blocks|key|883078|text|我建议使用XDocument+(基于父节点的NB特定过滤等被省略)：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|883079|var+document+=+XDocument.Load(path);
var+nodes+=+document.Descendents().Where(e+=>+e.Name.LocalName.StartsWith("Node"));|code-block|syntax|javascript|883080|包含父元素过滤的更新|offset|length|style|BOLD|883081|var+nodes+=+document.Descendents()
++++++++++++++++++++.Where(e+=>+e.Atrributes().Any(a+=>+a.Name.localName+==+"Name"+&&+a.Value+==+"AAA"))
++++++++++++++++++++.SelectMany(e+=>+e.Descendents().Where(e+=>+e.Name.LocalName.StartsWith("Node"));
var+values+=+nodes.Select(n+=>+n.Value).ToList();+//+This+will+be+a+list+containing+"hello",+"john,+"hi",+"marry"|883082|entityMap^0|0|0|8|2|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@$I|T|J|U|K|L]]|9|@]|A|$]]|$1|M|3|N|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

I'd recommend using an XDocument (NB specific filtering based on parent nodes etc omitted):

<pre><code>var document = XDocument.Load(path);
var nodes = document.Descendents().Where(e =&gt; e.Name.LocalName.StartsWith("Node"));
</code></pre>

Update to include filtering of parent element

<pre><code>var nodes = document.Descendents()
 .Where(e =&gt; e.Atrributes().Any(a =&gt; a.Name.localName == "Name" &amp;&amp; a.Value == "AAA"))
 .SelectMany(e =&gt; e.Descendents().Where(e =&gt; e.Name.LocalName.StartsWith("Node"));
var values = nodes.Select(n =&gt; n.Value).ToList(); // This will be a list containing "hello", "john, "hi", "marry"
</code></pre>

blocks|key|1268421|text|如果您曾经使用过linq-to-entities或linq-to-sql，那么您可以使用linq-to-xml。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1268422|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/bb387098.aspx^0|18|B|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@$A|M|B|N|1|O]]|C|$]]|$1|D|3|-4|5|6|7|P|8|@]|9|@]|C|$]]]|E|$F|$5|G|H|I|C|$J|K]]]]

If you ever used linq-to-entities or linq-to-sql, there is a <a href="http://msdn.microsoft.com/en-us/library/bb387098.aspx" rel="nofollow">linq-to-xml</a> you can use.

blocks|key|3007319|text|假设你有一个XmlDocument，你可以像这样使用XPath：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3007320|XmlNode+node+=+doc.SelectSingleNode("//Segment[@Name='AAA']");|code-block|syntax|javascript|3007321|来获取Segment节点，然后在循环中迭代它的所有子节点。|3007322|entityMap^0|6|B|0|0|3|7|0^^$0|@$1|2|3|4|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|M|3|-4|5|6|7|V|8|@]|D|@]|E|$]]]|N|$]]

Assuming you have an <code>XmlDocument</code> you can use XPath like:

<pre><code>XmlNode node = doc.SelectSingleNode("//Segment[@Name='AAA']");
</code></pre>

to get the <code>Segment</code> node and then iterate all its children in a loop.

blocks|key|124729|text|试试这个：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|124730|System.Xml.Linq.XDocument+doc+=+XDocument.Load(your+file);

var+nodes+=+
+++++doc.Element("Loop").Element("Loop").Elements("Segment")
++++++++++++++++.Where(input+=>+(string)input.Attribute("Name")+==+"AAA")
++++++++++++++++.Select(input+=>+input.Elements()).ToList();|code-block|syntax|javascript|124731|然后：|124732|List<string>+result+=+new+List<string>();

foreach+(List<XElement>+item+in+nodes)
{
++++result.AddRange(item.Select(i+=>+i.Value));
}|124733|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Try this:

<pre><code>System.Xml.Linq.XDocument doc = XDocument.Load(your file);

var nodes = 
 doc.Element("Loop").Element("Loop").Elements("Segment")
 .Where(input =&gt; (string)input.Attribute("Name") == "AAA")
 .Select(input =&gt; input.Elements()).ToList();
</code></pre>

Then:

