我试图把在我们的票务网站上的用户的实时视图。
目前,我在网站上有两个会话(会话列)。我当前的查询返回以下内容:
EVENTID EVENT Session SessionOpened SessionLength NumberofTix
1619 BB King 11 2013-01-28 09:34:16.300 -2 2
1622 BB King 12 2013-01-28 09:36:55.073 0 1
1622 BB King 12 2013-01-28 09:36:55.077 0 3但是,它应该看起来像这样:
EVENTID EVENT Session SessionOpened SessionLength NumberofTix
1619 BB King 11 2013-01-28 09:34:16.300 -2 2
1622 BB King 12 2013-01-28 09:36:55.073 0 4为什么会话12返回2行-1行包含1张票证,1行包含3张票证?
查询:
SELECT distinct set_eSRO_Event as EventID, shName as EventName, setSRO_UID as SRO_SessionID, setDateTime as SessionStarted,
DATEDIFF(mi, getDate(), setDateTime) as SessionTimer, Count(*) AS NumberofTickets FROM SessionTickets
INNER JOIN Shows on shCode = setShowCode
WHERE setStatus = 0
GROUP BY setsro_UID, shName, set_eSRO_Event, setDateTime发布于 2013-01-28 22:59:49
你的结果列和查询的别名不一致,所以很难说。我认为setDateTime是不同的(= SessionStarted或SessionOpened)。当你按setDatetime分组时,如果它们是不同的=>两行。
因此,向setDatetime添加一个MIN聚合函数(就像您“想要”的结果一样),并从GROUP BY中删除setDatetime
SELECT set_eSRO_Event as EventID,
shName as EventName,
setSRO_UID as SRO_SessionID,
MIN(setDateTime) as SessionStarted,
DATEDIFF(mi, getDate(), MIN(setDateTime)) as SessionTimer,
COUNT(*) AS NumberofTickets
FROM SessionTickets
INNER JOIN Shows on shCode = setShowCode
WHERE setStatus = 0
GROUP BY setsro_UID, shName, set_eSRO_Eventhttps://stackoverflow.com/questions/14564642
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