在WebView中允许麦克风访问(权限) [Android Studio] [Java]
在WebView中允许麦克风访问(权限) [Android Studio] [Java]
提问于 2016-10-25 17:59:25
我目前正在开发一个音乐调谐器，它使用html5和webview来显示“应用程序”。我已经编写了清单中所需的所有权限，我认为对于webview，还需要另一个权限。
我现在使用这个https://jbergknoff.github.io/guitar-tuner/作为示例重定向页面
这是我的manifest.xml
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.raynordev.projectrosin">
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.MICROPHONE" />
<uses-permission android:name="android.permission.RECORD_AUDIO" />
<uses-permission android:name="android.permission.INTERNET" />
<uses-feature android:name="android.hardware.audio.low_latency" />
<uses-feature android:name="android.hardware.audio.pro" />
<uses-feature android:name="android.hardware.microphone" android:required="true"/>
<application
android:allowBackup="true"
android:icon="@mipmap/ic_launcher"
android:label="@string/app_name"
android:supportsRtl="true"
android:theme="@style/AppTheme">
<activity
android:name=".MainActivity"
android:theme="@style/Theme.AppCompat.Light.NoActionBar">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
<activity android:name="com.raynordev.projectrosin.HomeActivity">
</activity>
</application>
</manifest>这是我的.java
public class HomeActivity extends AppCompatActivity {
private WebView wv;
private String TAG = "HomeActivity";
private static final int REQUEST_INTERNET = 200;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_home);
WebView wv = (WebView) findViewById(R.id.webView);
wv.getSettings().setJavaScriptEnabled(true);
wv.getSettings().setJavaScriptCanOpenWindowsAutomatically(true);
wv.setWebViewClient(new WebViewClient());
wv.setWebChromeClient(new WebChromeClient());
wv.loadUrl("https://jbergknoff.github.io/guitar-tuner/");
}
}如果需要我提供更多信息，请让我知道。
谢谢大家！！
回答 2
Stack Overflow用户
发布于 2017-11-21 18:05:58
<uses-permission android:name="android.permission.MODIFY_AUDIO_SETTINGS" />示例：
MainActivity
public class MainActivity extends AppCompatActivity {
private static final int MY_PERMISSIONS_REQUEST_RECORD_AUDIO = 101;
private ActivityMainBinding mBinding;
private PermissionRequest myRequest;
@Override
protected void onCreate(@Nullable Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
mBinding = DataBindingUtil.setContentView(this, R.layout.activity_main);
setWebView();
}
private void setWebView() {
mBinding.webView.getSettings().setJavaScriptEnabled(true);
mBinding.webView.getSettings().setJavaScriptCanOpenWindowsAutomatically(true);
mBinding.webView.setWebViewClient(new WebViewClient());
mBinding.webView.getSettings().setSaveFormData(true);
mBinding.webView.getSettings().setSupportZoom(false);
mBinding.webView.getSettings().setCacheMode(WebSettings.LOAD_NO_CACHE);
mBinding.webViemBinding.webView.getSettings().setPluginState(WebSettings.PluginState.ON);
mBinding.webView.setWebChromeClient(new WebChromeClient() {
@Override
public void onPermissionRequest(final PermissionRequest request) {
myRequest = request;
for (String permission : request.getResources()) {
switch (permission) {
case "android.webkit.resource.AUDIO_CAPTURE": {
askForPermission(request.getOrigin().toString(), Manifest.permission.RECORD_AUDIO, MY_PERMISSIONS_REQUEST_RECORD_AUDIO);
break;
}
}
}
}
});
mBinding.webView.loadUrl("<your url");
}
@Override
public void onBackPressed() {
if (mBinding.webView.canGoBack()) {
mBinding.webView.goBack();
} else {
super.onBackPressed();
}
}
@Override
public void onRequestPermissionsResult(int requestCode,
String permissions[], int[] grantResults) {
switch (requestCode) {
case MY_PERMISSIONS_REQUEST_RECORD_AUDIO: {
Log.d("WebView", "PERMISSION FOR AUDIO");
if (grantResults.length > 0
&& grantResults[0] == PackageManager.PERMISSION_GRANTED) {
// permission was granted, yay! Do the
// contacts-related task you need to do.
myRequest.grant(myRequest.getResources());
mBinding.webView.loadUrl("<your url>");
} else {
// permission denied, boo! Disable the
// functionality that depends on this permission.
