两个精灵之间的冲突- Python 3.5.2
两个精灵之间的冲突- Python 3.5.2
提问于 2016-10-20 06:47:00
我有一张ufo和导弹的图像。我试着把它弄到如果导弹击中ufo的地方，它们都会爆炸并消失，然后几分钟后，另一个ufo会重新出现，但碰撞代码不起作用。有人能给我解释一下如何让代码工作吗？
pygame.display.init()
pygame.font.init()
screen = pygame.display.set_mode((800, 600))
clock = pygame.time.Clock()
ufo = pygame.image.load("ufo.png")
rocket = pygame.image.load("rocket.png")
done = False
debug = False
fontObj = pygame.font.SysFont("Courier New", 20)
#Making my Empty Lists
missiles = [] #[x,y]
ufo_list = [] #[x,y,hspeed]
particle_list = []
#UFO Respawn Info
ufoRespawn = True
ufoHits = 0
ufoSpawnTimer = 0.0
ufoSpeed = 500.0
#MISSILE Info
launchX = 400
launchY = 550
missileSpeed = 100.0
missileDirection = 0
#creating the Starfield
myStars = [] # An (initially) empty list
for i in range(1000):
x = random.randint(0, 800)
y = random.randint(0, 600)
newStar = [x, y] # A 2-element list
myStars.append(newStar)
starSpeed = 100.0 # Rate of star movement (px / s)
starDirection = 0 # 0 = not moving, -1 = left, +1 = right
#input
while not done:
event = pygame.event.poll()
if event.type == pygame.QUIT:
done = True
keys = pygame.key.get_pressed()
if keys[pygame.K_ESCAPE]:
done = True
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_d:
debug = not debug
dt = clock.tick() /1000.0
#the missile range (making it disappear after it hits the top)
for missile in missiles:
missile[1] -= missileSpeed * dt
if missile[1] < 0: missiles.remove(missle)
#triangle following mouse position
mx, my = pygame.mouse.get_pos()
if mx > launchX:
launchX += .3
if mx < launchX:
launchX -= .3
#bullets firing when pressing with mouse
mbuttons = pygame.mouse.get_pressed()
if mbuttons [0]:
x = launchX
y = launchY
newMissiles = [x,y]
missiles.append(newMissiles)
#Creating the UFOs
ufoSpawnTimer -= dt
if ufoSpawnTimer <= 0:
if random.choice (("head", "tail")) == "head":
x = 0
hspeed = random.randint (10,50)
else:
x = 800
hspeed = random.randint (-50, -10)
y = random.randint (0,300)
new_ufo = [x,y,hspeed]
ufo_list.append(new_ufo)
ufoSpawnTimer = 5.0
#Moving the Starfield
for i in range(len(myStars)):
myStars[i][0] += starSpeed * dt * starDirection
if myStars[i][0] < 0: myStars[i][0] = 800
if myStars[i][0] > 800: myStars[i][0] = 0
screen.fill ((0,0,0))
#drawing the triangle a.k.a missle launcher :D
pygame.draw.polygon(screen, (255,255,255), [[launchX, launchY], [launchX + 10, launchY + 10], \
[launchX - 10, launchY + 10]], 3)
for missile in missiles:
x = int(missile[0])
y = int(missile[1])
screen.blit(rocket, (x,y))
#drawing the ufo
for v in ufo_list:
v[0] += v[2] * dt
screen.blit(ufo,(v[0],v[1]))
#Missle distance from UFO - NEED HELP ON THIS PORTION
#Hit Detection
missileDist = ((x - v[0]) ** 2 + (y - v[1]) ** 2) ** 0.5
if **????** :
ufoRespawn = True
ufoHits += 10
#drawing th starfield
for star in myStars:
x = int(star[0])
y = int(star[1])
pygame.draw.circle(screen, (255,255,255), (x,y), 2)
pygame.display.flip()
pygame.font.quit()
pygame.display.quit()回答 1
Stack Overflow用户
发布于 2016-10-20 07:41:38
