blocks|key|3537394|text|这是因为您的查询格式不正确，您可以尝试使用php中的p.brandid++IN+('1,2,3')函数。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3537395|$select->where('p.brandid++IN+(?)',implode(",",$details[brand]));|code-block|syntax|javascript|3537396|entityMap^0|Q|N|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

This is because your query is getting formed wrongly <code>p.brandid IN ('1,2,3')</code> instead of <code>p.brandid IN (1,2,3)</code> you can try using implode function in php

<pre><code>$select-&gt;where('p.brandid IN (?)',implode(",",$details[brand]));
</code></pre>

blocks|key|1959769|text|您可以根据Zend框架对其进行修改|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1959770|locate(concat(',',$details[brand],','),concat(',',p.brandid,','))>0|code-block|syntax|javascript|1959771|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can modify this according to Zend framwork

<pre><code>locate(concat(',',$details[brand],','),concat(',',p.brandid,','))&gt;0
</code></pre>

blocks|key|1811083|text|只是小规模的研究，因为我也有同样的问题。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1811084|我不确定您使用的是哪个版本的Zend。但是@Omesh提供的解决方案不适用于我的1.12版本。|1811085|在我的例子中，它是完全相反的explode解决方案：|offset|length|style|CODE|1811086|$select->where('p.brandid++IN+(?)',+explode(',',$details[brand]));|code-block|syntax|javascript|1811087|这可能取决于$details['brand']的类型。在我的例子中，我有像555,666,777,877这样的字符串。但即使你在那里有数组。如果Zend接受string+(implode的结果)而不接受array，那就很奇怪了。在我的例子中，它不接受string，但接受array。|1811088|entityMap^0|0|0|E|7|0|0|6|H|11|F|26|6|2E|7|2T|5|3H|6|3R|5|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|T|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|U|8|@$F|V|G|W|H|I]]|9|@]|A|$]]|$1|J|3|K|5|L|7|X|8|@]|9|@]|A|$M|N]]|$1|O|3|P|5|6|7|Y|8|@$F|Z|G|10|H|I]|$F|11|G|12|H|I]|$F|13|G|14|H|I]|$F|15|G|16|H|I]|$F|17|G|18|H|I]|$F|19|G|1A|H|I]|$F|1B|G|1C|H|I]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|1D|8|@]|9|@]|A|$]]]|R|$]]

Just small research, because I have the same problem.

I am not sure what version of Zend do you use. But solution provided by @Omesh doesn't work with my version 1.12.

In my case it is absolutely opposite <code>explode</code> solution:

<pre><code>$select-&gt;where('p.brandid IN (?)', explode(',',$details[brand]));
</code></pre>

Probably it depends on the type of <code>$details['brand']</code>. In my case I have string like <code>555,666,777,877</code>. But even if you have array there. That is strange if Zend accept in your case <code>string</code> (result of <code>implode</code>) and does not accept <code>array</code>. And in my case it does not accept <code>string</code> but accept <code>array</code>.

blocks|key|3450629|text|只需使用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3450630|$select->where->in('field_name',+$your_simple_array);|code-block|syntax|javascript|3450631|如果您以前使用where()函数时使用了某些条件，例如|offset|length|style|CODE|3450632|$select->where(['field_name'+=>+$value]);|3450633|只需使用它后面的第一个，比如|3450634|$select->where(['field_name'+=>+$value]);
$select->where->in('field_name',+$your_simple_array);|3450635|请始终记住，不要将where用作函数where()，而应仅将其用作关键字。|3450636|这是有效的，我在以下上下文中进行了测试：|3450637|$select+=+$this->tableGateway->getSql()->select()->where(['field1'+=>+$v1,+'field2'+=>+$v2]);
$select->where->in('field_name',+['v1',+'v2',+'v3']);|3450638|也就是说，在模型类的开头使用这些库：|3450639|use+Zend\Db\Sql\Sql;
use+Zend\Db\Sql\Where;|3450640|entityMap^0|0|0|7|7|0|0|0|0|9|5|I|7|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|15|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|16|8|@$I|17|J|18|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|19|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|1A|8|@]|9|@]|A|$]]|$1|Q|3|R|5|D|7|1B|8|@]|9|@]|A|$E|F]]|$1|S|3|T|5|6|7|1C|8|@$I|1D|J|1E|K|L]|$I|1F|J|1G|K|L]]|9|@]|A|$]]|$1|U|3|V|5|6|7|1H|8|@]|9|@]|A|$]]|$1|W|3|X|5|D|7|1I|8|@]|9|@]|A|$E|F]]|$1|Y|3|Z|5|6|7|1J|8|@]|9|@]|A|$]]|$1|10|3|11|5|D|7|1K|8|@]|9|@]|A|$E|F]]|$1|12|3|-4|5|6|7|1L|8|@]|9|@]|A|$]]]|13|$]]

Just use

<pre><code>$select-&gt;where-&gt;in('field_name', $your_simple_array);
</code></pre>

If you using <code>where()</code> function with something criteria before, like 

<pre><code>$select-&gt;where(['field_name' =&gt; $value]);
</code></pre>

just use the first one after it, like 

<pre><code>$select-&gt;where(['field_name' =&gt; $value]);
$select-&gt;where-&gt;in('field_name', $your_simple_array);
</code></pre>

Always remember to use <code>where</code> not as a function <code>where()</code>, but just as a keyword.

This is valid and tested by me in the following context:

<pre><code>$select = $this-&gt;tableGateway-&gt;getSql()-&gt;select()-&gt;where(['field1' =&gt; $v1, 'field2' =&gt; $v2]);
$select-&gt;where-&gt;in('field_name', ['v1', 'v2', 'v3']);
</code></pre>

That is, using these libraries in the beginning of the model class:

<pre><code>use Zend\Db\Sql\Sql;
use Zend\Db\Sql\Where;
</code></pre>

Using the zend framework i have used a query,having a IN clause,this is my query

<pre><code> $select-&gt;where('p.brandid IN (?)',$details[brand]);
</code></pre>

in the above query, $details[brand] has a value like this array(1,2,3) .

Actually the query has to return all the values which are all related to this array(1,2,3).

But my query is returning the result related to the first value present in the above array(1,2,3).ie 1 alone other 2,3 is not considered. 

when i print this query it shows like this 

<pre><code> [where] =&gt; Array
 (
 [0] =&gt; (p.brandid IN ('1,2,3'))
 )
</code></pre>

Can anyone show me what is the mistake i have made or solution for this..

Zend Framework Mysql WHERE IN clause

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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使用zend框架，我使用了一个查询，有一个IN子句，这是我的查询       $select->where('p.brandid  IN (?)',$details[brand]);在上面的查询中，$detailsbrand的值类似于这个数组(1，2，3)。实际上，查询必须返回所有与该数组(1，2，3)相关的值。但是我...

问Zend Framework Mysql WHERE IN子句
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