blocks|key|271473|text|为什么不先构建集合，然后再处理集合中的文件呢？如果元素已经存在，则集合不会添加相同的元素；|type|unstyled|depth|inlineStyleRanges|entityRanges|data|271474|>>>+myset++=+{+element+for+element+in+['abc',+'def',+'ghi',+'def']+}
>>>+myset
set(['abc',+'ghi',+'def'])|code-block|syntax|javascript|271475|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Why don't you build your set first, and then process the files in the set afterwards? the set will not add the same element if it is already present;

<pre><code>&gt;&gt;&gt; myset = { element for element in ['abc', 'def', 'ghi', 'def'] }
&gt;&gt;&gt; myset
set(['abc', 'ghi', 'def'])
</code></pre>

blocks|key|1415209|text|更多的代码可能会有所帮助。不确定是否是这种情况，但if条件与初始化位置在同一个块中|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1415210|processed_set+=+set()|code-block|syntax|javascript|1415211|因此，基本上，如果xyz+!=+1，则只剩下一个空集，并且不会向该集添加任何内容。如果设置的循环多次命中第一个else语句，则每次都会清除set的内容。|1415212|再说一次，我不太确定你的代码是如何流动的，因为它现在有点晦涩难懂。添加更多的周边代码，人们会更容易帮到你。|1415213|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|6|7|P|8|@]|9|@]|A|$]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

A bit more of your code might be helpful. Not sure if this is the case, but your if conditional is in the same block as where you initialize

<pre><code>processed_set = set()
</code></pre>

So basically if xyz != 1 then you are left with an empty set and nothing gets added to the set. If you have a loop set up that hits the first else statement multiple times, you are clearing the contents of your set each time.

Again, I am not really sure of how your code flows since it is a bit obscure at the moment. Add more of the surrounding code and it will be a bit easier for people to help you out.

blocks|key|272417|text|从我从代码示例和基于函数名的猜测中可以推断出，如果已经处理了filename，那么您要做的就是避免运行代码。你可以这样做：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|272418|processed_set+=+set()+#initialize+set+outside+of+loop
for+filename+in+filenames:+#loop+over+some+collection+of+filenames
++++if+filename+not+in+processed_set:+#check+for+non-membership
++++++++processed_set.add(filename)+#add+to+set+since+filename+wasn't+in+the+set
++++++++create_folder(filename)+#repositioned+based+on+implied+semantics+of+the+name
++++++++createdata(filename)|code-block|syntax|javascript|272419|或者，如果createdata和create_folder都是您不希望对同一文件名多次运行的函数，则可以创建一个过滤装饰器。如果你真正关心返回值，你会想要使用一个记忆装饰器|272420|def+run_once(f):
++++f.processed+=+set()
++++def+wrapper(filename):
++++++++if+filename+not+in+f.processed:
++++++++f.processed.add(filename)
++++++++f(filename)
++++return+wrapper|272421|然后，对于只想运行一次的函数，在函数定义之前的行上包含@run_once。|272422|entityMap^0|U|8|0|0|5|A|G|D|0|0|R|9|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@$9|X|A|Y|B|C]|$9|Z|A|10|B|C]]|D|@]|E|$]]|$1|M|3|N|5|H|7|11|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|12|8|@$9|13|A|14|B|C]]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|15|8|@]|D|@]|E|$]]]|R|$]]

From what I can infer from the code sample and guess based on function names, what you want to do is to avoid running the code if <code>filename</code> has already been processed. You would do it this way:

<pre><code>processed_set = set() #initialize set outside of loop
for filename in filenames: #loop over some collection of filenames
 if filename not in processed_set: #check for non-membership
 processed_set.add(filename) #add to set since filename wasn't in the set
 create_folder(filename) #repositioned based on implied semantics of the name
 createdata(filename)
</code></pre>

Alternatively, if <code>createdata</code> and <code>create_folder</code> are both functions you don't want to run multiple times for the same filename, you could create a filtering decorator. If you actually care about the return value, you would want to use a memoizing decorator 

<pre><code>def run_once(f):
 f.processed = set()
 def wrapper(filename):
 if filename not in f.processed:
 f.processed.add(filename)
 f(filename)
 return wrapper
</code></pre>

then include <code>@run_once</code> on the line prior to your function definitions for the functions you only want to run once.

I have a part in a code like below where file name is supplied to the loop iteratively. I want that no two file names with same name should
get processed ( to avoid duplicate processing) so I used the approach of "set" as above.

However this does not seem to work as expected. I get an empty processed_set and logic is not executed as expected.

<pre><code>else:
 create_folder(filename)
 processed_set=set()

 if xyz ==1:
 if filename not in processed_set:
 createdata(name)
 processed_set.add(filename)
 else:
 avoid_double_process(name)
</code></pre>

Using set to avoid duplicate processing

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我在下面这样的代码中有一个部分，其中文件名迭代地提供给循环。我希望不会有两个同名的文件被处理(以避免重复处理)，所以我使用了上面的"set“方法。然而，这似乎并没有像预期的那样工作。我得到一个空的processed_set，逻辑没有按预期执行。else:    create_folder(filename)    pr...

问使用set避免重复处理
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