blocks|key|2546048|text|为什么不使用find命令创建一个数组来获取文件名列表呢？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2546049|例如：|2546050|#!/bin/bash
IFS=$'\n'
MyArr=($(find+/location/to/Kanto-station-names/+-type+f+-print0+%7C+xargs+-0+ls))

echo+${MyArr[@]}
echo+${MyArr[1}
echo+${MyArr[2}
echo+${MyArr[3}+|code-block|syntax|javascript|2546051|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Why not just create an array using the find command to get your list of filenames?

Ex:

<pre><code>#!/bin/bash
IFS=$'\n'
MyArr=($(find /location/to/Kanto-station-names/ -type f -print0 | xargs -0 ls))

echo ${MyArr[@]}
echo ${MyArr[1}
echo ${MyArr[2}
echo ${MyArr[3} 
</code></pre>

blocks|key|1467116|text|您的问题很难理解，但如果您只想将关东-station-names目录中的所有文件名组成一个数组，这应该是可行的(请注意，前导的'$‘是一个提示符，而不是您应该键入的内容)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1467117|$+myArray=()
$+for+FILE+in+`ls+Kanto-station-names`+;+do+myArray%2B=($FILE)+;+done|code-block|syntax|javascript|1467118|在此之后，您可以访问数组元素：|1467119|$+echo+${myArray[0]}
$+echo+${myArray[1]}|1467120|要查看数组的所有元素，请执行以下操作：|1467121|$+echo+${myArray[@]}|1467122|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

Your question is difficult to understand, but if you just want to make an array of all the filenames in Kanto-station-names directory, this should work (note that the leading '$' is a prompt, not something you should type):

<pre><code>$ myArray=()
$ for FILE in `ls Kanto-station-names` ; do myArray+=($FILE) ; done
</code></pre>

After that, you can access array elements:

<pre><code>$ echo ${myArray[0]}
$ echo ${myArray[1]}
</code></pre>

etc.
To see all elements of the array:

<pre><code>$ echo ${myArray[@]}
</code></pre>

blocks|key|4425795|text|#!/usr/bin/env+bash

#+cause+globs+to+expand+to+an+empty+list+if+no+matches+exist
shopt+-s+nullglob

#+Use+a+glob+expression+to+populate+the+array
stations=(+Kanto-station-names/*+)

((+${#stations[@]}+))+%7C%7C+{
++echo+"ERROR:+No+stations+exist+(make+sure+Kanto-station-names+contains+files)"+>&2
++exit+1
}

##+read+into+an+array+(bash+4.0+or+newer)
#readarray+-t+myarr+<+<(awk+'{print+$1}'+"${stations[@]}")

#+read+into+an+array+(bash+3.x-compatible)
IFS=$'\n'+read+-r+-d+''+-a+myarr+<+<(awk+'{print+$1}'+"${stations[@]}"+&&+printf+'\0')+%7C%7C+{
++echo+"Error+extracting+first+column+from+station+list"+>&2
++exit+1
}

