blocks|key|4661103|text|var+numAlpha+=+new+Regex("(?<NumOne>[0-9]%2B)(?<Operator>[%5E0-9])(?<NumTwo>[0-9]%2B)");
var+match+=+numAlpha.Match("121165468746*1132");
var+nb1+=+match.Groups["NumOne"].Value;+//+nb1+=+121165468746
var+nb2+=+match.Groups["NumTwo"].Value;+//+nb2+=+1132
var+op+=+match.Groups["Operator"].Value;+//+op+=+*|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|4661104|看起来您要做的是匹配由运算符分隔的一对整数。上面的正则表达式使用命名组(?<GroupName>+...+)和两个简单的正则表达式来实现。[0-9]%2B将匹配一个或多个数字，而[%5E0-9]将匹配任何一个非数字字符，这里假设它是运算符。|unstyled|offset|length|style|CODE|4661105|如果这不是你想要的，请留言，我会尽力帮助你。|4661106|4661107|Regular+Expressions+Page,+with+plenty+of+tutorials+and+references|unordered-list-item|4661108|Javascript+Regular+Expressions+Tester+with+Syntax+Highlighting|4661109|Java+RegEx+Tester.++More+powerful,+fewer+frills.|4661110|4661111|entityMap|0|LINK|mutability|MUTABLE|url|http://www.regular-expressions.info/|1|http://regexpal.com/|2|http://gskinner.com/RegExr/^0|0|Z|J|1X|6|2F|6|0|0|0|0|1T|0|0|0|1Q|1|0|0|1C|2|0|0^^$0|@$1|2|3|4|5|6|7|17|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|18|8|@$G|19|H|1A|I|J]|$G|1B|H|1C|I|J]|$G|1D|H|1E|I|J]]|9|@]|A|$]]|$1|K|3|L|5|F|7|1F|8|@]|9|@]|A|$]]|$1|M|3|-4|5|F|7|1G|8|@]|9|@]|A|$]]|$1|N|3|O|5|P|7|1H|8|@]|9|@$G|1I|H|1J|1|1K]]|A|$]]|$1|Q|3|R|5|P|7|1L|8|@]|9|@$G|1M|H|1N|1|1O]]|A|$]]|$1|S|3|T|5|P|7|1P|8|@]|9|@$G|1Q|H|1R|1|1S]]|A|$]]|$1|U|3|-4|5|F|7|1T|8|@]|9|@]|A|$]]|$1|V|3|-4|5|F|7|1U|8|@]|9|@]|A|$]]]|W|$X|$5|Y|Z|10|A|$11|12]]|13|$5|Y|Z|10|A|$11|14]]|15|$5|Y|Z|10|A|$11|16]]]]

<pre><code>var numAlpha = new Regex("(?&lt;NumOne&gt;[0-9]+)(?&lt;Operator&gt;[^0-9])(?&lt;NumTwo&gt;[0-9]+)");
var match = numAlpha.Match("121165468746*1132");
var nb1 = match.Groups["NumOne"].Value; // nb1 = 121165468746
var nb2 = match.Groups["NumTwo"].Value; // nb2 = 1132
var op = match.Groups["Operator"].Value; // op = *
</code></pre>

It looks like what you're trying to do is match some pair of integers separated by an operator. The above regex uses named groups <code>(?&lt;GroupName&gt; ... )</code>, and two simple regular expressions to achieve that. <code>[0-9]+</code> will match one or more digits, and <code>[^0-9]</code> will match any one non-digit character, which here is being assumed to be the operator.

If this isn't what you were looking for, leave a comment and I'll try to help you out. In the mean time, some reading material:

<ul>
<li><a href="http://www.regular-expressions.info/" rel="nofollow">Regular Expressions Page, with plenty of tutorials and references</a></li>
<li><a href="http://regexpal.com" rel="nofollow">Javascript Regular Expressions Tester with Syntax Highlighting</a></li>
<li><a href="http://gskinner.com/RegExr/" rel="nofollow">Java RegEx Tester. More powerful, fewer frills.</a></li>
</ul>

blocks|key|828023|text|这两个组分别称为n1和n2。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|828024|%5E(?<n1>\d%2B)[%5E\d]%2B?(?<n2>\d%2B)$|code-block|syntax|javascript|828025|entityMap^0|8|2|B|2|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

Try to use this pattern for your Regex: it assumes that there are at least two numbers with one or more digits, separated by one or more non-digit characters (in case the operator is not only one character). The groups are called <code>n1</code> and <code>n2</code>.

<pre><code>^(?&lt;n1&gt;\d+)[^\d]+?(?&lt;n2&gt;\d+)$
</code></pre>

blocks|key|179085|text|使用以下命令将数字与预定义的4个基本运算相匹配:乘、减、加、除。您可以根据需要在"op“表达式中添加更多运算符。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|179086|Regex+rg+=+new+Regex(@"(?<num1>[0-9]%2B)(?<op>[\*\-\%2B\\])(?<num2>[0-9]%2B)");|code-block|syntax|javascript|179087|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Use the following to match numbers with predefined 4 basic operations Multiply, Subtract, Add, Divide. You can add more operators to the "op" expressions as per your need.

<pre><code>Regex rg = new Regex(@"(?&lt;num1&gt;[0-9]+)(?&lt;op&gt;[\*\-\+\\])(?&lt;num2&gt;[0-9]+)");
</code></pre>

I'm programming a calculator in C# to begin with that. 
I will separate a string in two variables= Nb1 and Nb2. I looked on the web for examples and I found something : 

<pre><code>var numAlpha = new Regex("(?&lt;Alpha&gt;[a-zA-Z]*)(?&lt;Numeric&gt;[0-9]*)");
var match = numAlpha.Match("codename123");
var alpha = match.Groups["Alpha"].Value; // Alpha = codename
var num = match.Groups["Numeric"].Value; // Numeric = 123
</code></pre>

I fails to only adapt for the numbers : " 121165468746*1132" or "4586/6953" 
Nb1 =121165468746 || 4586
Nb2 =1132 || 6953

Can you help me ? I'm going crazy :-)

Regex regular expression

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

为此，我在C#中编写了一个计算器。我将在两个variables= Nb1和Nb2中分隔一个字符串。我在网上找了一些例子，发现了一些东西：var numAlpha = new Regex("(?<Alpha>[a-zA-Z]*)(?<Numeric>[0-9]*)");var match = numAlpha.Match...

问正则表达式
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问正则表达式EN