blocks|key|1323372|text|使用接口获取强类型：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1323373|//+Creating+
var+foo:any+=+{};
foo.x+=+3;
foo.y='123';

var+jsonString+=+JSON.stringify(foo);
alert(jsonString);


//+Reading
interface+Bar{
++++x:number;
++++y?:string;+
}

var+baz:Bar+=+JSON.parse(jsonString);
alert(baz.y);|code-block|syntax|javascript|1323374|如果需要，可以使用类型断言"<>“。|1323375|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

Use Interfaces to get strong types:

<pre><code>// Creating 
var foo:any = {};
foo.x = 3;
foo.y='123';

var jsonString = JSON.stringify(foo);
alert(jsonString);


// Reading
interface Bar{
 x:number;
 y?:string; 
}

var baz:Bar = JSON.parse(jsonString);
alert(baz.y);
</code></pre>

And use type assertion "&lt;>" if you need to.

blocks|key|1327103|text|我认为处理这个问题的更好的方法是使用Object.assign+(但是需要ECMAScript+2015)。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1327104|给定一个类|1327105|class+Pet+{
++++name:+string;
++++age:+number;
++++constructor(name?:+string,+age?:+number)+{
++++++++this.name+=+name;
++++++++this.age+=+age;
++++}
++++getDescription():+string+{
++++++++return+"My+pet+"+%2B+this.name+%2B+"+is+"+%2B+this.age+%2B+"+years+old.";
++++}
++++static+fromJSON(d:+Object):+Pet+{
++++++++return+Object.assign(new+Pet(),+d);
++++}
}|code-block|syntax|javascript|1327106|像这样序列化和反序列化...|1327107|var+p0+=+new+Pet("Fido",+5);
var+s+=+JSON.stringify(p0);
var+p1+=+Pet.fromJSON(JSON.parse(s));
console.log(p1.getDescription());|1327108|要将此示例带到下一个级别，请考虑嵌套对象...|1327109|class+Type+{
++++kind:+string;
++++breed:+string;
++++constructor(kind?:+string,+breed?:+string)+{
++++++++this.kind+=+kind;
++++++++this.breed+=+breed;
++++}
++++static+fromJSON(d:+Object)+{
++++++++return+Object.assign(new+Type(),+d);
++++}
}
class+Pet+{
++++name:+string;
++++age:+number;
++++type:+Type;
++++constructor(name?:+string,+age?:+number)+{
++++++++this.name+=+name;
++++++++this.age+=+age;
++++}
++++getDescription():+string+{
++++++++return+"My+pet+"+%2B+this.name+%2B+"+is+"+%2B+this.age+%2B+"+years+old.";
++++}
++++getFullDescription():+string+{
++++++++return+"My+"+%2B+this.type.kind+%2B+",+a+"+%2B+this.type.breed+%2B+",+is+"+%2B+this.age+%2B+"+years+old.";
++++}
++++static+fromJSON(d:+Object):+Pet+{
++++++++var+o+=+Object.assign(new+Pet(),+d);
++++++++o.type+=+Type.fromJSON(o['type']);
++++++++return+o;
++++}
}|1327110|1327111|var+q0+=+new+Pet("Fido",+5);
q0.type+=+new+Type("dog",+"Pomeranian");
var+t+=+JSON.stringify(q0);
var+q1+=+Pet.fromJSON(JSON.parse(t));
console.log(q1.getFullDescription());|1327112|因此，与使用接口不同，这种方法保留了方法。|1327113|entityMap^0|0|0|0|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|X|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|Y|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|Z|8|@]|9|@]|A|$G|H]]|$1|I|3|J|5|6|7|10|8|@]|9|@]|A|$]]|$1|K|3|L|5|F|7|11|8|@]|9|@]|A|$G|H]]|$1|M|3|N|5|6|7|12|8|@]|9|@]|A|$]]|$1|O|3|P|5|F|7|13|8|@]|9|@]|A|$G|H]]|$1|Q|3|J|5|6|7|14|8|@]|9|@]|A|$]]|$1|R|3|S|5|F|7|15|8|@]|9|@]|A|$G|H]]|$1|T|3|U|5|6|7|16|8|@]|9|@]|A|$]]|$1|V|3|-4|5|6|7|17|8|@]|9|@]|A|$]]]|W|$]]

I think a better way to handle this is to use Object.assign (which however requires ECMAScript 2015).

