我正在尝试制作一个Android应用程序,可以打开docx文件进行读取、编辑和保存。
我的想法是将存档中的所有xml文件提取到一个临时文件夹中。在这个文件夹中,我们可以在/word/document.xml中编辑文档的内容。问题是,当我压缩这个临时文件夹来创建一个新的docx文件并替换旧文件时,在新的docx存档中,路径类似于/mnt/sdcard/temp/"all files xml go here",而xml文件应该在第一级。
有人能帮我解决这个问题吗?以下是压缩临时目录的方法
注意:我使用的dir2zip参数的值是/mnt/sdcard/temp/***.docx
public void zipDir(String dir2zip, ZipOutputStream zos)
{
try
{
//create a new File object based on the directory we
//have to zip File
File zipDir = new File(dir2zip);
//get a listing of the directory content
String[] dirList = zipDir.list();
byte[] readBuffer = new byte[2156];
int bytesIn = 0;
//loop through dirList, and zip the files
for(int i=0; i<dirList.length; i++)
{
File f = new File(zipDir, dirList[i]);
if(f.isDirectory())
{
//if the File object is a directory, call this
//function again to add its content recursively
String filePath = f.getPath();
zipDir(filePath, zos);
//loop again
continue;
}
//if we reached here, the File object f was not a directory
//create a FileInputStream on top of f
FileInputStream fis = new FileInputStream(f);
//create a new zip entry
ZipEntry anEntry = new ZipEntry(f.getPath());
//place the zip entry in the ZipOutputStream object
zos.putNextEntry(anEntry);
//now write the content of the file to the ZipOutputStream
while((bytesIn = fis.read(readBuffer)) != -1)
{
zos.write(readBuffer, 0, bytesIn);
}
//close the Stream
fis.close();
}
}
catch(Exception e)
{
//handle exception
}
}发布于 2012-11-27 15:04:54
我已经设法自己修好了。问题出在下面这一行:
File f = new File(zipDir, dirList[i]);它应该是
File f = new File(dirList[i]);如果包含参数zipDir,则在归档中将使用目录的绝对路径!
https://stackoverflow.com/questions/13566468
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