blocks|key|2626114|text|您可以使用urllib2模块请求url。但我建议使用BeutifulSoup来检查urls内容。http://pypi.python.org/pypi/BeautifulSoup。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2626115|entityMap|0|LINK|mutability|MUTABLE|url|http://pypi.python.org/pypi/BeautifulSoup^0|1C|15|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

You can request a url with urllib2 module. But I suggest using BeutifulSoup to check urls content. <a href="http://pypi.python.org/pypi/BeautifulSoup" rel="nofollow">http://pypi.python.org/pypi/BeautifulSoup</a>.

blocks|key|4836814|text|不再维护djangoembed。但是你可能想看看micawber。它似乎很适合你的要求。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4836815|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/worldcompany/djangoembed|1|https://github.com/coleifer/micawber^0|4|B|0|O|8|1|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@$A|O|B|P|1|Q]|$A|R|B|S|1|T]]|C|$]]|$1|D|3|-4|5|6|7|U|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]|L|$5|G|H|I|C|$J|M]]]]

<a href="https://github.com/worldcompany/djangoembed" rel="nofollow">djangoembed</a> is no longer maintained. But you might want to take a look at <a href="https://github.com/coleifer/micawber" rel="nofollow">micawber</a>. It seems a good fit for your request.

blocks|key|4750018|text|Open+Graph+Protocol实际上是由Facebook发明的，它基本上是一组元数据，你可以添加它来紧密地描述页面的内容:+9GAG将描述正在显示的图像；YouTube将描述视频等。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4750019|在任何一种情况下，如果您按照其他人的建议让应用程序本身从URL检索和解析内容，请非常小心。我更愿意开发一个JavaScript应用程序，它将利用客户端的资源来解析内容本身，因为如果您不小心的话，有很多方法可以让别人向您提供恶意的URL，这些URL会故意耗尽您的应用程序的可用资源，更不用说这个过程本身就非常昂贵。|4750020|entityMap|0|LINK|mutability|MUTABLE|url|http://ogp.me/^0|0|J|0|0|0^^$0|@$1|2|3|4|5|6|7|N|8|@]|9|@$A|O|B|P|1|Q]]|C|$]]|$1|D|3|E|5|6|7|R|8|@]|9|@]|C|$]]|$1|F|3|-4|5|6|7|S|8|@]|9|@]|C|$]]]|G|$H|$5|I|J|K|C|$L|M]]]]

The <a href="http://ogp.me/" rel="nofollow">Open Graph Protocol</a> was indeed invented by Facebook and it's basically a set of metadata you can add to closely describe the page's content: 9GAG would describe the image that's being shown; YouTube would describe the video, etc. Most pages that provide the ability to share the content on Facebook are OGP friendly, but that still doesn't cover the entirety of the content available on the web.

In either case, be very careful if you go down the path of having your application itself retrieve and resolve content from URLs as others suggested. I'd much rather develop a JavaScript application that will utilize the client's resources to resolve the content itself, as there are many ways someone can feed you with malicious URLs that will purposefully exhaust your application's available resources if your not careful, not to mention that the process itself is very expensive to begin with.

blocks|key|4749968|text|要扩展现有的响应:使用requests下载页面，然后使用beautifulsoup4处理它。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|4749969|示例|4749970|import+requests
from+bs4+import+BeautifulSoup

r+=+requests.get('http://www.facebook.com')
soup+=+BeautifulSoup(r.text)
print+soup.title.string|code-block|syntax|javascript|4749971|它会返回|4749972|Welcome+to+Facebook+-+Log+In,+Sign+Up+or+Learn+More|style|CODE|4749973|有关如何从html中提取其他元素的信息，请参阅漂亮汤文档。|4749974|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.python-requests.org/en/latest/|1|http://www.crummy.com/software/BeautifulSoup/^0|B|8|0|S|E|1|0|0|0|0|0|1F|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@$A|13|B|14|1|15]|$A|16|B|17|1|18]]|C|$]]|$1|D|3|E|5|6|7|19|8|@]|9|@]|C|$]]|$1|F|3|G|5|H|7|1A|8|@]|9|@]|C|$I|J]]|$1|K|3|L|5|6|7|1B|8|@]|9|@]|C|$]]|$1|M|3|N|5|6|7|1C|8|@$A|1D|B|1E|O|P]]|9|@]|C|$]]|$1|Q|3|R|5|6|7|1F|8|@]|9|@]|C|$]]|$1|S|3|-4|5|6|7|1G|8|@]|9|@]|C|$]]]|T|$U|$5|V|W|X|C|$Y|Z]]|10|$5|V|W|X|C|$Y|11]]]]