<pre><code>List&lt;string&gt; result = new List&lt;string&gt;();

foreach (List&lt;XElement&gt; item in nodes)
{
 result.AddRange(item.Select(i =&gt; i.Value));
}
</code></pre>

blocks|key|3007344|text|您可以使用XmlDocument将其作为对象加载，然后使用XPath查询所需的特定节点。您的xpath查询(我现在无法对其进行测试)可能如下所示。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|3007345|XmlNodeList+xNodes+=+xmlDocument.SelectNodes("//Segment[@Name+=+'AAA']");|code-block|syntax|javascript|3007346|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-ca/library/system.xml.xmldocument.aspx|1|http://msdn.microsoft.com/en-us/library/ms256086.aspx^0|5|B|0|T|5|1|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@$A|T|B|U|1|V]|$A|W|B|X|1|Y]]|C|$]]|$1|D|3|E|5|F|7|Z|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|10|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]|Q|$5|L|M|N|C|$O|R]]]]

You could use <a href="http://msdn.microsoft.com/en-ca/library/system.xml.xmldocument.aspx" rel="noreferrer">XmlDocument</a> to load your xml as an object and then query the specific nodes you want using <a href="http://msdn.microsoft.com/en-us/library/ms256086.aspx" rel="noreferrer">XPath</a>. Your xpath query (which I can't test right now) would probably look like this. 

<pre><code>XmlNodeList xNodes = xmlDocument.SelectNodes("//Segment[@Name = 'AAA']");
</code></pre>

blocks|key|1268441|text|你可以试试这个吗？|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1268442|XDocument+xmlFile+=+XDocument.Load("myFile.xml");
foreach+(var+nodeSegment+in+xmlFile.Descendants("Loop"))
{
+++foreach+(var+nodes+in+nodeSegment.Descendants().Where(e+=>+e.Name.LocalName.StartsWith("Node")))
+++{

+++}
}|code-block|syntax|javascript|1268443|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Do you can try this ?

<pre><code>XDocument xmlFile = XDocument.Load("myFile.xml");
foreach (var nodeSegment in xmlFile.Descendants("Loop"))
{
 foreach (var nodes in nodeSegment.Descendants().Where(e =&gt; e.Name.LocalName.StartsWith("Node")))
 {

 }
}
</code></pre>

blocks|key|883216|text|您可以使用XmlDocument和XPath：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|883217|XmlDocument+doc+=+new+XmlDocument();
doc.Load(xml);
foreach(XmlNode+node+in+doc.SelectNodes("//Segment[@Name='AAA']/node()"))
{
++++string+name+=+node.Name;
++++string+value+=+node.innerText;
++++//+...
}|code-block|syntax|javascript|883218|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

You could use XmlDocument and XPath:

<pre><code>XmlDocument doc = new XmlDocument();
doc.Load(xml);
foreach(XmlNode node in doc.SelectNodes("//Segment[@Name='AAA']/node()"))
{
 string name = node.Name;
 string value = node.innerText;
 // ...
}
</code></pre>

blocks|key|3007375|text|我为我的问题找到了一个简单的解决方案|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3007376|XmlNodeList+xnList+=+doc.SelectNodes("/Loop/Loop/Segment[@Name='AAA']");
++++++++++foreach+(XmlNode+xn+in+xnList)
++++++++++{
++++++++++++++if+(xn.HasChildNodes)
++++++++++++++{
++++++++++++++++++foreach+(XmlNode+item+in+xn.ChildNodes)
++++++++++++++++++{
++++++++++++++++++++++Console.WriteLine(item.InnerText);
++++++++++++++++++}
++++++++++++++}++
++++++++++}|code-block|syntax|javascript|3007377|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I found a simple solution for my problem

<pre><code>XmlNodeList xnList = doc.SelectNodes("/Loop/Loop/Segment[@Name='AAA']");
 foreach (XmlNode xn in xnList)
 {
 if (xn.HasChildNodes)
 {
 foreach (XmlNode item in xn.ChildNodes)
 {
 Console.WriteLine(item.InnerText);
 }
 } 
 }
</code></pre>

blocks|key|3007383|text|试试看..|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3007384|List<string>+nodeDetails+=+new+List<string>();