Given a class

<pre><code>class Pet {
 name: string;
 age: number;
 constructor(name?: string, age?: number) {
 this.name = name;
 this.age = age;
 }
 getDescription(): string {
 return "My pet " + this.name + " is " + this.age + " years old.";
 }
 static fromJSON(d: Object): Pet {
 return Object.assign(new Pet(), d);
 }
}
</code></pre>

Serialize and deserialize like this...

<pre><code>var p0 = new Pet("Fido", 5);
var s = JSON.stringify(p0);
var p1 = Pet.fromJSON(JSON.parse(s));
console.log(p1.getDescription());
</code></pre>

To take this example to the next level, consider nested objects...

<pre><code>class Type {
 kind: string;
 breed: string;
 constructor(kind?: string, breed?: string) {
 this.kind = kind;
 this.breed = breed;
 }
 static fromJSON(d: Object) {
 return Object.assign(new Type(), d);
 }
}
class Pet {
 name: string;
 age: number;
 type: Type;
 constructor(name?: string, age?: number) {
 this.name = name;
 this.age = age;
 }
 getDescription(): string {
 return "My pet " + this.name + " is " + this.age + " years old.";
 }
 getFullDescription(): string {
 return "My " + this.type.kind + ", a " + this.type.breed + ", is " + this.age + " years old.";
 }
 static fromJSON(d: Object): Pet {
 var o = Object.assign(new Pet(), d);
 o.type = Type.fromJSON(o['type']);
 return o;
 }
}
</code></pre>

Serialize and deserialize like this...

<pre><code>var q0 = new Pet("Fido", 5);
q0.type = new Type("dog", "Pomeranian");
var t = JSON.stringify(q0);
var q1 = Pet.fromJSON(JSON.parse(t));
console.log(q1.getFullDescription());
</code></pre>

So unlike using an interface, this approach preserves methods.

blocks|key|1000806|text|AQuirky+answer适用于我。您可能在使用Object.assign方法时遇到了一些问题。我不得不修改我的tsconfig.json以包含：|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|1000807|"compilerOptions":+{
++++...
++++"lib":+["es2015"],
++++...
}|code-block|syntax|javascript|1000808|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/a/52237888/4629842^0|0|E|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@$A|R|B|S|1|T]]|C|$]]|$1|D|3|E|5|F|7|U|8|@]|9|@]|C|$G|H]]|$1|I|3|-4|5|6|7|V|8|@]|9|@]|C|$]]]|J|$K|$5|L|M|N|C|$O|P]]]]

The <a href="https://stackoverflow.com/a/52237888/4629842">AQuirky answer</a> works for me.
You may have some troubles with the Object.assign method. I had to modify my tsconfig.json to include:

<pre><code>"compilerOptions": {
 ...
 "lib": ["es2015"],
 ...
}
</code></pre>

blocks|key|1327155|text|首先，您需要为您的源实体创建一个接口，该接口作为JSON从API接收：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1327156|interface+UserEntity+{
++name:+string,
++age:+number,
++country_code:+string+
};|code-block|syntax|javascript|1327157|第二，用构造器实现你的模型，你可以定制(驼峰化)一些字段名：|1327158|++class+User++{+
++++constructor({+name,+age,+country_code:+countryCode+}:+UserEntity)+{
++++++Object.assign(this,+{+name,+age,+countryCode+});
++++}
++}|1327159|最后使用JS+object+jsonUser创建用户模型的实例“|1327160|++++const+jsonUser+=+{name:+'Ted',+age:+2,+country_code:+'US'};

