blocks|key|2385810|text|只要将赋值放在if之外即可。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2385811|x+=+if+some+condition
++some+value
elsif+another+condition
++a+different+value|code-block|syntax|javascript|2385812|或者您可以使用Hash。|2385813|x+=+dict[some+condition]|2385814|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Just put the assignment outside the if.

<pre><code>x = if some condition
 some value
elsif another condition
 a different value
</code></pre>

Or you could use a Hash.

<pre><code>x = dict[some condition]
</code></pre>

blocks|key|5738456|text|它不是一个模式，而是一个运算符。您所指的是三元运算符：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5738457|If+Condition+is+true+?+Then+value+X+:+Otherwise+value+Y|code-block|syntax|javascript|5738458|下面是一个示例：|5738459|speed+=+90
speed+>+55+?+puts("I+can't+drive+55!")+:+puts("I'm+a+careful+driver")|5738460|使用三元语句很简短，而且效果很好。|5738461|entityMap^0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|S|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

It's not a pattern, but an operator. The one you're referring to is the ternary operator:

<pre><code>If Condition is true ? Then value X : Otherwise value Y
</code></pre>

Here is an example:

<pre><code>speed = 90
speed &gt; 55 ? puts("I can't drive 55!") : puts("I'm a careful driver")
</code></pre>

Using the ternary statement is short, sweet, and does the job.

blocks|key|263404|text|x+=+some+condition+?+some+value+:+
++++another+condition+?+a+different+value+:+...|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|263405|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>x = some condition ? some value : 
 another condition ? a different value : ...
</code></pre>

blocks|key|5738576|text|条件语句也是一个表达式，因此，如果变量在每个条件中都相同，您可以做的第一件事是：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|5738577|x+=+if+cond1
++expr1
elsif+cond2
++expr2
....
end|code-block|syntax|javascript|5738578|如果条件都是单个表达式的所有状态，则可以使用case语句使其更简洁。|5738579|然而，下一个最明显的重构练习是将大的条件分离到一个方法中，该方法应该提供评估所有条件和表达式所需的最小数据。|5738580|例如。|5738581|#+Where+conditional+is+currently,+and+x+assigned,+assuming+the+conditionals
#+need+a+couple+of+variables+.+.+.
x+=+foo+param1,+param2

#+Elsewhere
private

def+foo+p1,+p2
++if+cond1
++++expr1
++elsif+cond2
++++expr2
++....
++end
end|5738582|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|T|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

A conditional statement is also an expression, so one of the first things you can do, if the variable is the same in each condition, is:

<pre><code>x = if cond1
 expr1
elsif cond2
 expr2
....
end
</code></pre>

If the conditions are all states of a single expression, you can make this even neater, using a case statement.

However, the next most obvious re-factoring exercise is to get the big conditional isolated into a method, which should be fed the bare minimum data required to evaluate all the conditions and expressions.

E.g. 

<pre><code># Where conditional is currently, and x assigned, assuming the conditionals
# need a couple of variables . . .
x = foo param1, param2

# Elsewhere
private

def foo p1, p2
 if cond1
 expr1
 elsif cond2
 expr2
 ....
 end
end
</code></pre>

blocks|key|263532|text|如果您想重构代码的清晰度和灵活性，可以考虑replacing+conditional+with+polymorphism重构。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|263533|您的问题中没有足够的细节来进一步提出建议，但这种重构将使您的代码库更具抵抗力。如果您收到一个新的需求，打破条件并修改它是不好的形式(更容易引入bug，更难做到)；最好是创建一个可以插入现有代码库的新对象。这种灵活性就是Open/Closed+Principle+(+SOLID缩写中的"O“)所描述的。|263534|entityMap|0|LINK|mutability|MUTABLE|url|http://refactoring.com/catalog/replaceConditionalWithPolymorphism.html|1|https://en.wikipedia.org/wiki/Open/closed_principle^0|L|13|0|0|31|L|1|0^^$0|@$1|2|3|4|5|6|7|P|8|@]|9|@$A|Q|B|R|1|S]]|C|$]]|$1|D|3|E|5|6|7|T|8|@]|9|@$A|U|B|V|1|W]]|C|$]]|$1|F|3|-4|5|6|7|X|8|@]|9|@]|C|$]]]|G|$H|$5|I|J|K|C|$L|M]]|N|$5|I|J|K|C|$L|O]]]]

If you want to refactor for code clarity and flexibility, consider the <a href="http://refactoring.com/catalog/replaceConditionalWithPolymorphism.html" rel="nofollow">replacing conditional with polymorphism</a> refactor. 

There's not enough detail in your question to go much further with recommendations, but this refactor will make your code base much more resistant to change. If you receive a new requirement, it's bad form to break open the conditional and modify it (more prone to introducing bugs, more difficult to do); it's preferable to create a new object that you can plug into the existing codebase. This flexibility what the <a href="https://en.wikipedia.org/wiki/Open/closed_principle" rel="nofollow">Open/Closed Principle</a> (the "O" in the SOLID acronym) describes.

I'm working on a project. Currently I have a fairly large conditional statement, that assigns a value to a variable based on some input parameters. So, I have something like this.

<pre><code>if some condition
 x = some value
elsif another condition
 x = a different value
 ...
</code></pre>

What's the best way to refactor this? I'm hoping that I might end up with something like

<pre><code>x = some value if some condition || another value if another condition
</code></pre>

Is there a pattern for this sort of thing?

Refactoring conditional variable assignment

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我在做一个项目。目前我有一个相当大的条件语句，它根据一些输入参数为变量赋值。所以，我有这样的东西。if some condition  x = some valueelsif another condition  x = a different value  ...重构的最好方法是什么？我希望我能以这样的方式结束x = some value if some condition || another

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