blocks|key|3449929|text|如果你想知道SLComposeViewController是否支持Facebook，可以查看isAvailableForServiceType，例如|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3449930|if+([SLComposeViewController+class])+{
++++//+once+you+know+that+they+have+iOS+6+or+higher
++++//+check+if+the+account+is+setup
++++if+([SLComposeViewController+isAvailableForServiceType:SLServiceTypeFacebook])
++++{
++++++++//+now+we+know+we+have+a+facebook+account+configure+and+logged+in
++++}
}+else+{
++++//+You+don't+have+iOS+6+or+higher
}|code-block|syntax|javascript|3449931|通常，比起检查iOS的版本，使用API+(或者弱链接类的class或NSClassFromString，或者respondsToSelector，如果一个类有后来版本的iOS中添加的方法)会更好。有关更多信息，请参阅iOS应用程序编程指南的Supporting+Multiple+Versions+of+iOS部分。|3449932|entityMap|0|LINK|mutability|MUTABLE|url|http://developer.apple.com/library/ios/documentation/NetworkingInternet/Reference/SLComposeViewController_Class/Reference/Reference.html#//apple_ref/occ/clm/SLComposeViewController/isAvailableForServiceType:|1|http://developer.apple.com/library/ios/documentation/iphone/conceptual/iphoneosprogrammingguide/AdvancedAppTricks/AdvancedAppTricks.html#//apple_ref/doc/uid/TP40007072-CH7-SW4^0|6|N|1A|P|1A|P|0|0|0|S|5|Y|H|1I|I|3C|Z|1|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@$9|11|A|12|1|13]]|E|$]]|$1|F|3|G|5|H|7|14|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|15|8|@$9|16|A|17|B|C]|$9|18|A|19|B|C]|$9|1A|A|1B|B|C]]|D|@$9|1C|A|1D|1|1E]]|E|$]]|$1|M|3|-4|5|6|7|1F|8|@]|D|@]|E|$]]]|N|$O|$5|P|Q|R|E|$S|T]]|U|$5|P|Q|R|E|$S|V]]]]

If you're wondering if <code>SLComposeViewController</code> supports Facebook, check <a href="http://developer.apple.com/library/ios/documentation/NetworkingInternet/Reference/SLComposeViewController_Class/Reference/Reference.html#//apple_ref/occ/clm/SLComposeViewController/isAvailableForServiceType:" rel="noreferrer"><code>isAvailableForServiceType</code></a>, e.g.

<pre><code>if ([SLComposeViewController class]) {
 // once you know that they have iOS 6 or higher
 // check if the account is setup
 if ([SLComposeViewController isAvailableForServiceType:SLServiceTypeFacebook])
 {
 // now we know we have a facebook account configure and logged in
 }
} else {
 // You don't have iOS 6 or higher
}
</code></pre>

It's generally better to use API (or <code>class</code> or <code>NSClassFromString</code> for weakly linked classes, or <code>respondsToSelector</code>, if a class has methods that were added in later versions of iOS) rather than checking for version of iOS. For more information, see <a href="http://developer.apple.com/library/ios/documentation/iphone/conceptual/iphoneosprogrammingguide/AdvancedAppTricks/AdvancedAppTricks.html#//apple_ref/doc/uid/TP40007072-CH7-SW4" rel="noreferrer">Supporting Multiple Versions of iOS</a> section of the iOS App Programming Guide.

blocks|key|5089354|text|您可以使用以下代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5089355|if([[[UIDevice+currentDevice]+systemVersion]+intValue]+==+6)
{
+//+your+code+for+iOS+6
}
else
{
+//+your+code+for+other+iOS
}|code-block|syntax|javascript|5089356|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You can use the following code: 

<pre><code>if([[[UIDevice currentDevice] systemVersion] intValue] == 6)
{
 // your code for iOS 6
}
else
{
 // your code for other iOS
}
</code></pre>

blocks|key|3449957|text|步骤是:第一个弱链接社会框架(使其成为可选项)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3449958|接下来，检查应用程序是否可以使用SLComposeViewController，然后检查用户是否设置了他们的Facebook帐户|3449959|if(NSClassFromString(@"SLComposeViewController")+!=+nil)
{
++if([SLComposeViewController+isAvailableForServiceType:SLServiceTypeFacebook]])
++{
+++//Add+your+SLComposeViewController+code
++}
}|code-block|syntax|javascript|3449960|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

The steps are:
First weak link the social framework (make it optional)

Next check to see if the app can you use SLComposeViewController and then check to see if the user has set up their Facebook account

<pre><code>if(NSClassFromString(@"SLComposeViewController") != nil)
{
 if([SLComposeViewController isAvailableForServiceType:SLServiceTypeFacebook]])
 {
 //Add your SLComposeViewController code
 }
}
</code></pre>

I have in my app a facebook share button, a tweet button. My app supports to IOS 5.1. 
So for twitter there is no problem. But how should I work with the facebook share button. 

If the IOS device that is running the app is using IOS6 I want to use the new way, like you can see over <a href="http://www.google.com/imgres?q=facebook%20share%20in%20app%20ios&amp;um=1&amp;hl=nl&amp;sa=N&amp;tbm=isch&amp;tbnid=IFGDxpn5cChLRM%3a&amp;imgrefurl=http://www.theiospost.com/latest/2012/9/19/ios-6-review.html&amp;docid=pfXBWRkOxzy7nM&amp;imgurl=http://www.theiospost.com/storage/iOS6-Review-FacebookShareSheet.png%253F__SQUARESPACE_CACHEVERSION%253D1348056541859&amp;w=765&amp;h=1499&amp;ei=_vF_ULfTLe7R4QS504HgBw&amp;zoom=1&amp;iact=rc&amp;dur=299&amp;sig=114756556720582691644&amp;page=1&amp;tbnh=156&amp;tbnw=80&amp;start=0&amp;ndsp=27&amp;ved=1t:429,r:4,s:20,i:144&amp;tx=33&amp;ty=78&amp;biw=1422&amp;bih=707" rel="nofollow">here</a>

But when the app is running on previous IOS devices. I want to use the old fashion way.

Can anybody help me?

Kind regards

determine which IOS is running on the device

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我的应用程序中有一个facebook分享按钮，一个推文按钮。我的应用支持IOS 5.1。因此，对于twitter来说，这不是问题。但是我该如何使用facebook的分享按钮呢？如果运行应用程序的IOS设备使用的是IOS6，我想使用新的方式，就像您在上看到的那样但当该应用程序在以前的IOS设备上运行时。我想用传统的方式。...

问确定设备上运行的是哪个IOS
EN

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问确定设备上运行的是哪个IOSEN