blocks|key|3155400|text|您不能使用strtotime，因为它会创建一个UTC时间戳，从而删除时区信息。相反，只需使用DateTime|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3155401|$date+=+new+DateTime('30-Mar-2013+America/Los_Angeles');
echo+$date->format('I');
#+1

$date+=+new+DateTime('31-Mar-2013+America/Los_Angeles');
echo+$date->format('I');
#+1

$date+=+new+DateTime('09-Mar-2013+America/Los_Angeles');
echo+$date->format('I');
#+0

$date+=+new+DateTime('10-Mar-2013+America/Los_Angeles');
echo+$date->format('I');
#+0|code-block|syntax|javascript|3155402|注意到最后一个的DST仍然是0吗？这是因为转换发生在凌晨2:00：|3155403|$date+=+new+DateTime('10-Mar-2013+01:00+America/Los_Angeles');
echo+$date->format('I');
#+0

$date+=+new+DateTime('10-Mar-2013+02:00+America/Los_Angeles');
echo+$date->format('I');
#+1|3155404|这是一个“向前跳跃”的转换，时钟从2:00跳到3:00。|3155405|注意回退转换过程中的多义性，此时时钟会从2:00跳回到1:00|3155406|$date+=+new+DateTime('3-Nov-2013+01:00+America/Los_Angeles');
echo+$date->format('I');
#+1|3155407|有两个1:00的AM，这是第一个。它是模棱两可的，因为我们可能指的是第二个，但没有表示出来。|3155408|有人会认为PHP会允许以下两种情况之一：|3155409|new+DateTime('3-Nov-2013+01:00+-0700+America/Los_Angeles')++#PDT
new+DateTime('3-Nov-2013+01:00+-0800+America/Los_Angeles')++#PST|3155410|但当我测试时，这些似乎不起作用。我还尝试了ISO格式的日期。有人知道如何正确区分PHP中的多义值吗？如果是这样，请在评论中编辑或更新。谢谢。|3155411|entityMap^0|5|9|1A|8|0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|14|8|@$9|15|A|16|B|C]|$9|17|A|18|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|19|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|1A|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|1B|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|1C|8|@]|D|@]|E|$]]|$1|Q|3|R|5|6|7|1D|8|@]|D|@]|E|$]]|$1|S|3|T|5|H|7|1E|8|@]|D|@]|E|$I|J]]|$1|U|3|V|5|6|7|1F|8|@]|D|@]|E|$]]|$1|W|3|X|5|6|7|1G|8|@]|D|@]|E|$]]|$1|Y|3|Z|5|H|7|1H|8|@]|D|@]|E|$I|J]]|$1|10|3|11|5|6|7|1I|8|@]|D|@]|E|$]]|$1|12|3|-4|5|6|7|1J|8|@]|D|@]|E|$]]]|13|$]]

You can't use <code>strtotime</code> because it creates a UTC timestamp, which removes the timezone information. Instead, just use <code>DateTime</code>

<pre><code>$date = new DateTime('30-Mar-2013 America/Los_Angeles');
echo $date-&gt;format('I');
# 1

$date = new DateTime('31-Mar-2013 America/Los_Angeles');
echo $date-&gt;format('I');
# 1

$date = new DateTime('09-Mar-2013 America/Los_Angeles');
echo $date-&gt;format('I');
# 0

$date = new DateTime('10-Mar-2013 America/Los_Angeles');
echo $date-&gt;format('I');
# 0
</code></pre>

Notice that the DST is still 0 on that last one? That's because the transition happens at 2:00 AM:

<pre><code>$date = new DateTime('10-Mar-2013 01:00 America/Los_Angeles');
echo $date-&gt;format('I');
# 0

$date = new DateTime('10-Mar-2013 02:00 America/Los_Angeles');
echo $date-&gt;format('I');
# 1
</code></pre>

This is a "spring-forward" transition, where the clock jumps from 2:00 to 3:00.

Beware of ambiguity during fall-back transitions, where the clock jumps from 2:00 back to 1:00

<pre><code>$date = new DateTime('3-Nov-2013 01:00 America/Los_Angeles');
echo $date-&gt;format('I');
# 1
</code></pre>

There are two 1:00 AMs, and this is taking the first one. It is ambiguous, because we might have meant the second one, and that is not represented.

One would think that PHP would allow either of the following:

<pre><code>new DateTime('3-Nov-2013 01:00 -0700 America/Los_Angeles') #PDT
new DateTime('3-Nov-2013 01:00 -0800 America/Los_Angeles') #PST
</code></pre>

But these don't seem to work when I tested. I also tried ISO format dates. Anyone know how to properly distinguish ambiguous values in PHP? If so, please edit or update in comments. Thanks.

blocks|key|3155491|text|注意回退转换过程中的多义性，此时时钟会从2:00跳回到1:00+$date+=+new+DateTime('3-Nov-2013+02:01+America/Los_Angeles');|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3155492|echo+$date->format('I');|3155493|3155494|有两个1:00+AM，2:01是第二个1点加上1小时1分钟。|3155495|entityMap^0|W|1P|0|0|O|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|S|8|@]|D|@]|E|$]]|$1|I|3|J|5|6|7|T|8|@]|D|@]|E|$]]|$1|K|3|-4|5|6|7|U|8|@]|D|@]|E|$]]]|L|$]]

Beware of ambiguity during fall-back transitions, where the clock jumps from 2:00 back to 1:00
<code>$date = new DateTime('3-Nov-2013 02:01 America/Los_Angeles');</code>

<code>echo $date-&gt;format('I');</code>

<h1>0</h1>

There are two 1:00 AMs, and 2:01 is taking the second one o'clock plus 1 hour and 1 minute.

I want to give date() a date and have it return if that date is DST or not. Running PHP 5.4.7 via xampp on a windows 7 box. A linux box running PHP 5.2.8 returns 0 no matter what date I give it.

What's wrong with my code?

<pre><code>echo date('I', strtotime('30-Mar-2013'));
# should return a 1 but returns 0

echo date('I', strtotime('30-Mar-2013 America/Los_Angeles'))."&lt;br&gt;"; # returns 0
echo date('I', strtotime('31-Mar-2013 America/Los_Angeles'))."&lt;br&gt;"; # returns 1
</code></pre>

The switch between DST should be between 9-Mar-2013 - 10-Mar-2013. 

At this point, the question is, why doesn't my PHP code return 1.

PHP - using date to find out daylight savings time

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我想给date()一个日期，无论这个日期是不是DST，都让它返回。在windows7机器上通过xampp运行PHP 5.4.7。运行PHP5.2.8的linux机器返回0，无论我给它的日期是什么。我的代码出了什么问题？echo date('I', strtotime('30-Mar-2013'));# should r...

问PHP -使用date查找夏令时
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