问如何将单词列表按照最常用到最不常用的顺序排列？

EN

const fs = require('fs')
const split = require('split2')
const through = require('through2')

const words = {}

fs.createReadStream('words.txt')
  .pipe(split())
  .pipe(through(write, end))


function write (buf, enc, next) {
  const word = buf.toString()
  words[word] = ++words[word] || 1

  next()
}

function end () {
  Object.keys(words)
    .sort((a, b) => words[b] - words[a])
    .forEach(word => {
      console.log(`${word}: ${words[word]} times`)
    })
}

var letterArray = "asdf\njkasdf\nthe\nsadf".split('\n');

function count(letterArray) {

    let mapping = {};

    for (let i=0; i < letterArray.length; i++){
        if (mapping[letterArray[i]] !== undefined){ // if the letter already exists in the mapping increment it
            mapping[letterArray[i]] += 1;
        }else { //if the letter does not exist add it and initialize it
            mapping[letterArray[i]] = 1;
        }
    }

    return mapping;
}

console.log("count: ", count(letterArray));

import numpy as np
from sklearn.feature_extraction.text import CountVectorizer

def wordcount(data):
    cv = CountVectorizer(min_df=0, strip_accents="ascii", decode_error ="ignore")

    counts = cv.fit_transform([data]).toarray().ravel()
    words = np.array(cv.get_feature_names())

    counts = map(int, counts)

    words = [i.tolist() for i in words]
    words = [x.encode('UTF8') for x in words]

    unsorted_result = zip(words, counts)
    print sorted(unsorted_result,key=lambda x: x[1], reverse=True)