选择最大的奇数python
我正在尝试用Python编写一个简单的程序来计算x，y，z值中最大的奇数。如何让用户选择x，y和z的值呢？
因此，程序将询问x，y和z是什么，然后说"x，y，z是最大的奇数“，或者这些数字都是偶数。
到目前为止，我拥有的内容如下所示。这至少是一个良好的开始吗？
# This program exmamines variables x, y, and z
# and prints the largest odd number among them
if x%2 !== 0 and x > y and y > z:
print 'x is the largest odd among x, y, and z'
elif y%2 !== 0 and y > z and z > x:
print 'y is the largest odd among x, y, and z'
elif z%2 !== 0 and z > y and y > x:
print 'z is the largest odd among x, y, and z'
elif x%2 == 0 or y%2 == 0 or z%2 == 0:
print 'even'有了这个帖子，我现在有了：
# This program exmamines variables x, y, and z
# and prints the largest odd number among them
if x%2 !== 0:
if y%2 !== 0:
if z%2 !== 0:
if x > y and x > z: #x is the biggest odd
elif y > z and y > x: #y is the biggest odd
elif z > x and z > y: #z is the biggest odd
else: #z is even
if x > y: #x is the biggest odd
else: #y is the biggest odd
else: #y is even
if z%2 != 0: #z is odd
if x > z: #x is the biggest odd
else: #z is the biggest odd
else: #y,z are even and x is the biggest odd
else: #x is even
if y%2 != 0 and z%2 != 0; #y,z is odd
if y > z: #y is the biggest odd
else: #z is the biggest odd
else: #x and y is even
if z%2 != 0: #z is the biggest odd回答 28
Stack Overflow用户
发布于 2013-04-01 02:24:09
最好先对数字进行过滤，然后再对它们进行排序。
numbers = [x, y, z]
sorted_odd_nums = sorted((x for x in enumerate(numbers) if x[1]%2),
key = lambda x:x[1],
reverse=True)
if not sorted_odd_nums:
# all numbers were even and filtered out.
elif sorted_odd_nums[0][0] == 0:
# x is the biggest odd number
elif sorted_odd_nums[0][0] == 1:
# y is the biggest odd number
elif sorted_odd_nums[0][0] == 2:
# z is the biggest odd number它的用途：
enumerate(numbers)返回一系列(index, item)对。由于原始列表是[x, y, z]，所以即使在过滤和排序之后，我们仍然可以保持x，y，z的轨迹。
如果给定元组中的第二项不是偶数，则(x for x in enumerate(numbers) if x[1]%2)筛选上面的枚举。
sort( ... , key=lambda x:x[1], reverse=True)使用第二个索引项(即原始编号)的值按降序对筛选出的项进行排序。
用户输入
要从用户读取数据，最简单的方法是使用raw_input(py2) / input(py3k)。
number = int(raw_input('enter a number: '))仅使用if语句
你必须嵌套if语句。像这样：
if x%2: # x is odd
if y%2: # y is odd
if z%2: #z is odd
if x>y and x>z: #x is the biggest odd number
elif y>z and y>x: #y is the biggest odd number
elif z>x and z>y: #z is the biggest odd number
else: #z is even
if x>y: #x is the biggest odd number
else: #y is the biggest odd number
else: #y is even
if z%2: #z is odd
...Stack Overflow用户
发布于 2013-04-01 03:19:25
方法
避免使用if-stmts查找最大值。在max中使用python内置。使用生成器或filter仅查找奇数。
使用这样的内置更安全/更可靠，因为它更简单地组合它们，代码经过良好的测试，并且代码主要在C中执行(而不是多字节码指令)。
代码
def find_largest_odd(*args):
return max(arg for arg in args if arg & 1)或者：
def find_largest_odd(*args):
return max(filter(lambda x: x & 1, args))测试
>>> def find_largest_odd(*args):
... return max(arg for arg in args if arg & 1)
...
>>> print find_largest_odd(1, 3, 5, 7)
7
>>> print find_largest_odd(1, 2, 4, 6)
1和：
>>> def find_largest_odd(*args):
... return max(filter(lambda x: x & 1, args))
>>> print find_largest_odd(1, 3, 5, 7)
7
>>> print find_largest_odd(1, 2, 4, 6)
1如果您传递一个空序列或仅提供偶数，您将得到一个ValueError
>>> find_largest_odd(0)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 2, in find_largest_odd
ValueError: max() arg is an empty sequence参考文献
- filter
- max
- generators
Stack Overflow用户
发布于 2013-10-26 01:03:08
如果有人正在寻找使用条件语句的简单解决方案
x,y,z = 4,1,6
largest = None
if x%2:
largest = x
if y%2:
if y > largest:
largest = y
if z%2:
if z > largest:
largest = z
if largest:
print "largest number is" largest
else
print "there are no odd numbers"https://stackoverflow.com/questions/15732805
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