blocks|key|5175730|text|另一种方法|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|5175731|您可以像这样简单地检查请求是否为AJAX。|5175732|/*+AJAX+check++*/
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH'])+&&+strtolower($_SERVER['HTTP_X_REQUESTED_WITH'])+==+'xmlhttprequest')+{
++echo+'its+ajax!';
}else{
++echo+'im+called,+but+not+via+ajax';
}|code-block|syntax|javascript|5175733|entityMap^0|0|5|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|R|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|S|8|@]|D|@]|E|$K|L]]|$1|M|3|-4|5|6|7|T|8|@]|D|@]|E|$]]]|N|$]]

Another method

You can simple check whether the request is AJAX or not like this,

<pre><code>/* AJAX check */
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) &amp;&amp; strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
 echo 'its ajax!';
}else{
 echo 'im called, but not via ajax';
}
</code></pre>

blocks|key|3537209|text|需要添加通过AJAX调用发送的数据中的is_ajax:+1。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3537210|entityMap^0|J|A|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

Needed to add <code>is_ajax: 1</code> in data that is being sent via AJAX call.

blocks|key|5266569|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5266570|jQuery.ajax({
++++++++++++type:+'POST',
++++++++++++url:+'my-service.php',
++++++++++++data:+{is_ajax:1},
++++++++++++success:+function(response)+{+
++++++++++++++++alert(response);
+++++++++++++}
++++++++});|code-block|syntax|javascript|5266571|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

try this : 

<pre><code>jQuery.ajax({
 type: 'POST',
 url: 'my-service.php',
 data: {is_ajax:1},
 success: function(response) { 
 alert(response);
 }
 });
</code></pre>

blocks|key|3053977|text|编辑AJAX调用并修改数据|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3053978|jQuery.ajax({
++++++++++++type:+'POST',
++++++++++++url:+'my-service.php',
++++++++++++data:+{"is_ajax":"the+value"},
++++++++++++success:+function(response)+{+
++++++++++++++++alert(response);
+++++++++++++}
++++++++});|code-block|syntax|javascript|3053979|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

edit your AJAX call and modify the data

<pre><code>jQuery.ajax({
 type: 'POST',
 url: 'my-service.php',
 data: {"is_ajax":"the value"},
 success: function(response) { 
 alert(response);
 }
 });
</code></pre>

blocks|key|5175787|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5175788|if(isset($_POST['is_ajax']))
{
++++echo+'its+ajax!';
}
else+
{
echo+'im+called,+but+not+via+ajax';
}|code-block|syntax|javascript|5175789|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try this : 

<pre><code>if(isset($_POST['is_ajax']))
{
 echo 'its ajax!';
}
else 
{
echo 'im called, but not via ajax';
}
</code></pre>

blocks|key|3054006|text|您检测AJAX的方法似乎是错误的。如果你的服务器支持HTTP_X_REQUESTED_WITH，那么这就是解决之道：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3054007|if(!empty($_SERVER['HTTP_X_REQUESTED_WITH'])+&&+strtolower($_SERVER['HTTP_X_REQUESTED_WITH'])+==+'xmlhttprequest')+{
++/*+special+ajax+here+*/
++die($content);
}|code-block|syntax|javascript|3054008|来源：Detect+an+AJAX+Request|offset|length|3054009|entityMap|0|LINK|mutability|MUTABLE|url|http://davidwalsh.name/detect-ajax^0|0|0|3|M|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

It seems that your method of detecting AJAX is wrong. If your server supports HTTP_X_REQUESTED_WITH, then it's the way to go :

<pre><code>if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) &amp;&amp; strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
 /* special ajax here */
 die($content);
}
</code></pre>

source : <a href="http://davidwalsh.name/detect-ajax" rel="nofollow">Detect an AJAX Request</a>

I'm calling a file via jQuery's AJAX method looks like this:

<pre><code> $is_ajax = $_REQUEST['is_ajax'];
 if(isset($is_ajax) &amp;&amp; $is_ajax)
 {
 echo 'its ajax!';
 }
 else echo 'im called, but not via ajax';
</code></pre>

and my AJAX call:

<pre><code>jQuery.ajax({
 type: 'POST',
 url: 'my-service.php',
 data: data,
 success: function(response) { 
 alert(response);
 }
 });
</code></pre>

But alert always shows 'not ajax' message. What am I doing wrong?

PHP not recognising AJAX call

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在通过jQuery的AJAX方法调用一个文件，如下所示：    $is_ajax = $_REQUEST['is_ajax'];    if(isset($is_ajax) && $is_ajax)    {        echo 'its ajax!';    }    else echo 'im called...

问PHP无法识别AJAX调用
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