CLIENT */;
/*!40101 SET @OLD_CHARACTER_SET_RESULTS=@@CHARACTER_SET_RESULTS */;
/*!40101 SET @OLD_COLLATION_CONNECTION=@@COLLATION_CONNECTION */;
/*!40101 SET NAMES utf8 */;

--
-- Database: `employment`
--

-- --------------------------------------------------------

--
-- Table structure for table `candidate`
--

CREATE TABLE IF NOT EXISTS `candidate` (
  `CID` int(4) NOT NULL AUTO_INCREMENT,
  `title` varchar(5) NOT NULL,
  `fname` varchar(30) NOT NULL,
  `lname` varchar(30) NOT NULL,
  `dob` date NOT NULL,
  `email` varchar(50) NOT NULL,
  `address` varchar(255) NOT NULL,
  `city` varchar(50) NOT NULL,
  `postcode` varchar(10) NOT NULL,
  `phone_num` varchar(11) NOT NULL,
  `username` varchar(40) NOT NULL,
  `password` varchar(40) NOT NULL,
  `regdate` datetime NOT NULL,
  `acc_type` enum('c','s') NOT NULL DEFAULT 'c',
  `emailactivate` enum('0','1') NOT NULL DEFAULT '0',
  `cv_name` varchar(60) NOT NULL,
  `cv` blob NOT NULL,
  PRIMARY KEY (`CID`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 COMMENT='// this is the table for the candidates' AUTO_INCREMENT=175 ;

--
-- Dumping data for table `candidate`
--

INSERT INTO `candidate` (`CID`, `title`, `fname`, `lname`, `dob`, `email`, `address`, `city`, `postcode`, `phone_num`, `username`, `password`, `regdate`, `acc_type`, `emailactivate`, `cv_name`, `cv`) VALUES
(128, 'Mr', 'clement', 'Chilingulo', '0000-00-00', 'chlngl@yahoo.com', '28 oakfield Road', 'london', 'E6 1LW', '07771611873', 'casante', 'b59c67bf196a4758191e42f76670ceba', '0000-00-00 00:00:00', 'c', '0', '', '');
INSERT INTO `candidate` (`CID`, `title`, `fname`, `lname`, `dob`, `email`, `address`, `city`, `postcode`, `phone_num`, `username`, `password`, `regdate`, `acc_type`, `emailactivate`, `cv_name`, `cv`) VALUES
(134, 'Mr', 'rverv', 'revrb', '0000-00-00', 'tdbsdrt', 'trsbrtd', 'trbtrtrb', 'tbrfbgrts', 'trfbtrgbrfg', 'clement', 'b59c67bf196a4758191e42f76670ceba', '0000-00-00 00:00:00', 's', '0', '', '');
INSERT INTO `candidate` (`CID`, `title`, `fname`, `lname`, `dob`, `email`, `address`, `city`, `postcode`, `phone_num`, `username`, `password`, `regdate`, `acc_type`, `emailactivate`, `cv_name`, `cv`) VALUES
(165, 'Mr', 'oinInINOioni', 'ioin', '0000-00-00', 'inioimn', 'in', 'oin', 'oni', 'io', 'k', '7b8b965ad4bca0e41ab51de7b31363a1', '0000-00-00 00:00:00', 'c', '0', '', ''),
(166, 'Mr', 'pjINoNlkinoinoi', 'ino', '0000-00-00', 'oimpnponi', 'inoi', 'no', 'nj', 'nio', 'nio', 'eb5bc837d01b911029ae378e8a1c9f5d', '0000-00-00 00:00:00', 'c', '0', '', ''),
(167, 'Mr', 'vrae', 'ergvaer', '0000-00-00', 'aerbg', 'aergvera', 'aergvrea', 'aergvear', 'aergarev', 'grebvarvf', '609c1b136ec8d0d2dfdf9a2105fb605f', '0000-00-00 00:00:00', 'c', '0', '', ''),
(168, 'Mr', 'vrae', 'ergvaer', '0000-00-00', 'aerbg', 'aergvera', 'aergvrea', 'aergvear', 'aergarev', 'grebvarvf', '609c1b136ec8d0d2dfdf9a2105fb605f', '0000-00-00 00:00:00', 'c', '0', '', ''),
(169, 'Mr', 'ubp', 'bu', '0000-00-00', 'ubip', ';ub', 'ubi', 'ubo', 'buo', 'ubiipbu', '9f44ce1389a3e7372834ed730b559a5e', '0000-00-00 00:00:00', 'c', '0', '', ''),
(170, 'Mr', 'rvev', 'ferhbgetb', '0000-00-00', 'tsbtrb', 'trbstrb', 'trbsfb ', 'stb stb', 'vvfs', 'csdcdsvarewdcv', 'd41d8cd98f00b204e9800998ecf8427e', '0000-00-00 00:00:00', 'c', '0', '', ''),
(171, 'Mr', 'rvev', 'ferhbgetb', '0000-00-00', 'tsbtrb', 'trbstrb', 'trbsfb ', 'stb stb', 'vvfs', 'csdcdsvarewdcv', 'd41d8cd98f00b204e9800998ecf8427e', '0000-00-00 00:00:00', 'c', '0', '', ''),
(172, '', '', '', '0000-00-00', '', '', '', '', '', '', 'd41d8cd98f00b204e9800998ecf8427e', '0000-00-00 00:00:00', 'c', '0', '', ''),
(173, '', 'dds', 'vrv av', '0000-00-00', 'rvear', 'vreverav', 'rvedfsdv', 'frvdvf', 'fveavd', 'vdrareavdv', '84c71ac76340092398a1ed4bc7d6fe19', '0000-00-00 00:00:00', 'c', '0', '', ''),
(174, '', 'dds', 'vrv av', '0000-00-00', 'rvedwear', 'vreverav', 'rvedfsdv', 'frvdvf', 'fveavd', 'vdraredfcavdv', 'd41d8cd98f00b204e9800998ecf8427e', '0000-00-00 00:00:00', 'c', '0', '', '');