To expand on the existing responses: Download the page using <a href="http://docs.python-requests.org/en/latest/" rel="nofollow">requests</a> and then process it with <a href="http://www.crummy.com/software/BeautifulSoup/" rel="nofollow">beautifulsoup4</a>.

<h3>Example</h3>

<pre><code>import requests
from bs4 import BeautifulSoup

r = requests.get('http://www.facebook.com')
soup = BeautifulSoup(r.text)
print soup.title.string
</code></pre>

Which would return

<code>Welcome to Facebook - Log In, Sign Up or Learn More</code>

See the beautifulsoup documentation on how to pull out other elements from the html.

blocks|key|4836778|text|这个问题没有简单的答案。使用just+requests或urllib2，您可以对结构进行一些猜测，并获取标题或猜测新闻文章/视频的内容。我知道有两种解决方案可以让你从一开始就运行，而不是重新发明轮子。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4836779|4836780|Embed.ly，是一种付费服务，它有一个非常好的API.|ordered-list-item|offset|length|4836781|djangoembed.使用oEmbed协议的免费解决方案。虽然我还没有用过这个，但它似乎正是你所需要的。|4836782|4836783|entityMap|0|LINK|mutability|MUTABLE|url|http://embed.ly/|1|https://github.com/worldcompany/djangoembed^0|0|0|0|8|0|0|0|B|1|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|V|8|@]|9|@]|A|$]]|$1|C|3|D|5|E|7|W|8|@]|9|@$F|X|G|Y|1|Z]]|A|$]]|$1|H|3|I|5|E|7|10|8|@]|9|@$F|11|G|12|1|13]]|A|$]]|$1|J|3|-4|5|6|7|14|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]|S|$5|N|O|P|A|$Q|T]]]]

There's no simple answer for this. Using just requests or urllib2, you can make some guesses on the structure and grab the title or guess what the content may be of a news article / video. Instead of reinventing the wheel, there are two solutions that I know of to get you off the ground running.

<ol>
<li><a href="http://embed.ly" rel="nofollow" title="Embed.ly">Embed.ly</a>, which is a paid service and has a very nice API.</li>
<li><a href="https://github.com/worldcompany/djangoembed" rel="nofollow">djangoembed</a>. A free solution using the oEmbed protocol. Although I haven't used this, it seems like exactly what you need.</li>
</ol>

I'm building a website where users are posting content and URLs, very much alike the facebook wall/news feed.

I was thinking that I could take the URL from the user and open it from the server in the django backend and examine the content (just like facebook does).

I thought that there should be a django-opengraph app which helps me to open a URL and check the meta-tags to determine what kind of content etc. But it seems that Open Graph is an invention of Facebook?

My question is how I can open a URL using django and fetch content (video, audio, images, texts) and by determine what kind of content i can embed it properly into my site? Any apps?

And also, I'm intersted in the security aspect of open URLs from the server sent by a user.

Thanks!

Processing and examine user URLs in django

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在建立一个网站，在那里用户发布内容和URL，非常类似于facebook墙/新闻馈送。我在想，我可以从用户那里获取URL，并在django后端的服务器上打开它，然后检查内容(就像facebook一样)。我想应该有一个django-opengraph应用程序，它可以帮助我打开URL并检查元标记，以确定哪种内容等。但似乎open Graph是Facebook的发明？我的问题是，如何使用django打

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