blocks|key|5674703|text|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5674704|会执行this.ActivateAction()吗？|blockquote|5674705|5674706|5674707|是。否则，该方法将不知道返回什么！|5674708|return语句首先计算表达式，然后返回该值。当然，在void方法的情况下，只有一个|5674709|return;|code-block|syntax|javascript|5674710|没什么好评估的。|5674711|有关更多详细信息，请参阅14.17+of+the+Java+Language+Specification一节。|offset|length|5674712|entityMap|0|LINK|mutability|MUTABLE|url|http://docs.oracle.com/javase/specs/jls/se7/html/jls-14.html#jls-14.17^0|0|0|0|0|0|0|0|0|C|14|0|0^^$0|@$1|2|3|-4|4|5|6|12|7|@]|8|@]|9|$]]|$1|A|3|B|4|C|6|13|7|@]|8|@]|9|$]]|$1|D|3|-4|4|5|6|14|7|@]|8|@]|9|$]]|$1|E|3|-4|4|5|6|15|7|@]|8|@]|9|$]]|$1|F|3|G|4|5|6|16|7|@]|8|@]|9|$]]|$1|H|3|I|4|5|6|17|7|@]|8|@]|9|$]]|$1|J|3|K|4|L|6|18|7|@]|8|@]|9|$M|N]]|$1|O|3|P|4|5|6|19|7|@]|8|@]|9|$]]|$1|Q|3|R|4|5|6|1A|7|@]|8|@$S|1B|T|1C|1|1D]]|9|$]]|$1|U|3|-4|4|5|6|1E|7|@]|8|@]|9|$]]]|V|$W|$4|X|Y|Z|9|$10|11]]]]

<blockquote>
 Will this.ActivateAction() be carried out? 
</blockquote>

Yes. Otherwise the method won't know what to return!

The return statement first evaluates the expression, then returns that value. Of course in the case of a void method with just a return statement of

<pre><code>return;
</code></pre>

there's nothing to evaluate.

See section <a href="http://docs.oracle.com/javase/specs/jls/se7/html/jls-14.html#jls-14.17" rel="nofollow">14.17 of the Java Language Specification</a> for more details.

blocks|key|925857|text|是，会被执行。它不是在您的return语句之后，而是来自该方法的return值也将是该方法的return值。|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|CODE|entityRanges|data|925858|entityMap^0|0|1|D|6|W|6|1A|6|0^^$0|@$1|2|3|4|5|6|7|I|8|@$9|J|A|K|B|C]|$9|L|A|M|B|D]|$9|N|A|O|B|D]|$9|P|A|Q|B|D]]|E|@]|F|$]]|$1|G|3|-4|5|6|7|R|8|@]|E|@]|F|$]]]|H|$]]

Yes, it will be executed. It is not after your <code>return</code> statement, rather the <code>return</code> value from that method, is going to be the <code>return</code> value of this method as well.

blocks|key|2322738|text|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2322739|会执行this.ActivateAction()吗？|blockquote|2322740|2322741|2322742|是。|2322743|return+this.ActivateAction();|code-block|syntax|javascript|2322744|等同于|2322745|boolean+b+=+this.ActivateAction();
return+b;|2322746|如果将执行返回语句后的方法，则为|2322747|2322748|2322749|2322750|this.ActivateAction()不在return语句之后，但是return语句的一部分。|offset|length|style|CODE|BOLD|2322751|entityMap^0|0|0|0|0|0|0|0|0|0|0|0|0|0|L|Z|E|0^^$0|@$1|2|3|-4|4|5|6|14|7|@]|8|@]|9|$]]|$1|A|3|B|4|C|6|15|7|@]|8|@]|9|$]]|$1|D|3|-4|4|5|6|16|7|@]|8|@]|9|$]]|$1|E|3|-4|4|5|6|17|7|@]|8|@]|9|$]]|$1|F|3|G|4|5|6|18|7|@]|8|@]|9|$]]|$1|H|3|I|4|J|6|19|7|@]|8|@]|9|$K|L]]|$1|M|3|N|4|5|6|1A|7|@]|8|@]|9|$]]|$1|O|3|P|4|J|6|1B|7|@]|8|@]|9|$K|L]]|$1|Q|3|R|4|5|6|1C|7|@]|8|@]|9|$]]|$1|S|3|-4|4|C|6|1D|7|@]|8|@]|9|$]]|$1|T|3|-4|4|5|6|1E|7|@]|8|@]|9|$]]|$1|U|3|-4|4|5|6|1F|7|@]|8|@]|9|$]]|$1|V|3|W|4|5|6|1G|7|@$X|1H|Y|1I|Z|10]|$X|1J|Y|1K|Z|11]]|8|@]|9|$]]|$1|12|3|-4|4|5|6|1L|7|@]|8|@]|9|$]]]|13|$]]

<blockquote>
 Will this.ActivateAction() be carried out?
</blockquote>

Yes. 

