blocks|key|1278877|text|编辑：如果你不知道你有多少个 ，你可以这样做：|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|CODE|entityRanges|data|1278878|1278879|使用 拆分字符串并删除空条目。|ordered-list-item|1278880|使用单个your连接字符串|1278881|1278882|代码如下：|1278883|string+yourString+=+"choose+to+still+go+on+the+trip.+ \r\nNote+that+when+booking";

var+temp+=+
++++yourString.Split(new+string[]+{+" "+},+StringSplitOptions.RemoveEmptyEntries)
+++++++++++++++.Where(i+=>+i.Replace("+",+string.Empty).Length+>+0);

string+result+=+string.Join(" ",+temp);|code-block|syntax|javascript|1278884|entityMap^0|0|3|E|4|0|0|2|4|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|D]]|E|@]|F|$]]|$1|G|3|-4|5|6|7|11|8|@]|E|@]|F|$]]|$1|H|3|I|5|J|7|12|8|@$9|13|A|14|B|D]]|E|@]|F|$]]|$1|K|3|L|5|J|7|15|8|@]|E|@]|F|$]]|$1|M|3|-4|5|6|7|16|8|@]|E|@]|F|$]]|$1|N|3|O|5|6|7|17|8|@]|E|@]|F|$]]|$1|P|3|Q|5|R|7|18|8|@]|E|@]|F|$S|T]]|$1|U|3|-4|5|6|7|19|8|@]|E|@]|F|$]]]|V|$]]

EDIT: If you don't know how many <code>&lt;br&gt;</code> you have, you can do this:

<ol>
<li>Split your string with <code>&lt;br&gt;</code> and remove empty entries.</li>
<li>Join the string with single <code>&lt;br&gt;</code></li>
</ol>

Here is the code:

<pre><code>string yourString = "choose to still go on the trip. &lt;br&gt;&lt;br&gt;\r\nNote that when booking";

var temp = 
 yourString.Split(new string[] { "&lt;br&gt;" }, StringSplitOptions.RemoveEmptyEntries)
 .Where(i =&gt; i.Replace(" ", string.Empty).Length &gt; 0);

string result = string.Join("&lt;br&gt;", temp);
</code></pre>

blocks|key|3027971|text|就像马丁·伊登所说的：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3027972|while+(text.Contains(" "))+
{+
++++text+=+text.Replace(" ",+" ");+
}++++|code-block|syntax|javascript|3027973|或|3027974|string+newString+=+oldString.Replace(" ",+" ");
newString+=+newString.Replace(" ",+" ");|3027975|在增加 的情况下执行多行这样的操作|offset|length|style|CODE|3027976|entityMap^0|0|0|0|0|3|4|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|W|8|@$M|X|N|Y|O|P]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|9|@]|A|$]]]|R|$]]

like Martin Eden susposed:

<pre><code>while (text.Contains("&lt;br&gt;&lt;br&gt;")) 
{ 
 text = text.Replace("&lt;br&gt;&lt;br&gt;", "&lt;br&gt;"); 
} 
</code></pre>

or

<pre><code>string newString = oldString.Replace("&lt;br&gt;&lt;br&gt;&lt;br&gt;", "&lt;br&gt;");
newString = newString.Replace("&lt;br&gt;&lt;br&gt;", "&lt;br&gt;");
</code></pre>

do multiple such lines with increasing <code>&lt;br&gt;</code>

blocks|key|904047|text|如果您需要考虑标签之间有空格的情况，请尝试以下regex：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|904048|myInputStr+=+Regex.Replace(myInputStr,
++++@"([\b\s]*<[\b\s]*[bB][rR][\s]*/?[\b\s]*>){2,}",
++++" ",+RegexOptions.Multiline);|code-block|syntax|javascript|904049|此正则表达式将用单个实例替换2个或更多个 标记实例，而不考虑标记的形式(间距、大小写、自闭合等)。|offset|length|style|CODE|904050|entityMap^0|0|0|K|4|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

If you need to account for the case where there is whitespace between the tags, try the following regex:

<pre><code>myInputStr = Regex.Replace(myInputStr,
 @"([\b\s]*&lt;[\b\s]*[bB][rR][\s]*/?[\b\s]*&gt;){2,}",
 "&lt;br&gt;", RegexOptions.Multiline);
</code></pre>

This regex will replace 2 or more instances of <code>&lt;br&gt;</code> tags with a single instance, regardless of the formation of the tag (spacing, casing, self-closing etc.).

