数组内的substr_count
数组内的substr_count
提问于 2012-10-19 17:12:10
我正在尝试搜索强标签中的关键字。
我已经为标记生成了一个数组，它显示为：
Array
(
[0] => Array
(
[0] => seo agency in london
[1] => seo agency in london
[2] => seo consultant in london
[3] => seo consultant in london
[4] => seo experts in london
)
[1] => Array
(
[0] => seo agency in london
[1] => seo agency in london
[2] => seo consultant in london
[3] => seo consultant in london
[4] => seo experts in london
)
)我想搜索关键字，在本例中是"seo“
我正在使用：
function substr_count_array( $haystack, $needle ) {
$count = 0;
foreach ($needle as $substring) {
$count += substr_count( $haystack, $substring);
}
return $count;
}
$matchPattern7 = '/<strong(?:"(?:[^\\\"]|\\\.)*"|\'(?:[^\\\\\']|\\\.)*\'|[^\'">])*>(.*?)<\/strong>/';
preg_match_all($matchPattern7, $content, $foundIt7);
echo substr_count_array(strtolower($foundIt7), strtolower($keyword));作为参考..
$keyword = seo
我得到的是零，有人能帮我吗？谢谢
回答 2
Stack Overflow用户
回答已采纳
发布于 2012-10-19 17:46:57
经过测试并为我工作：
$foundIt7=array();
$foundIt7[1]=array(0 => ' seo agency in london',
1 => 'seo agency in london',
2 => 'seo consultant in london',
3 => 'seo consultant in london',
4 => 'seo experts in london');
print_r($foundIt7[1]);
function substr_count_array( $haystackAr, $needle ) {
$count = 0;
foreach ($haystackAr as $haystack) {
$count += substr_count( $haystack, $needle);
}
return $count;
}
echo substr_count_array($foundIt7[1],'seo');//returns 5Stack Overflow用户
发布于 2012-10-19 17:17:13
function substr_count_array( $haystack, $needle ) {
$count = 0;
foreach ( $haystack as $substring) {
foreach($substring as $string)
{
$count += substr_count($string, $haystack);
}
}
return $count;
}页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/12970977
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