blocks|key|4842796|text|您可以在Perl脚本中将路径附加到path变量：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4842797|$ENV{PATH}+.=+':/home/user/dev/tools';|code-block|syntax|javascript|4842798|通常，该设置不能更改父进程的PATH变量，只能更改脚本本身及其子进程。|4842799|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

You can append the path to the PATH variable from within the Perl script:

<pre><code>$ENV{PATH} .= ':/home/user/dev/tools';
</code></pre>

As usually, the setting cannot change the PATH variable of the parent process, only the script itself and its children processes.

blocks|key|1492162|text|如果您的Python脚本有正确的shebang行(例如，#!第一行)指向python，那么您不需要执行system("python+/home/user/dev/tools/python.py")+-只要system("/home/user/dev/tools/python.py")就足够了。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1492163|这样你就不需要依赖Python搜索$PATH了。|1492164|然后，您可以更改您的$PATH：|1492165|local+$ENV{PATH}+=+$ENV{PATH}+?+"$ENV{PATH}:/home/user/dev/tools"+
++++++++++++++++++++++++++++++:+"/home/user/dev/tools";

system("python.py");|code-block|syntax|javascript|1492166|(确保将其本地化，以免影响程序中其他位置的路径)|1492167|entityMap^0|S|2|1F|1B|2U|14|0|H|5|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]|$9|X|A|Y|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|Z|8|@$9|10|A|11|B|C]]|D|@]|E|$]]|$1|H|3|I|5|6|7|12|8|@]|D|@]|E|$]]|$1|J|3|K|5|L|7|13|8|@]|D|@]|E|$M|N]]|$1|O|3|P|5|6|7|14|8|@]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|15|8|@]|D|@]|E|$]]]|R|$]]

If your Python scripts have correct shebang line (e.g. <code>#!</code> first line) pointing to python, you do NOT need to do <code>system("python /home/user/dev/tools/python.py")</code> - merely <code>system("/home/user/dev/tools/python.py")</code> is enough.

Then you don't need to rely on Python searching <code>$PATH</code>.

Then, you can then change your $PATH:

<pre><code>local $ENV{PATH} = $ENV{PATH} ? "$ENV{PATH}:/home/user/dev/tools" 
 : "/home/user/dev/tools";

system("python.py");
</code></pre>

(Make sure to localize this so as to not affect the PATH elsewhere in your program)

blocks|key|4842889|text|另一种可能适合也可能不适合您的需求的方法：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|4842890|在调用system之前的某个位置：|4842891|chdir+'/home/user/dev/tools'+or+die+"Couldn't+chdir+to+tools:+$!\n";|code-block|syntax|javascript|4842892|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

An alternate approach that may or may not fit your needs:

Somewhere before calling system:

<pre><code>chdir '/home/user/dev/tools' or die "Couldn't chdir to tools: $!\n";
</code></pre>

blocks|key|510014|text|关于你的更新，|type|unstyled|depth|inlineStyleRanges|entityRanges|data|510015|510016|在perl.pl中设置$ENV没有任何影响。$export+PATH=$PATH:/home/user/dev/tools并从shell+works运行$python.py。|blockquote|510017|510018|510019|那是胡说。如果可以，那么设置$ENV{PATH}并从Perl运行python.py也是如此。|offset|length|style|CODE|510020|local+$ENV{PATH}+=+"$ENV{PATH}:/home/user/dev/tools";
system("python.py");|code-block|syntax|javascript|510021|entityMap^0|0|0|0|0|0|E|A|W|9|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|V|8|@]|9|@]|A|$]]|$1|C|3|D|5|E|7|W|8|@]|9|@]|A|$]]|$1|F|3|-4|5|6|7|X|8|@]|9|@]|A|$]]|$1|G|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]|$1|H|3|I|5|6|7|Z|8|@$J|10|K|11|L|M]|$J|12|K|13|L|M]]|9|@]|A|$]]|$1|N|3|O|5|P|7|14|8|@]|9|@]|A|$Q|R]]|$1|S|3|-4|5|6|7|15|8|@]|9|@]|A|$]]]|T|$]]

Regarding your update,

<blockquote>
 Setting $ENV in perl.pl has no affect. $export PATH=$PATH:/home/user/dev/tools and running $python.py from shell works.
</blockquote>

That's not true. If that works, so does setting the <code>$ENV{PATH}</code> and running <code>python.py</code> from Perl.

<pre><code>local $ENV{PATH} = "$ENV{PATH}:/home/user/dev/tools";
system("python.py");
</code></pre>

I don't know how to google this right: I want to call an external tool in <code>Perl</code> - For non root installed modules I can add the directory to <code>@INC</code>. But this don't work for other binaries/executables. E.g. Perlfile is in <code>/home/user/dev/perl.pl</code>, Modules are in <code>/home/user/dev/modules/</code>, Pythonscript is in <code>/home/user/dev/tools/python.py</code>. Now I can <code>push @INC,'/home/user/dev/modules/'</code> to find all modules. For the pythonscript I need to use the whole path <code>system("python /home/user/dev/tools/python.py")</code>. Is there a possibility to search the tools directory automatically, without adding it to build PATH, so I only need to call <code>system("python python.py")</code>? Thx

Perl system call without path to executable, except using PATH variable

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我不知道如何用谷歌搜索:我想在Perl中调用一个外部工具--对于未安装根目录的模块，我可以将目录添加到@INC中。但这不适用于其他二进制文件/可执行文件。例如，Perlfile在/home/user/dev/perl.pl中，模块在/home/user/dev/modules/中，Pythonscript在/home/...

问不带可执行文件路径的Perl系统调用，使用path变量除外
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