blocks|key|4134888|text|尝试此代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4134889|NSMutableArray*+arrCountryName+=+(NSMutableArray+*)[yourString+componentsSeparatedByString:+@","];|code-block|syntax|javascript|4134890|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

try This Code :

<pre><code>NSMutableArray* arrCountryName = (NSMutableArray *)[yourString componentsSeparatedByString: @","];
</code></pre>

blocks|key|2304845|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2304846|if([dict+objectForKey:@"Result"]+isKindofClass:[NSArray+class]])
{

+++NSArray+*arrValues+=+[dict+objectForKey:@"Result"];
++//u+have+your+array+
++for(NSString+*value+in+arrValues)
++{
++++NSLog(@"%25@",values);
++}
}|code-block|syntax|javascript|2304847|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

try this:

<pre><code>if([dict objectForKey:@"Result"] isKindofClass:[NSArray class]])
{

 NSArray *arrValues = [dict objectForKey:@"Result"];
 //u have your array 
 for(NSString *value in arrValues)
 {
 NSLog(@"%@",values);
 }
}
</code></pre>

blocks|key|2498999|text|如果您完全按照格式复制了打印输出，则@"Result"键似乎包含一个数组数组，该数组包含一个元素，该元素已经是您想要的数组，因此这对您来说应该是有效的：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2499000|NSArray+*res+=+[[dict+objectForKey:@"Result"]+objectAtIndex:0];|code-block|syntax|javascript|2499001|我认为这是数组中的一个数组的原因是，它在列表周围显示了两层嵌套括号。|2499002|entityMap^0|I|9|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@]|D|@]|E|$]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

If you copied the printout exactly as formatted, it appears that the <code>@"Result"</code> key contains an array of arrays with a single element which is already the array that you wanr, so this should work for you:

<pre><code>NSArray *res = [[dict objectForKey:@"Result"] objectAtIndex:0];
</code></pre>

The reason I think this is an array in an array is that it shows two levels of nested parentheses around the list.

blocks|key|4134946|text|NSString+*separatorString+=+@",";
NSScanner+*aScanner+=+[NSScanner+scannerWithString:yourString];
NSString+*thingsScanned;
[aScanner+scanUpToString:separatorString+intoString:&thingsScanned];
NSLog(@"container:+%25@",+thingsScanned);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4134947|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>NSString *separatorString = @",";
NSScanner *aScanner = [NSScanner scannerWithString:yourString];
NSString *thingsScanned;
[aScanner scanUpToString:separatorString intoString:&amp;thingsScanned];
NSLog(@"container: %@", thingsScanned);
</code></pre>

blocks|key|4134989|text|在这里，您可以使用inputString并生成数组输出，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4134990|NSString+*inputString+=+@"Test1,Test2,Test3,Test4";
NSMutableArray*+outputArray+=+[[NSMutableArray+alloc]+init];
outputArray+=+[inputString+componentsSeparatedByString:+@","];|code-block|syntax|javascript|4134991|如果你需要更多的帮助，让我知道。|4134992|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Here you can use your inputString and generate the Array output as follows:

<pre><code>NSString *inputString = @"Test1,Test2,Test3,Test4";
NSMutableArray* outputArray = [[NSMutableArray alloc] init];
outputArray = [inputString componentsSeparatedByString: @","];
</code></pre>

If you need any more help them let me know.

I am getting response from web-service like this

<pre><code>Result = (
 (
 "Test1",
 "Test2",
 "Test3",
 "Test4",
 Test5
 )
);
</code></pre>

By, [dict objectForKey:@"Result"]; I am getting value

<pre><code>(
 "Test1",
 "Test2",
 "Test3",
 "Test4",
 Test5
 )
</code></pre>

So, how can I get values in array format from NSSting format.

For eg. Array :- Test1, Test2, Test3, Test4, Test5

Can anyone reply please.

Thanks in advance.

Split String into Array Objects

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我从web服务中得到了响应，如下所示Result =     (            (        "Test1",        "Test2",        "Test3",        "Test4",        Test5    ));By，dict objectForKey:@"Result"；...

问将字符串拆分为数组对象
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