blocks|key|2618690|text|setTimeout只调用回调一次，这很正常。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|2618691|如果你想让你的函数以固定的时间间隔执行，你可能需要setInterval。|2618692|顺便说一句，您的代码中还有另一个错误:您可能需要|2618693|t+=+setInterval(+function(elem){
++++++++//this+should+be+executed+as+long+as+I+hover,+
++++++++//with+interval+declared+in+viewSpped+variable
++++++++$(elem).find('img').first().appendTo('.'+%2B+container).fadeOut(500);
++++++++$(elem).find('img').first().fadeIn(800);++++
++++},+viewSpeed,+this);|code-block|syntax|javascript|2618694|setInterval或setTimeout传递给回调的参数在持续时间之后。|style|CODE|2618695|或者，为了更好地兼容(请注意，我提供的链接也提供了IE的变通方法)：|2618696|var+$elem+=+$(this);
t+=+setInterval(+function(){
 + ++ + +$elem.find('img').first().appendTo('.'+%2B+container).fadeOut(500);
 + ++ + +$elem.find('img').first().fadeIn(800);+ + 
},+viewSpeed);|2618697|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/DOM/window.setTimeout|1|https://developer.mozilla.org/en-US/docs/DOM/window.setInterval^0|0|A|0|0|P|B|1|0|0|0|0|B|C|A|0|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@]|9|@$A|15|B|16|1|17]]|C|$]]|$1|D|3|E|5|6|7|18|8|@]|9|@$A|19|B|1A|1|1B]]|C|$]]|$1|F|3|G|5|6|7|1C|8|@]|9|@]|C|$]]|$1|H|3|I|5|J|7|1D|8|@]|9|@]|C|$K|L]]|$1|M|3|N|5|6|7|1E|8|@$A|1F|B|1G|O|P]|$A|1H|B|1I|O|P]]|9|@]|C|$]]|$1|Q|3|R|5|6|7|1J|8|@]|9|@]|C|$]]|$1|S|3|T|5|J|7|1K|8|@]|9|@]|C|$K|L]]|$1|U|3|-4|5|6|7|1L|8|@]|9|@]|C|$]]]|V|$W|$5|X|Y|Z|C|$10|11]]|12|$5|X|Y|Z|C|$10|13]]]]

<a href="https://developer.mozilla.org/en-US/docs/DOM/window.setTimeout" rel="nofollow">setTimeout</a> only call the callback once, that's normal.

Maybe you want <a href="https://developer.mozilla.org/en-US/docs/DOM/window.setInterval" rel="nofollow">setInterval</a> if you want your function to be executed at regular intervals.

And, incidently, there is another error in your code : You probably want

<pre><code>t = setInterval( function(elem){
 //this should be executed as long as I hover, 
 //with interval declared in viewSpped variable
 $(elem).find('img').first().appendTo('.' + container).fadeOut(500);
 $(elem).find('img').first().fadeIn(800); 
 }, viewSpeed, this);
</code></pre>

The arguments passed by <code>setInterval</code> or <code>setTimeout</code> to the callback are after the duration.

Or, to be more compatible (note that the link I provide also gives the workaround for IE) :

<pre><code>var $elem = $(this);
t = setInterval( function(){
        $elem.find('img').first().appendTo('.' + container).fadeOut(500);
        $elem.find('img').first().fadeIn(800);    
}, viewSpeed);
</code></pre>

blocks|key|3099791|text|setTimeout在不带参数的情况下调用其回调。所以elem不会被传递给你的回调函数。如果您正在尝试执行自调用函数，那么您所要做的就是立即调用您的函数，而不是将回调传递给setTimeout()。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3099792|我不知道您希望elem是什么，但如果您希望它成为悬停的项目，您可以这样做：|3099793|$('.'+%2B+container).hover(function()+{+++
++++var+self+=+$(this);
++++t+=+setTimeout(+function(){
++++++++//this+should+be+executed+as+long+as+I+hover,+
++++++++//with+interval+declared+in+viewSpped+variable
++++++++self.find('img').first().appendTo('.'+%2B+container).fadeOut(500);
++++++++self.find('img').first().fadeIn(800);++++

++++},+viewSpeed);
}...|code-block|syntax|javascript|3099794|entityMap^0|0|A|R|4|2E|C|0|7|4|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]|$9|R|A|S|B|C]|$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|V|8|@$9|W|A|X|B|C]]|D|@]|E|$]]|$1|H|3|I|5|J|7|Y|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|N|$]]

<code>setTimeout</code> calls its callback with no arguments. So <code>elem</code> will NOT be passed to your callback. If you were trying to do a self-invoking function, then all you're doing is calling your function immediately, not passing a callback to <code>setTimeout()</code>.

I don't know what you expect <code>elem</code> to be, but if you want it to be the item that was hovered, you would do that like this:

<pre><code>$('.' + container).hover(function() { 
 var self = $(this);
 t = setTimeout( function(){
 //this should be executed as long as I hover, 
 //with interval declared in viewSpped variable
 self.find('img').first().appendTo('.' + container).fadeOut(500);
 self.find('img').first().fadeIn(800); 

 }, viewSpeed);
}...
</code></pre>

blocks|key|2618777|text|您将立即调用该函数，而不是将其用作回调(这无论如何都不会起作用，因为您需要传递一个参数)，我想您的意思也是setInterval。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|2618778|var+elem+=+$(this);
var+container+=+$('.'+%2B+container);

t+=+setInterval(function()+{
++++++++elem.find('img').first().appendTo(container).fadeOut(500);
++++++++elem.find('img').first().fadeIn(800);
++++},+viewSpeed);|code-block|syntax|javascript|2618779|entityMap^0|1H|B|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

You're calling the function immediately instead of using it as a callback (which wouldn't work anyway, as you need to pass a parameter), and I think you also meant <code>setInterval</code>.

<pre><code>var elem = $(this);
var container = $('.' + container);

t = setInterval(function() {
 elem.find('img').first().appendTo(container).fadeOut(500);
 elem.find('img').first().fadeIn(800);
 }, viewSpeed);
</code></pre>

I have this code, but it execute only once...

<pre><code>$('.' + container).hover(function() { 
 t = setTimeout( function(elem){
 //this should be executed as long as I hover, 
 //with interval declared in viewSpped variable
 $(elem).find('img').first().appendTo('.' + container).fadeOut(500);
 $(elem).find('img').first().fadeIn(800); 

 }(this), viewSpeed);


 }...
</code></pre>

Any idea what I'm doing wrong? thanks!

setTimeOut code not working with jQuery

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

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我有这段代码，但它只执行一次...$('.' + container).hover(function() {           t = setTimeout( function(elem){            //this should be executed as long as I hover,       ...

问不适用于jQuery的setTimeOut代码
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问不适用于jQuery的setTimeOut代码EN