blocks|key|3674073|text|你在你的描述中用了正确的词。使用stop()|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3674074|$("#photo").stop().fadeTo("fast",+0,+function()+{|code-block|syntax|javascript|3674075|entityMap|0|LINK|mutability|MUTABLE|url|http://api.jquery.com/stop/^0|G|6|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

Well you use the correct word in your descripton. Use <a href="http://api.jquery.com/stop/" rel="nofollow">stop()</a>

<pre><code>$("#photo").stop().fadeTo("fast", 0, function() {
</code></pre>

blocks|key|3674107|text|您可以使用setTimeout函数在两次单击抓取之间进行延迟。我的意思是，第二次点击只有在一段时间后，在第一次点击之后才会被处理。它设置两次单击之间的间隔。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3674108|entityMap^0|5|A|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

You may use a <code>setTimeout</code> function to make a delay between click grabs. I mean, a second click will be processed only after sometime, after the first click. It sets an interval between clicks.

blocks|key|3763950|text|我相信你要找的是.stop()+http://api.jquery.com/stop/|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3763951|$("#photo").stop(false,+false).fadeTo()|code-block|syntax|javascript|3763952|entityMap|0|LINK|mutability|MUTABLE|url|http://api.jquery.com/stop/^0|8|7|G|R|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@$9|V|A|W|1|X]]|E|$]]|$1|F|3|G|5|H|7|Y|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]]]

I believe what you are looking for is <code>.stop()</code>
<a href="http://api.jquery.com/stop/" rel="nofollow">http://api.jquery.com/stop/</a>

<pre><code>$("#photo").stop(false, false).fadeTo()
</code></pre>

blocks|key|2072932|text|$(document).ready(function()+{
++++var+loaded+=+true;
++++$(".jTscroller+a").click(function(event)+{
++++++++if(!loaded)+return;
++++++++loaded+=+false;
++++++++event.preventDefault();
++++++++var+target+=+$(this).attr("href");
++++++++$("#photo").fadeTo("fast",+0,+function()+{
++++++++++++$("#photo").attr("src",target);
++++++++++++$("#photo").load(function()+{
++++++++++++++++$("#photo").fadeTo("fast",+1);
++++++++++++++++loaded+=+true;
++++++++++++});
++++++++});
++++});
});|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|2072933|跟踪其状态|unstyled|2072934|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>$(document).ready(function() {
 var loaded = true;
 $(".jTscroller a").click(function(event) {
 if(!loaded) return;
 loaded = false;
 event.preventDefault();
 var target = $(this).attr("href");
 $("#photo").fadeTo("fast", 0, function() {
 $("#photo").attr("src",target);
 $("#photo").load(function() {
 $("#photo").fadeTo("fast", 1);
 loaded = true;
 });
 });
 });
});
</code></pre>

Keep track of its state

blocks|key|2038253|text|我会像这样防止它：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2038254|var+photo+=+$("#photo");
if+(0+==+photo.queue("fx").length)+{
+++++foto.fadeTo();
}|code-block|syntax|javascript|2038255|我与stop不同，因为它只在这个元素上的所有动画都完成时才会触发。此外，将元素存储在变量中也会节省一些时间，因为选择器只需获取该元素一次。|offset|length|style|CODE|2038256|entityMap^0|0|0|2|4|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

I would prevent it like this:

<pre><code>var photo = $("#photo");
if (0 == photo.queue("fx").length) {
 foto.fadeTo();
}
</code></pre>

I differs from <code>stop</code> as it will only fire when all animations on this element are done. Also storing the element in a variable will save you some time, because the selector has to grab the element only once.

blocks|key|3763999|text|使用on()和off()：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3764000|$(document).ready(function()+{
++++$(".jTscroller+a").on('click',+changeImage);

++++function+changeImage(e)+{
++++++++e.preventDefault();
++++++++$(e.target).off('click');
++++++++$("#photo").fadeOut("fast",+function()+{
++++++++++++this.src+=+e.target.href;
++++++++++++this.onload+=+function()+{
++++++++++++++++$(this).fadeIn("fast");
++++++++++++++++$(e.target).on('click',+changeImage);
++++++++++++});
++++++++});
++++}
});|code-block|syntax|javascript|3764001|entityMap|0|LINK|mutability|MUTABLE|url|http://api.jquery.com/on/|1|http://api.jquery.com/off/^0|2|4|0|7|5|1|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]|$A|W|B|X|1|Y]]|C|$]]|$1|D|3|E|5|F|7|Z|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|10|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]|Q|$5|L|M|N|C|$O|R]]]]

Use <a href="http://api.jquery.com/on/" rel="nofollow">on()</a> and <a href="http://api.jquery.com/off/" rel="nofollow">off()</a> :

<pre><code>$(document).ready(function() {
 $(".jTscroller a").on('click', changeImage);

 function changeImage(e) {
 e.preventDefault();
 $(e.target).off('click');
 $("#photo").fadeOut("fast", function() {
 this.src = e.target.href;
 this.onload = function() {
 $(this).fadeIn("fast");
 $(e.target).on('click', changeImage);
 });
 });
 }
});
</code></pre>

How can I stop this function from happening twice when a user clicks too fast?

<pre><code>$(document).ready(function() {
 $(".jTscroller a").click(function(event) {
 event.preventDefault();
 var target = $(this).attr("href");
 $("#photo").fadeTo("fast", 0, function() {
 $("#photo").attr("src",target);
 $("#photo").load(function() {
 $("#photo").fadeTo("fast", 1);
 });
 });
 });
});
</code></pre>

The issue I'm having is that if a user clicks too fast the element won't fade back in, it just stays hidden. 

The issue wasn't what I thought it was. When I was clicking on the same thumbnail it would try to load in the same image and stick loading forever. The <code>.stop()</code> answer does fix double animation so I'm accepting that answer, but my solution was to check if the last clicked item was the currently displayed item. New script:

<pre><code>$(document).ready(function() {
 $(".jTscroller a").click(function(event) {
 event.preventDefault();
 var last = $("#photo").attr("src"); 
 var target = $(this).attr("href");
 if (last != target) {
 $("#photo").stop().fadeTo("fast", 0, function() {
 $("#photo").attr("src",target);
 $("#photo").load(function() {
 $("#photo").fadeTo("fast", 1);
 });
 });
 };
 });
});
</code></pre>

Prevent Double Animation in jQuery

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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当用户点击太快时，我如何才能阻止这个函数发生两次？$(document).ready(function() {    $(".jTscroller a").click(function(event) {        event.preventDefault();        var target = $(this)...

问在jQuery中防止双重动画
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