blocks|key|709551|text|type|unstyled|depth|inlineStyleRanges|entityRanges|data|709552|如果它的电子表格读取为CSV，如果你可以|ordered-list-item|709553|，为什么使用正则表达式？jsut在/|offset|length|style|CODE|709554|上爆炸|709555|然后是这样的东西：|709556|$file+=+fopen('/path/to/file.csv',+'r');
//+skip+headers
fseek($file,+1);

while($row+=+fgetcsv($file))+{
+++$from+=+explode('/',+$row[0]);
+++$to+=+explode('/',+$row[1]);

+++foreach($from+as+$i+=>+$sender)+{
++++++$recipient+=+isset($to[$i])+?+$to[$i]+:+'undefined';
++++++echo+"$sender+->+$recipient";
+++}++
}|code-block|syntax|javascript|709557|entityMap^0|0|0|H|1|0|0|0|0^^$0|@$1|2|3|-4|4|5|6|U|7|@]|8|@]|9|$]]|$1|A|3|B|4|C|6|V|7|@]|8|@]|9|$]]|$1|D|3|E|4|C|6|W|7|@$F|X|G|Y|H|I]]|8|@]|9|$]]|$1|J|3|K|4|5|6|Z|7|@]|8|@]|9|$]]|$1|L|3|M|4|5|6|10|7|@]|8|@]|9|$]]|$1|N|3|O|4|P|6|11|7|@]|8|@]|9|$Q|R]]|$1|S|3|-4|4|5|6|12|7|@]|8|@]|9|$]]]|T|$]]

<ol>
<li>If its s spreadsheet read it as CSV if you can</li>
<li>why regex? jsut explode on <code>/</code></li>
</ol>

So then something like this:

<pre><code>$file = fopen('/path/to/file.csv', 'r');
// skip headers
fseek($file, 1);

while($row = fgetcsv($file)) {
 $from = explode('/', $row[0]);
 $to = explode('/', $row[1]);

 foreach($from as $i =&gt; $sender) {
 $recipient = isset($to[$i]) ? $to[$i] : 'undefined';
 echo "$sender -&gt; $recipient";
 } 
}
</code></pre>

blocks|key|1893159|text|您可以在$row2匹配项上使用嵌套的foreach和循环，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1893160|$row+=+"LAX/SAF/ORL";
$row2+=+"ORL/SFO";
$to_locations+=+explode('/',+$row);
$from_locations+=+explode('/',+$row2);
foreach+($to_locations+as+$to){
++foreach+($from_locations+as+$from)+{
++++echo+$to+.+"+->+"+.+$from+.+"<br+/>";
++}
}|code-block|syntax|javascript|1893161|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You could use a nested foreach and loop over the $row2 matches, like so:

<pre><code>$row = "LAX/SAF/ORL";
$row2 = "ORL/SFO";
$to_locations = explode('/', $row);
$from_locations = explode('/', $row2);
foreach ($to_locations as $to){
 foreach ($from_locations as $from) {
 echo $to . " -&gt; " . $from . "&lt;br /&gt;";
 }
}
</code></pre>

blocks|key|5244047|text|实际上你们已经很接近了。我会这样做：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5244048|$row+=+"LAX/SAF/ORL";
$row2+=+"ORL/SFO";
$from+=+explode('/',+$row);
$to+++=+explode('/',+$row2);

foreach+($from+as+$f){
++++foreach($to+as+$t)+{
++++++++echo+$f+.+"+->+"+.+$t+.+"<br+/>";
++++}
}|code-block|syntax|javascript|5244049|编辑:您可能想要添加对if+($f+==+$t)的检查，因为ORL+->+ORL没有真正的意义。:)|offset|length|style|CODE|5244050|entityMap^0|0|0|B|D|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

You're actually fairly close. I would do it as such:

<pre><code>$row = "LAX/SAF/ORL";
$row2 = "ORL/SFO";
$from = explode('/', $row);
$to = explode('/', $row2);

foreach ($from as $f){
 foreach($to as $t) {
 echo $f . " -&gt; " . $t . "&lt;br /&gt;";
 }
}
</code></pre>

EDIT: You may want to add a check for <code>if ($f == $t)</code>, because ORL -> ORL doesn't really make sense. :)

blocks|key|5244088|text|根据您所拥有的，尝试：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5244089|$row+=+"LAX/SAF/ORL";
$row2+=+"ORL/SFO";
$arow+=+explode("/",+$row);
$arow2+=+explode("/",+$row2);
foreach($arow+as+$p1)+{
++++foreach($arow2+as+$p2)+{
++++++++echo+"$p1+->+$p2+ ";
++++}
}|code-block|syntax|javascript|5244090|这将创建您正在查找的输出类型，因为您已经知道什么是$row和$row2+%5E%5E|offset|length|style|CODE|5244091|entityMap^0|0|0|P|4|U|5|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]|$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|V|8|@]|9|@]|A|$]]]|N|$]]