+++++++var+nodes+=+from+n+in+XDocument.Load(@"D:\pfXml.xml")
++++++++++++++++++++++++++++++++++++++++++++++.Element("Loop")
++++++++++++++++++++++++++++++++++++++++++++++.Element("loop")
++++++++++++++++++++++++++++++++++++++++++++++.Elements("Segment")
++++++++++++++++++++++++++++++++++++++where+(string)n.Attribute("Name")+==+"AAAA"
++++++++++++++++++++++++++++++++++++++select+new
++++++++++++++++++++++++++++++++++++++{
++++++++++++++++++++++++++++++++++++++++++n1+=+n.Element("Node1").Value,
++++++++++++++++++++++++++++++++++++++++++n2+=+n.Element("Node2").Value,
++++++++++++++++++++++++++++++++++++++++++n3+=+n.Element("Node3").Value,
++++++++++++++++++++++++++++++++++++++++++n4+=+n.Element("Node4").Value
++++++++++++++++++++++++++++++++++++++};
++++++++foreach+(var+node+in+nodes)
++++++++{
++++++++++++nodeDetails.Add(node.n1);
++++++++++++nodeDetails.Add(node.n2);
++++++++++++nodeDetails.Add(node.n3);
++++++++++++nodeDetails.Add(node.n4);
++++++++}|code-block|syntax|javascript|3007385|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Try this out..

<pre><code>List&lt;string&gt; nodeDetails = new List&lt;string&gt;();

 var nodes = from n in XDocument.Load(@"D:\pfXml.xml")
 .Element("Loop")
 .Element("loop")
 .Elements("Segment")
 where (string)n.Attribute("Name") == "AAAA"
 select new
 {
 n1 = n.Element("Node1").Value,
 n2 = n.Element("Node2").Value,
 n3 = n.Element("Node3").Value,
 n4 = n.Element("Node4").Value
 };
 foreach (var node in nodes)
 {
 nodeDetails.Add(node.n1);
 nodeDetails.Add(node.n2);
 nodeDetails.Add(node.n3);
 nodeDetails.Add(node.n4);
 }
</code></pre>

I have following XML:

<pre><code>&lt;Loop Name="MasterData"&gt;
 &lt;Loop Name="SlaveData"&gt;
 &lt;Segment Name="AAA"&gt;
 &lt;Node1&gt;hello&lt;/Node1&gt;
 &lt;Node2&gt;john&lt;/Node2&gt;
 &lt;Node3&gt;hi&lt;/Node3&gt;
 &lt;Node4&gt;marry&lt;/Node4&gt;
 &lt;/Segment&gt;
 &lt;Segment Name="BBB"&gt;
 &lt;Node1&gt;00&lt;/Node1&gt;
 &lt;Node2&gt; &lt;/Node2&gt;
 &lt;Node3&gt;00&lt;/Node3&gt;
 &lt;Node4&gt; &lt;/Node4&gt;
 &lt;/Segment&gt; 
 &lt;/Loop&gt;
&lt;/Loop&gt;
</code></pre>

I have to read value of each Node i.e, Node1, Node2, Node3, Node4 which are under Segment node whose attribute ie <code>Name = "AAA"</code>. How can I do this. I am referring following link from stackoverflow but thats not working for me.

<a href="https://stackoverflow.com/questions/1600065/how-to-read-attribute-value-from-xmlnode-in-c">How to read attribute value from XmlNode in C#?</a>

I need output like this

Lets I have four sting variables <code>strNode1, strNode2, strNode3, strNode4</code>. I want to store values in above four variables like following

<pre><code>strNode1 = "hello"
strNode2 = "john"
strNode3 = "hi"
strNode4 = "marry"
</code></pre>

How to read a particular node from xml in C#?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

我有以下XML：<Loop Name="MasterData"> <Loop Name="SlaveData"> <Segment Name="AAA"> <Node1>hello</Node1> <Node2>john</Node2> <Node3>hi</Node3> ...

问如何在C#中读取xml中的特定节点？
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问如何在C#中读取xml中的特定节点？EN