有许多不同的方法来检测冲突，可能值得看看这样做的库，但到目前为止最简单的方法是使用pygame.sprite.spritecollide()。
但是在我展示如何使用这个函数之前，您需要知道什么是pygame.sprite.Group()和什么是sprite类。
基本上，什么是pygame.sprite.Group()，是一种跟踪和保存多个精灵的方法。在你的情况下，似乎为你的导弹建立一个导弹群将是最好的选择。
所以我会创建一个小组来保存你的导弹：missiles_group = pygame.sprite.Group()。您可以通过说missiles_group.add(<sprite instance name>)将导弹添加到组中。
关于精灵类，请看我对一个问题的回答。简而言之，sprite类是一种创建Sprite的模块化方法。与仅使用普通图像不同，sprite类将包含sprite的必要方法和属性。我将在下面的示例中使用sprite类，因此如果需要更多详细信息，请阅读上面链接的答案。
这样就不会有太多的细节，下面是如何将每个函数参数填充到上面的函数中。
sprite：这是将针对一组spritesgroup：进行测试的sprite，这是将用于测试sprite.dokill：的组，这是一个布尔值。如果设置为true，则每次sprite参数与group参数中的内容发生冲突时，将删除group参数中的对象。如果dokill参数设置为false，则visa反之亦然。这是该函数需要的另一个参数，但对于您要执行的操作，并不需要此参数。
结合上述信息，下面是一个示例。该示例创建了一个子画面和一个子画面列表。每次精灵与组中的精灵发生碰撞时，HIT都会显示在屏幕上：
import pygame #import the pygame module into the namespace <module>
WIDTH = 640 # define a constant width for our window
HEIGHT = 480 # define a constant height for our window
#create a pygame window, and
#initialize it with our WIDTH and HEIGHT constants
display = pygame.display.set_mode((WIDTH, HEIGHT))
clock = pygame.time.Clock() # create a game clock
class Sprite(pygame.sprite.Sprite):
def __init__(self):
pygame.sprite.Sprite.__init__(self)
self.image = pygame.Surface((20, 20))
self.image.fill((255, 0, 0))
self.rect = self.image.get_rect()
self.rect.x = WIDTH / 2
self.rect.y = HEIGHT / 2
self.vx = 0
self.vy = 0
def update(self):
self.vx = 0
self.vy = 0
key = pygame.key.get_pressed()
if key[pygame.K_LEFT]:
self.vx = -1
elif key[pygame.K_RIGHT]:
self.vx = 1
if key[pygame.K_UP]:
self.vy = -1
elif key[pygame.K_DOWN]:
self.vy = 1
self.rect.x += self.vx
self.rect.y += self.vy
# cretae a player sprite
player = Sprite()
# create a group to hold all of our sprites
sprites = pygame.sprite.Group()
# create a group to hold sprites we want to
# test collions against. These sprites will
# still be added to the sprites list
# but we need a seperate group to test for
# collisions against
collision_sprites = pygame.sprite.Group()
# add a sprite to out collison sprite group
# We also add the sprite to our sprites group
# that holds all sprites
tmp = Sprite()
tmp.update = lambda: None
sprites.add(tmp)
collision_sprites.add(tmp)
# add a player sprites to the player group
player.rect.x = 10
sprites.add(player)
running = True # our variable for controlling our game loop
while running:
for e in pygame.event.get(): # iterate ofver all the events pygame is tracking
clock.tick(60) # make our clock keep pour game at 60 FPS
if e.type == pygame.QUIT: # is the user trying to close the window?
running = False # if so break the loop
pygame.quit() # quit the pygame module
quit() # quit is for IDLE friendliness
sprites.update()
# here is where we test for collision
if pygame.sprite.spritecollide(player, collision_sprites, False):
print("HIT!")
display.fill((180, 180, 180)) # fill the pygame screen with white
sprites.draw(display)
pygame.display.flip() # update the screen如果我的例子很大，那么请慢慢来，仔细地一步一步来看。我试着添加尽可能多的好的评论。祝好运!
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/40142731
复制相关文章
相似问题
腾讯云开发者
