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社区首页 >问答首页 >MySQL count、left join、group by返回零行

MySQL count、left join、group by返回零行
EN

Stack Overflow用户
提问于 2013-01-27 23:55:52
回答 3查看 7.5K关注 0票数 4

在以下sql语句中:

代码语言:javascript
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 SELECT `keywords`.keyID, count(`keywords-occurencies`.keyID) as countOccurencies 
                    FROM `keywords-occurencies`  
                    LEFT JOIN `keywords` 
                    ON `keywords-occurencies`.keyID = `keywords`.keyID 
                    WHERE `keywords-occurencies`.`keyID` IN (1,2,3) AND date BETWEEN '2013/01/25' AND '2013/01/27'
                    GROUP BY `keywords`.`keyID`

如果keyID 3没有返回值,则不会将其计为0,也不会将其包括在结果集中,并显示如下结果

代码语言:javascript
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keyID countOccurencies
1       3
3       5

我想像这样显示零结果

代码语言:javascript
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keyID countOccurencies
1       3
2       0
3       5

用于测试的样本数据:

代码语言:javascript
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--
-- Table structure for table `keywords`
--

CREATE TABLE IF NOT EXISTS `keywords` (
  `keyID` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `keyName` varchar(40) NOT NULL,
  PRIMARY KEY (`keyID`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ;

--
-- Dumping data for table `keywords`
--

INSERT INTO `keywords` (`keyID`, `keyName`) VALUES
(1, 'testKey1'),
(2, 'testKey2');

-- --------------------------------------------------------

--
-- Table structure for table `keywords-occurencies`
--

CREATE TABLE IF NOT EXISTS `keywords-occurencies` (
  `occurencyID` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `keyID` int(10) unsigned NOT NULL,
  `date` date NOT NULL,
  PRIMARY KEY (`occurencyID`),
  KEY `keyID` (`keyID`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ;

--
-- Dumping data for table `keywords-occurencies`
--

INSERT INTO `keywords-occurencies` (`occurencyID`, `keyID`, `date`) VALUES
(1, 1, '2013-01-27'),
(2, 1, '2013-01-26');

--
-- Constraints for table `keywords-occurencies`
--
ALTER TABLE `keywords-occurencies`
  ADD CONSTRAINT `keywords@002doccurencies_ibfk_1` FOREIGN KEY (`keyID`) REFERENCES `keywords` (`keyID`) ON DELETE CASCADE ON UPDATE CASCADE;
EN

Stack Overflow用户

发布于 2015-05-19 15:38:32

将其更改为LEFT JOIN对我很有效:

代码语言:javascript
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SELECT k.keyID, count(ko.keyID) as countOccurencies 
FROM `keywords-occurencies` ko
      LEFT JOIN `keywords` k
      ON ko.keyID = k.keyID 
WHERE k.`keyID` IN (1,2,3) AND date BETWEEN '2013/01/25' AND '2013/01/27'
GROUP BY k.`keyID`
票数 0
EN
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/14549120

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