使用NSJSONSerializer iOS发布http JSON请求
使用NSJSONSerializer iOS发布http JSON请求
提问于 2013-02-19 23:34:19
下面是我的代码：
在我的.m
NSArray *keys = [NSArray arrayWithObjects:@"Training_Code", @"Training_Duration",@"Training_Startdate",@"Training_Enddate",@"Trainer_ID",@"Training_Location",@"Comments",@"Keyword",@"NumberofDays", nil];
NSArray *objects = [NSArray arrayWithObjects:@"Training_Code", @"Training_Duration",@"Training_Startdate",@"Training_Enddate",@"Trainer_ID",@"Training_Location",@"Comments",@"Keyword",@"NumberofDays", nil];
NSData *jsonData;
NSString *jsonString;
NSDictionary *jsonDictionary = [NSDictionary dictionaryWithObjects:objects forKeys:keys];
if([NSJSONSerialization isValidJSONObject:jsonDictionary])
{
jsonData = [NSJSONSerialization dataWithJSONObject:jsonDictionary options:0 error:nil];
jsonString = [[NSString alloc]initWithData:jsonData encoding:NSUTF8StringEncoding];
}
// Be sure to properly escape your url string.
NSURL *url1 = [NSURL URLWithString:@"http://xx.xx.xx.xxx/DeployiOSCalender/service1.asmx"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url1];
[request setHTTPMethod:@"POST"];
[request setHTTPBody: jsonData];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setValue:[NSString stringWithFormat:@"%d", [jsonData length]] forHTTPHeaderField:@"Content-Length"];
NSError *errorReturned = nil;
NSURLResponse *theResponse =[[NSURLResponse alloc]init];
NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&theResponse error:&errorReturned];
if (errorReturned) {
// Handle error.
}
else
{
NSError *jsonParsingError = nil;
NSArray *jsonArray = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableContainers|NSJSONReadingAllowFragments error:&jsonParsingError];
}这是将数据返回给我：
{
d = "[{\"Training_Code\":\"1234 \",\"Training_Duration\":\"2hrs \",\"Training_Startdate\":\"14/02/2013 15:00:00\",\"Training_Enddate\":\"14/02/2013 17:00:00\",\"Trainer_ID\":1,\"Training_Location\":\"B-Wing Training room-4\",\"Comments\":\"C# training\",\"Keyword\":\"C#1234\",\"NumberofDays\":1},{\"Training_Code\":\"4321 \",\"Training_Duration\":\"16 \",\"Training_Startdate\":\"17/02/2013 10:30:00\",\"Training_Enddate\":\"17/02/2013 17:30:00\",\"Trainer_ID\":2,\"Training_Location\":\"A-Wing Training Room-6\",\"Comments\":\"Objective-C\",\"Keyword\":\"Obj-C4321\",\"NumberofDays\":2}]";
}这不是正确的格式。我想让它变成这样：
[{"Training_Code":"1234 ","Training_Duration":"2hrs ","Training_Startdate":"14/02/2013 15:00:00","Training_Enddate":"14/02/2013 17:00:00","Trainer_ID":1,"Training_Location":"B-Wing Training room-4","Comments":"C# training","Keyword":"C#1234","NumberofDays":1},{"Training_Code":"4321 ","Training_Duration":"16 ","Training_Startdate":"17/02/2013 10:30:00","Training_Enddate":"17/02/2013 17:30:00","Trainer_ID":2,"Training_Location":"A-Wing Training Room-6","Comments":"Objective-C","Keyword":"Obj-C4321","NumberofDays":2}注意:我的web服务返回了正确的json格式。
我需要做哪些额外的事情来实现this.Please建议。
回答 2
Stack Overflow用户
回答已采纳
发布于 2013-02-21 01:55:30
您说您的web服务返回了正确的JSON，但显然不是。您应该与您的web服务开发人员交谈，找出他们返回格式错误的JSON的原因。简单地说，您从web服务返回的内容不能被解析为JSON--除非您进行一些字符串提取(ugh)。
考虑您的响应数据，更好地格式化：
{
d = "
[
{
\"Training_Code\":\"1234 \",
\"Training_Duration\":\"2hrs \",
\"Training_Startdate\":\"14/02/2013 15:00:00\",
\"Training_Enddate\":\"14/02/2013 17:00:00\",
\"Trainer_ID\":1,
\"Training_Location\":\"B-Wing Training room-4\",
\"Comments\":\"C# training\",
\"Keyword\":\"C#1234\",
\"NumberofDays\":1
},
{
\"Training_Code\":\"4321 \",
\"Training_Duration\":\"16 \",
\"Training_Startdate\":\"17/02/2013 10:30:00\",
\"Training_Enddate\":\"17/02/2013 17:30:00\",
\"Trainer_ID\":2,
\"Training_Location\":\"A-Wing Training Room-6\",
\"Comments\":\"Objective-C\",
\"Keyword\":\"Obj-C4321\",
\"NumberofDays\":2
}
]
";
}首先，将数据响应转换为字符串：
NSString *json = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];然后你需要把这个从顶部剥离：
{
d = "这是从底部开始的
";
}然后，您可以使用以下代码替换所有转义引号：
json = [json stringByReplacingOccurrencesOfString:@"\\\"" withString:@"\""];此时，您的字符串应该是可解析的JSON，如下所示：
[
{
"Training_Code":"1234 ",
"Training_Duration":"2hrs ",
"Training_Startdate":"14/02/2013 15:00:00",
"Training_Enddate":"14/02/2013 17:00:00",
"Trainer_ID":1,
"Training_Location":"B-Wing Training room-4",
"Comments":"C# training",
"Keyword":"C#1234",
"NumberofDays":1
},
{
"Training_Code":"4321 ",
"Training_Duration":"16 ",
"Training_Startdate":"17/02/2013 10:30:00",
"Training_Enddate":"17/02/2013 17:30:00",
"Trainer_ID":2,
"Training_Location":"A-Wing Training Room-6",
"Comments":"Objective-C",
"Keyword":"Obj-C4321",
"NumberofDays":2
}
]所以你可以这样做：
id object = [NSJSONSerialization JSONObjectWithData:[json dataUsingEncoding:NSUTF8StringEncoding] options:0 error:&error];现在，object应该将包含两条记录的数组保存为字典。
但是，如果是我，我会回到web服务开发人员那里，要求他们修复他们发送给您的响应。您不应该处理所有这些字符串提取的废话。
Stack Overflow用户
发布于 2013-02-19 23:56:32
Trainer_ID和NumberofDays是原始的。您无法按原样将then添加到NSArray中。您应该将它们封装到NSNumber中：
NSArray *objects = [NSArray arrayWithObjects:Training_Code, Training_Duration,Training_Startdate,Training_Enddate,[NSNumber numberWithInt:Trainer_ID],Training_Location,Comments,Keyword,[NSNumber numberWithInt:NumberofDays], nil];页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/14961239
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