blocks|key|133902|text|这可以用另一种(更安全的)方式来完成，使用HTML+Agility+Pack+(开源项目http://html-agility-pack.net)。|type|unstyled|depth|inlineStyleRanges|offset|length|style|BOLD|entityRanges|data|133903|它考虑了 、 、<br+/>的各种表示法，而无需担心。这意味着您可以专注于实际任务:替换重复项。|CODE|133904|参见Remove+chain+of+duplicate+elements+with+HTML+Agility+Pack，它解释了一种如何替换重复项的方法。|133905|entityMap|0|LINK|mutability|MUTABLE|url|http://html-agility-pack.net/|1|https://stackoverflow.com/questions/11307158/remove-chain-of-duplicate-elements-with-html-agility-pack^0|L|H|18|S|0|0|4|4|9|5|F|6|0|2|1L|1|0^^$0|@$1|2|3|4|5|6|7|U|8|@$9|V|A|W|B|C]]|D|@$9|X|A|Y|1|Z]]|E|$]]|$1|F|3|G|5|6|7|10|8|@$9|11|A|12|B|H]|$9|13|A|14|B|H]|$9|15|A|16|B|H]]|D|@]|E|$]]|$1|I|3|J|5|6|7|17|8|@]|D|@$9|18|A|19|1|1A]]|E|$]]|$1|K|3|-4|5|6|7|1B|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]|S|$5|N|O|P|E|$Q|T]]]]

This can be done in another (safer) way, using HTML Agility Pack (open source project <a href="http://html-agility-pack.net" rel="nofollow noreferrer">http://html-agility-pack.net</a>). 

It takes into account the various notations <code>&lt;br&gt;</code>, <code>&lt;br/&gt;</code>, <code>&lt;br /&gt;</code> without you having to worry about it. This means you can focus on the actual task: replacing duplicates.

See <a href="https://stackoverflow.com/questions/11307158/remove-chain-of-duplicate-elements-with-html-agility-pack">Remove chain of duplicate elements with HTML Agility Pack</a>, it explains an approach on how to replace duplicates.

blocks|key|1278956|text|Regex.Replace(input,+@"(<br\s*/{0,1}>\s*(</\s*br>)*){2,}",+" ",+
++++RegexOptions.CultureInvariant+%7C+
++++RegexOptions.IgnoreCase+%7C
++++RegexOptions.Multiline);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1278957|将任何两个或两个以上出现的 、 或 替换为单个 。|unstyled|offset|length|style|CODE|1278958|这会将空格考虑在内。<br++>将与<br+/>或<br+>++</+br>一样匹配。|1278959|如果事先删除了不需要的"\r\n“，则可以省略RegexOptions.Multiline。|1278960|entityMap^0|0|D|4|I|5|O|9|12|4|0|A|6|I|6|P|D|0|N|M|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|R|8|@$G|S|H|T|I|J]|$G|U|H|V|I|J]|$G|W|H|X|I|J]|$G|Y|H|Z|I|J]]|9|@]|A|$]]|$1|K|3|L|5|F|7|10|8|@$G|11|H|12|I|J]|$G|13|H|14|I|J]|$G|15|H|16|I|J]]|9|@]|A|$]]|$1|M|3|N|5|F|7|17|8|@$G|18|H|19|I|J]]|9|@]|A|$]]|$1|O|3|-4|5|F|7|1A|8|@]|9|@]|A|$]]]|P|$]]

<pre><code>Regex.Replace(input, @"(&lt;br\s*/{0,1}&gt;\s*(&lt;/\s*br&gt;)*){2,}", "&lt;br&gt;", 
 RegexOptions.CultureInvariant | 
 RegexOptions.IgnoreCase |
 RegexOptions.Multiline);
</code></pre>

Replaces any two or more occurences of <code>&lt;br&gt;</code> or <code>&lt;br/&gt;</code> or <code>&lt;br&gt;&lt;/br&gt;</code> with a single <code>&lt;br&gt;</code>.

This takes whitespaces into account. <code>&lt;br &gt;</code> would match aswell as <code>&lt;br /&gt;</code> or <code>&lt;br &gt; &lt;/ br&gt;</code>.

If you remove the unwanted "\r\n" beforehand you can omit <code>RegexOptions.Multiline</code>.

I have following string regex 

<pre><code>"choose to still go on the trip. &lt;br&gt;&lt;br&gt;\r\nNote that when booking"
</code></pre>

After converting it with regex I need to replace <code>&lt;br&gt;</code> tags with only one <code>&lt;br&gt;</code> so string would be like this

<pre><code>"choose to still go on the trip. &lt;br&gt;Note that when booking"
</code></pre>

Remove consecutive from string using regex c#

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我有以下字符串正则表达式"choose to still go on the trip. \r\nNote that when booking"在使用正则表达式转换后，我只需要用一个 替换 标记，因此字符串将如下所示"choose to still go on the trip. N...

问使用正则表达式c#从字符串中删除连续的<br>
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问使用正则表达式c#从字符串中删除连续的<br>EN