++++const+userInstance+=+new+User(jsonUser);
++++
++++console.log({+userInstance+})|1327161|​|1327162|📷|atomic|offset|length|1327163|1327164|Here+is+the+link+to+playground|1327165|entityMap|0|IMAGE|mutability|IMMUTABLE|imageUrl|https://ask.qcloudimg.com/http-save/yehe-900000/9d34f48091e7a50128ea51fae35b0872.png|imageAlt|1|LINK|MUTABLE|url|https://www.typescriptlang.org/play?#code/JYOwLgpgTgZghgYwgAgKoGdoFFzDAT2QG8BYAKGWRDgFsIAuZdMKUAcwBpzK42GqArjQBG0LhWQIA9gPBR8AfWkATfs1Yg2ycgF8A3OXIIANnHTo0mKJSLaJlaSHUCEYKVAAUt6nQ7JeEH7SsiyKKvzBcvgAwlKqyDqMGNi4BACUxNyU2dkA8sIAVhCuAHRm6MBsIB5gABbA6H7etIH%2520fEEyUbHxOmkG9gm6hmSOzMgF6FIgydYAvMQ%2520-ADkACoQysgAMnAADsDKAuhLfgGMAEwdIfJKccuoAMpL%2520sOjYMiH0ACSTmBwIEjIeYgCAAd0s0A8EymMz6wyMU0mxggJWMUjYXg%2520UG%2520zD%2520SF65CAA^0|0|0|0|0|0|0|0|0|1|0|0|0|0|U|1|0^^$0|@$1|2|3|4|5|6|7|1C|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|1D|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|1E|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|1F|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|1G|8|@]|9|@]|A|$]]|$1|M|3|N|5|D|7|1H|8|@]|9|@]|A|$E|F]]|$1|O|3|P|5|6|7|1I|8|@]|9|@]|A|$]]|$1|Q|3|R|5|S|7|1J|8|@]|9|@$T|1K|U|1L|1|1M]]|A|$]]|$1|V|3|P|5|6|7|1N|8|@]|9|@]|A|$]]|$1|W|3|X|5|6|7|1O|8|@]|9|@$T|1P|U|1Q|1|1R]]|A|$]]|$1|Y|3|-4|5|6|7|1S|8|@]|9|@]|A|$]]]|Z|$10|$5|11|12|13|A|$14|15|16|-4]]|17|$5|18|12|19|A|$1A|1B]]]]

First, you need to create an interface of your source entity which you receive from the API as JSON:
<pre><code>interface UserEntity {
 name: string,
 age: number,
 country_code: string 
};
</code></pre>
Second implement your model with constructor where you can customize (camelize) some field names:
<pre><code> class User { 
 constructor({ name, age, country_code: countryCode }: UserEntity) {
 Object.assign(this, { name, age, countryCode });
 }
 }
</code></pre>
Last create instance of your User model using JS object jsonUser&quot;
<pre><code> const jsonUser = {name: 'Ted', age: 2, country_code: 'US'};

 const userInstance = new User(jsonUser);
 
 console.log({ userInstance })
</code></pre>
<a href="https://i.stack.imgur.com/NdYVY.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/NdYVY.png" alt="Result log" /></a>
<a href="https://www.typescriptlang.org/play?#code/JYOwLgpgTgZghgYwgAgKoGdoFFzDAT2QG8BYAKGWRDgFsIAuZdMKUAcwBpzK42GqArjQBG0LhWQIA9gPBR8AfWkATfs1Yg2ycgF8A3OXIIANnHTo0mKJSLaJlaSHUCEYKVAAUt6nQ7JeEH7SsiyKKvzBcvgAwlKqyDqMGNi4BACUxNyU2dkA8sIAVhCuAHRm6MBsIB5gABbA6H7etIH%20fEEyUbHxOmkG9gm6hmSOzMgF6FIgydYAvMQ%20-ADkACoQysgAMnAADsDKAuhLfgGMAEwdIfJKccuoAMpL%20sOjYMiH0ACSTmBwIEjIeYgCAAd0s0A8EymMz6wyMU0mxggJWMUjYXg%20UG%20zD%20SF65CAA" rel="nofollow noreferrer">Here is the link to playground</a>