}
}
// other 'case' lines to check for other
// permissions this app might request
}
}
public void askForPermission(String origin, String permission, int requestCode) {
Log.d("WebView", "inside askForPermission for" + origin + "with" + permission);
if (ContextCompat.checkSelfPermission(getApplicationContext(),
permission)
!= PackageManager.PERMISSION_GRANTED) {
// Should we show an explanation?
if (ActivityCompat.shouldShowRequestPermissionRationale(MainActivity.this,
permission)) {
// Show an expanation to the user *asynchronously* -- don't block
// this thread waiting for the user's response! After the user
// sees the explanation, try again to request the permission.
} else {
// No explanation needed, we can request the permission.
ActivityCompat.requestPermissions(MainActivity.this,
new String[]{permission},
requestCode);
}
} else {
myRequest.grant(myRequest.getResources());
}
}
}Mainfest.xml：
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.MICROPHONE" />
<uses-permission android:name="android.permission.RECORD_AUDIO" />
<uses-permission android:name="android.permission.INTERNET" />
<uses-feature android:name="android.hardware.audio.low_latency" />
<uses-permission android:name="android.permission.MODIFY_AUDIO_SETTINGS" />
<uses-feature android:name="android.hardware.audio.pro" />
<uses-feature android:name="android.hardware.microphone"/> Build.gradle：
android {
compileSdkVersion 26
defaultConfig {
applicationId "myapp.example.com.myapplication"
minSdkVersion 21
targetSdkVersion 21
versionCode 1
versionName "1.0"
}
buildTypes {
release {
minifyEnabled false
proguardFiles getDefaultProguardFile('proguard-android.txt'), 'proguard-rules.pro'
}
}Stack Overflow用户
发布于 2019-02-14 19:21:49
总而言之，您需要以下组件：
onPermissionRequest
- Inside
-
MODIFY_AUDIO_SETTINGS权限。 - 此回调的
WebChromeClient和侦听回调，检查进入request对象的资源，创建此request对象的全局变量，在PermissionRequest类中迭代并查找特定权限，例如。PermissionRequest.RESOURCE_VIDEO_CAPTURE转换为Manifest.permission.CAMERA权限，使用任何你想要的机制检查你的应用程序是否有这个权限，如果没有，请求，如果是这样做4. - 在权限回调中，或者如果权限被授予，使用request对象来授予权限例如。
request.grant(new String[]{PermissionRequest.RESOURCE_VIDEO_CAPTURE})，你就可以走了
代码片段：
webView.webChromeClient = object: WebChromeClient(){
override fun onPermissionRequest(request: PermissionRequest?) {
super.onPermissionRequest(request)
webkitPermissionRequest = request
request?.resources?.forEach {
when(it){
PermissionRequest.RESOURCE_AUDIO_CAPTURE-> {
askForWebkitPermission(it, Manifest.permission.RECORD_AUDIO, REQUEST_CODE_PERMISSION_AUDIO)
}
PermissionRequest.RESOURCE_VIDEO_CAPTURE->{
askForWebkitPermission(it, Manifest.permission.CAMERA, REQUEST_CODE_PERMISSION_CAMERA)
}
}
}
}
}
private fun askForWebkitPermission(webkitPermission: String, androidPermission: String, requestCode: Int){
val context = activity?: return
if (context.hasPermission(androidPermission)){
webkitPermissionRequest!!.grant(arrayOf(webkitPermission))
}else{
requestPermissions(arrayOf(androidPermission), requestCode)
}
}希望这能有所帮助。
谷歌的示例：https://github.com/googlesamples/android-PermissionRequest
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/40236925
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