<pre><code>return this.ActivateAction();
</code></pre>

is equivalent to

<pre><code>boolean b = this.ActivateAction();
return b;
</code></pre>

<blockquote>
 if a method after a return statement will be carryed out 
</blockquote>

<code>this.ActivateAction()</code> is NOT after return statement but is part of return statement.

blocks|key|925877|text|是，将执行this.ActivateAction()并返回该方法的结果|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|925878|entityMap^0|5|L|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

Yes,<code>this.ActivateAction()</code> will be executed and answer of that method will be returned

blocks|key|925897|text|‘'return’实际上返回的是值，而不是方法。因此，方法的目的是处理并提供结果，只有在'+return‘之后才能返回值(value+=this.ActivateAction()的输出)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|925898|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

'return' actually returns value, not methods. So the purpose of method is to process and provide a result, only after that 'return' can return a value (value = output of this.ActivateAction())

blocks|key|925921|text|是，即使是recursive方法调用也会执行+this.ActivateAction()，并返回最后的结果。|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|CODE|entityRanges|data|925922|entityMap^0|0|M|5|9|N|L|0^^$0|@$1|2|3|4|5|6|7|I|8|@$9|J|A|K|B|C]|$9|L|A|M|B|D]|$9|N|A|O|B|D]]|E|@]|F|$]]|$1|G|3|-4|5|6|7|P|8|@]|E|@]|F|$]]]|H|$]]

Yes. <code>this.ActivateAction()</code> will be executed even if it is <code>recursive</code> method call and last result will be returned.

blocks|key|5674901|text|‘'this’是当前实例的引用|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5674902|所以当你写下|5674903|this.ActivateAction()|code-block|syntax|javascript|5674904|您正在使用当前实例调用该方法，因为您的对象不为空，因此将调用方法'ActivateAction‘。|5674905|调用之后，该方法将执行并根据其定义返回一些值。|5674906|因此，在它之前是否编写return并不重要|5674907|5674908|将始终使用当前实例，并调用“ActivateAction”方法并返回一些值。|5674909|现在，因为它返回了一些值|5674910|因此|5674911|return+this.ActivateAction()|5674912|只表示返回该值，这里的“return”没有特殊作用。|5674913|entityMap^0|0|0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|11|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|12|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|13|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|14|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|15|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|16|8|@]|9|@]|A|$]]|$1|O|3|E|5|F|7|17|8|@]|9|@]|A|$G|H]]|$1|P|3|Q|5|6|7|18|8|@]|9|@]|A|$]]|$1|R|3|S|5|6|7|19|8|@]|9|@]|A|$]]|$1|T|3|U|5|6|7|1A|8|@]|9|@]|A|$]]|$1|V|3|W|5|F|7|1B|8|@]|9|@]|A|$G|H]]|$1|X|3|Y|5|6|7|1C|8|@]|9|@]|A|$]]|$1|Z|3|-4|5|6|7|1D|8|@]|9|@]|A|$]]]|10|$]]

'this' is the reference to current instance

so when you write

<pre><code>this.ActivateAction()
</code></pre>

your are using the current instance to invoke the method , ans since your object is not null , thus the method 'ActivateAction' will be invoked.

after invocation the method executes and returns some value as per its definition .

so it doesn't matter whether you write return before it or not

<pre><code>this.ActivateAction()
</code></pre>

will always use the current instance and invoke the 'ActivateAction' method and return some value.

now since it returns some value

thus 

<pre><code>return this.ActivateAction()
</code></pre>

only means to return that value , 'return' here has no special role .

I am just confused if a method after a return statement will be carryed out or it is just see as a variable.
Example:

<pre><code>public boolean onSystemChecked(boolean dubug){
 if(this.isActivated()) {
 return this.ActivateAction();
 } else {
 if(debug) { 
 System.out.println("[Debug] System Off!");
 } 
 }
 return false;
}
</code></pre>

Will this.ActivateAction() be carried out? Thank you very much! :)

Do Java carry out method after a return statement

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我只是感到困惑，如果返回语句后的方法将被执行，或者它只是被视为一个变量。示例：public boolean onSystemChecked(boolean dubug){  if(this.isActivated()) {    return this.ActivateAction();  } else {    if...

问在返回语句后执行Java执行方法吗
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问在返回语句后执行Java执行方法吗EN