#+print+definition+of+our+populated+array+as+output
declare+-p+myarr|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4425796|unstyled|4425797|注意事项：|4425798|4425799|我们在这段代码中没有使用ls。所有文件名列表的生成都是通过globbing执行的。请参见Why+you+shouldn't+parse+the+output+of+ls(1).|unordered-list-item|offset|length|style|CODE|4425800|"${stations[@]}"在运行awk的进程替换中展开，因此名称将传递给awk+--这是原始代码中的错误之一。|4425801|bash4.0的注释掉替代选项中的readarray代码无法检测到awk中的失败退出状态。使用bash4.4或更高版本，您可以通过运行wait+"$!"+%7C%7C+{+echo+"Process+failed"+>&2;+}或类似程序来检测进程替换何时失败--在此之前，无法检测到进程替换的退出状态，因此，即使使用bash4.0到4.3，也有充分的理由使用与bash3.x兼容的方法。|4425802|4425803|entityMap|0|LINK|mutability|MUTABLE|url|http://mywiki.wooledge.org/ParsingLs^0|0|0|0|0|C|2|18|17|0|0|0|G|J|3|13|3|0|H|9|X|3|1V|17|0|0^^$0|@$1|2|3|4|5|6|7|12|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|13|8|@]|9|@]|A|$]]|$1|F|3|G|5|E|7|14|8|@]|9|@]|A|$]]|$1|H|3|-4|5|E|7|15|8|@]|9|@]|A|$]]|$1|I|3|J|5|K|7|16|8|@$L|17|M|18|N|O]]|9|@$L|19|M|1A|1|1B]]|A|$]]|$1|P|3|Q|5|K|7|1C|8|@$L|1D|M|1E|N|O]|$L|1F|M|1G|N|O]|$L|1H|M|1I|N|O]]|9|@]|A|$]]|$1|R|3|S|5|K|7|1J|8|@$L|1K|M|1L|N|O]|$L|1M|M|1N|N|O]|$L|1O|M|1P|N|O]]|9|@]|A|$]]|$1|T|3|-4|5|E|7|1Q|8|@]|9|@]|A|$]]|$1|U|3|-4|5|E|7|1R|8|@]|9|@]|A|$]]]|V|$W|$5|X|Y|Z|A|$10|11]]]]

<pre><code>#!/usr/bin/env bash

# cause globs to expand to an empty list if no matches exist
shopt -s nullglob

# Use a glob expression to populate the array
stations=( Kanto-station-names/* )

(( ${#stations[@]} )) || {
 echo "ERROR: No stations exist (make sure Kanto-station-names contains files)" &gt;&amp;2
 exit 1
}

## read into an array (bash 4.0 or newer)
#readarray -t myarr &lt; &lt;(awk '{print $1}' "${stations[@]}")

# read into an array (bash 3.x-compatible)
IFS=$'\n' read -r -d '' -a myarr &lt; &lt;(awk '{print $1}' "${stations[@]}" &amp;&amp; printf '\0') || {
 echo "Error extracting first column from station list" &gt;&amp;2
 exit 1
}

# print definition of our populated array as output
declare -p myarr
</code></pre>

<hr>

Items of note:

<ul>
<li>We don't use <code>ls</code> anywhere in this code. All generation of lists of filenames is performed with globbing. See <a href="http://mywiki.wooledge.org/ParsingLs" rel="nofollow noreferrer">Why you shouldn't parse the output of ls(1)</a>.</li>
<li><code>"${stations[@]}"</code> is expanded inside the process substitution that's running <code>awk</code>, so names are passed to <code>awk</code> -- this was one of the bugs in the original code.</li>
<li>The <code>readarray</code> code in the commented-out alternative for bash 4.0 does not detect a failed exit status from <code>awk</code>. With bash 4.4 or newer, you can detect when a process substitution fails by running <code>wait "$!" || { echo "Process failed" &gt;&amp;2; }</code> or similar -- prior to that point exit status of a process substitution can't be detected, so there are compelling reasons to use the bash 3.x-compatible approach even with bash 4.0 through 4.3.</li>
</ul>

I am trying to create an array of file names so I can sort through a large file and take only the ones I want. My script looks like this
<code>set STATIONS = Kanto-station-names</code> Where the folder "Kanto-station-names" has the names of files I want. This is followed by <code>myarr=($(awk '{print $1}') $STATIONS)</code> but terminal immediately goes into a subshell that looks more like a work document where commands do not function and I cannot exit. Any suggestions?

How can I fix my bash array?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在尝试创建一个文件名的数组，这样我就可以对一个大文件进行排序，并只获取我想要的文件。我的脚本看起来像这样的set STATIONS = Kanto-station-names，其中的文件夹“Kanto-station-name”包含我想要的文件名。紧随其后的是myarr=($(awk '{print $1}') $...

问如何修复我的bash数组？
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问如何修复我的bash数组？EN