Based on what you have, try:

<pre><code>$row = "LAX/SAF/ORL";
$row2 = "ORL/SFO";
$arow = explode("/", $row);
$arow2 = explode("/", $row2);
foreach($arow as $p1) {
 foreach($arow2 as $p2) {
 echo "$p1 -&gt; $p2 &lt;br&gt;";
 }
}
</code></pre>

And that will create the type of output you are looking for since you already know what <code>$row</code> and <code>$row2</code> are ^^

blocks|key|1893270|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1893271|$row+=+"LAX/SAF/ORL";
$row2+=+"ORL/SFO";

$rows+=+array($row,+$row2);

foreach+($rows+as+$row)+{
++++preg_match_all('([A-Za-z]%2B)',+$row,+$matches);
++++foreach+($matches[0]+as+$location_to){
++++++++echo+$location_to+.+"+->+"+.+$row2+.+"<br+/>";+//currently+doesn't+loop+through+row2
++++}
}|code-block|syntax|javascript|1893272|基本上，您拥有的代码将对$rows数组中的每个元素执行。|offset|length|style|CODE|1893273|将来，如果有更多的行(即文件的每一行)，只需将它们添加到$rows数组中，代码就会遍历每一行。|1893274|entityMap^0|0|0|C|5|0|S|5|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|N|5|6|7|V|8|@$I|W|J|X|K|L]]|9|@]|A|$]]|$1|O|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|P|$]]

Try this:

<pre><code>$row = "LAX/SAF/ORL";
$row2 = "ORL/SFO";

$rows = array($row, $row2);

foreach ($rows as $row) {
 preg_match_all('([A-Za-z]+)', $row, $matches);
 foreach ($matches[0] as $location_to){
 echo $location_to . " -&gt; " . $row2 . "&lt;br /&gt;"; //currently doesn't loop through row2
 }
}
</code></pre>

Basically, the code you had will execute for each element in the <code>$rows</code> array.

In the future, if you have more rows (i.e., each line of a file), you just add them to the <code>$rows</code> array, and the code will loop through each row.

blocks|key|1893298|text|$row+=+"LAX/SAF/ORL";
$row2+=+"ORL/SFO";
$first_array+=+explode('/',+$row);
$second_array+=+explode('/',+$row2);
$result_array+=+array();
$assoc_array+=+array();
foreach($first_array+as+$value1)+{
++foreach($second_array+as+$value2)+{
++++$assoc_array[$value1]+=+$value2;
++++$result_array[]+=+$value1.'+->+'.$value2;
++}
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1893299|这将引导您拥有一个关联的数组，或者一个包含形式为LAX+->+ORL的字符串的数组|unstyled|1893300|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|J|8|@]|9|@]|A|$]]|$1|G|3|-4|5|F|7|K|8|@]|9|@]|A|$]]]|H|$]]

<pre><code>$row = "LAX/SAF/ORL";
$row2 = "ORL/SFO";
$first_array = explode('/', $row);
$second_array = explode('/', $row2);
$result_array = array();
$assoc_array = array();
foreach($first_array as $value1) {
 foreach($second_array as $value2) {
 $assoc_array[$value1] = $value2;
 $result_array[] = $value1.' -&gt; '.$value2;
 }
}
</code></pre>

And this will lead you to have either an associated array, if you wish that, or an array which will have strings in the form LAX -> ORL

I am looping through a spreadsheet which may have information like so:

<pre><code>To From
LAX/SAF/ORL ORL/SAF
LAX/DUB DUB/SAF
SAF/LON LON/BNE/SYD
</code></pre>

I need to loop through this info so I get something like so:

<pre><code>Result 1: Lax -&gt; Orl
Result 2: Lax -&gt; Saf
Result 3: Saf -&gt; Orl
Result 4: Saf -&gt; Saf
Result 5: Orl -&gt; Orl
Result 6: Orl -&gt; Saf
</code></pre>

Here is what I have so far:

<pre><code>$row = "LAX/SAF/ORL";
$row2 = "ORL/SFO";
preg_match_all('([A-Za-z]+)', $row, $matches);
foreach ($matches[0] as $location_to){
 echo $location_to . " -&gt; " . $row2 . "&lt;br /&gt;"; //currently doesn't loop through row2
}
</code></pre>

How can I do this but for both sets of data? I'm currently stuck how to kind of.. foreach twice like above to get the output I need.

Any help would be greatly appreciated (This needs to run through one loop as it is a row on a spreadsheet and has other assigned data to it).

It's basically a multi trip entry sort of thing.

Thanks

Tricky foreach loop... how to?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我正在遍历一个电子表格，其中可能包含如下信息：To                  FromLAX/SAF/ORL         ORL/SAFLAX/DUB             DUB/SAFSAF/LON             LON/BNE/SYD我需要遍历这些信息，这样我就可以得到如下内容：Resul...

问棘手的foreach循环...怎么做？
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