-- --------------------------------------------------------

--
-- Table structure for table `candidate_skill`
--

CREATE TABLE IF NOT EXISTS `candidate_skill` (
  `CSID` int(4) NOT NULL AUTO_INCREMENT,
  `CID` int(4) NOT NULL,
  `S_CODE` int(4) NOT NULL,
  PRIMARY KEY (`CSID`),
  KEY `CID` (`CID`),
  KEY `S_CODE` (`S_CODE`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 COMMENT='//match candidate and skill' AUTO_INCREMENT=131 ;

--
-- Dumping data for table `candidate_skill`
--

INSERT INTO `candidate_skill` (`CSID`, `CID`, `S_CODE`) VALUES
(114, 134, 2),
(116, 134, 9),
(121, 134, 5),
(126, 128, 1);

-- --------------------------------------------------------

--
-- Table structure for table `job`
--

CREATE TABLE IF NOT EXISTS `job` (
  `JID` int(4) NOT NULL AUTO_INCREMENT,
  `job_title` varchar(40) NOT NULL,
  `job_desc` varchar(255) NOT NULL,
  `start_date` date NOT NULL,
  `end_date` date NOT NULL,
  PRIMARY KEY (`JID`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 COMMENT='// this is the table for the job vacancies' AUTO_INCREMENT=10 ;

--
-- Dumping data for table `job`
--

INSERT INTO `job` (`JID`, `job_title`, `job_desc`, `start_date`, `end_date`) VALUES
(1, 'engineer', ' fix engineering ish that is messed ', '0000-00-00', '0000-00-00'),
(5, 'pilot', '', '0000-00-00', '0000-00-00'),
(8, 'Charity Helper', ' ', '0000-00-00', '0000-00-00'),
(9, 'accountant', '  ', '0000-00-00', '0000-00-00');

-- --------------------------------------------------------

--
-- Table structure for table `skill`
--

CREATE TABLE IF NOT EXISTS `skill` (
  `S_CODE` int(4) NOT NULL AUTO_INCREMENT COMMENT '// this is the skill primary key',
  `skill_name` varchar(40) NOT NULL,
  `skill_desc` varchar(255) NOT NULL,
  PRIMARY KEY (`S_CODE`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=11 ;

--
-- Dumping data for table `skill`
--

INSERT INTO `skill` (`S_CODE`, `skill_name`, `skill_desc`) VALUES
(1, 'speaking', 'English is your first language'),
(2, '  writing', 'You can write English very well'),
(3, ' public', ''),
(5, 'initiative', ''),
(6, 'interviewing', ''),
(7, 'negotiating', ''),
(8, 'leading', ''),
(9, '  energy', ''),
(10, ' organisation', '');

-- --------------------------------------------------------

--
-- Table structure for table `skill_job`
--

CREATE TABLE IF NOT EXISTS `skill_job` (
  `SJID` int(4) NOT NULL AUTO_INCREMENT,
  `JID` int(4) NOT NULL,
  `S_CODE` int(4) NOT NULL,
  PRIMARY KEY (`SJID`),
  KEY `S_CODE` (`S_CODE`),
  KEY `JID` (`JID`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=106 ;

--
-- Dumping data for table `skill_job`
--

INSERT INTO `skill_job` (`SJID`, `JID`, `S_CODE`) VALUES
(91, 5, 2),
(94, 5, 5),
(95, 5, 9),
(98, 1, 1),
(102, 1, 8),
(105, 8, 8);

--
-- Constraints for dumped tables
--

--
-- Constraints for table `candidate_skill`
--
ALTER TABLE `candidate_skill`
  ADD CONSTRAINT `candidate_skill_ibfk_3` FOREIGN KEY (`CID`) REFERENCES `candidate` (`CID`) ON DELETE CASCADE ON UPDATE CASCADE,
  ADD CONSTRAINT `candidate_skill_ibfk_4` FOREIGN KEY (`S_CODE`) REFERENCES `skill` (`S_CODE`) ON DELETE CASCADE ON UPDATE CASCADE;

--
-- Constraints for table `skill_job`
--
ALTER TABLE `skill_job`
  ADD CONSTRAINT `skill_job_ibfk_4` FOREIGN KEY (`JID`) REFERENCES `job` (`JID`) ON DELETE CASCADE ON UPDATE CASCADE,
  ADD CONSTRAINT `skill_job_ibfk_5` FOREIGN KEY (`S_CODE`) REFERENCES `skill` (`S_CODE`) ON DELETE CASCADE ON UPDATE CASCADE;

/*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT */;
/*!40101 SET CHARACTER_SET_RESULTS=@OLD_CHARACTER_SET_RESULTS */;
/*!40101 SET COLLATION_CONNECTION=@OLD_COLLATION_CONNECTION */;
EN

Stack Overflow用户

发布于 2012-07-17 03:47:28

如果您不关心跨数据库管理系统的支持,您可以使用mysql特定的group_concat将两个s_code集合简化为字符串,每个候选人/作业一个字符串,然后像这样比较它们:

代码语言:javascript
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select * from 
(select cs.cid, group_concat(cs.s_code order by cs.s_code) skills 
    from candidate_skill cs group by cs.cid) cs, 
(select sj.jid, group_concat(sj.s_code order by sj.s_code) skills 
    from skill_job sj group by sj.jid) sj
where sj.skills = cs.skills

请注意,当您的表增长时,最终的where将越来越慢,并且您不能在group_concat()创建的字段上创建索引。

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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/11510855

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