blocks|key|184861|text|到目前为止，我发现的最好的方法是使用"jackson-js"，jackson-js是一个允许你使用ts装饰器描述类，然后序列化和期望保存类型信息的项目。它支持数组、映射等。|type|unstyled|depth|inlineStyleRanges|entityRanges|offset|length|data|184862|完整教程：https://itnext.io/jackson-js-powerful-javascript-decorators-to-serialize-deserialize-objects-into-json-and-vice-df952454cf|184863|简单示例：|184864|import+{+JsonProperty,+JsonClassType,+JsonAlias,+ObjectMapper+}+from+'jackson-js';

class+Book+{
++@JsonProperty()+@JsonClassType({type:+()+=>+[String]})
++name:+string;
++@JsonProperty()+@JsonClassType({type:+()+=>+[String]})
++@JsonAlias({values:+['bkcat',+'mybkcat']})
++category:+string;
}

class+Writer+{
++@JsonProperty()+@JsonClassType({type:+()+=>+[Number]})
++id:+number;
++@JsonProperty()+@JsonClassType({type:+()+=>+[String]})
++name:+string;
++@JsonProperty()+@JsonClassType({type:+()+=>+[Array,+[Book]]})
++books:+Book[]+=+[];
}

const+objectMapper+=+new+ObjectMapper();
//+eslint-disable-next-line+max-len
const+jsonData+=+'{"id":1,"name":"John","books":[{"name":"Learning+TypeScript","bkcat":"Web+Development"},{"name":"Learning+Spring","mybkcat":"Java"}]}';
const+writer+=+objectMapper.parse<Writer>(jsonData,+{mainCreator:+()+=>+[Writer]});
console.log(writer);
/*
Writer+{
++books:+[
++++Book+{+name:+'Learning+TypeScript',+category:+'Web+Development'+},
++++Book+{+name:+'Learning+Spring',+category:+'Java'+}
++],
++id:+1,
++name:+'John'
}
*/|code-block|syntax|javascript|184865|还有其他几个项目声称做了同样的事情-|184866|184867|https://github.com/typestack/class-transformer|unordered-list-item|184868|https://github.com/JohnWeisz/TypedJSON|184869|https://www.npmjs.com/package/typescript-json-serializer|184870|https://www.npmjs.com/package/ts-serializer|184871|184872|然而，当我使用Ts+Map时，jackson-js是唯一能为我工作的。|184873|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/pichillilorenzo/jackson-js|1|https://itnext.io/jackson-js-powerful-javascript-decorators-to-serialize-deserialize-objects-into-json-and-vice-df952454cf|2|3|4|5^0|I|C|0|0|5|3E|1|0|0|0|0|0|0|1A|2|0|0|12|3|0|0|1K|4|0|0|17|5|0|0|0^^$0|@$1|2|3|4|5|6|7|1F|8|@]|9|@$A|1G|B|1H|1|1I]]|C|$]]|$1|D|3|E|5|6|7|1J|8|@]|9|@$A|1K|B|1L|1|1M]]|C|$]]|$1|F|3|G|5|6|7|1N|8|@]|9|@]|C|$]]|$1|H|3|I|5|J|7|1O|8|@]|9|@]|C|$K|L]]|$1|M|3|N|5|6|7|1P|8|@]|9|@]|C|$]]|$1|O|3|-4|5|6|7|1Q|8|@]|9|@]|C|$]]|$1|P|3|Q|5|R|7|1R|8|@]|9|@$A|1S|B|1T|1|1U]]|C|$]]|$1|S|3|T|5|R|7|1V|8|@]|9|@$A|1W|B|1X|1|1Y]]|C|$]]|$1|U|3|V|5|R|7|1Z|8|@]|9|@$A|20|B|21|1|22]]|C|$]]|$1|W|3|X|5|R|7|23|8|@]|9|@$A|24|B|25|1|26]]|C|$]]|$1|Y|3|-4|5|6|7|27|8|@]|9|@]|C|$]]|$1|Z|3|10|5|6|7|28|8|@]|9|@]|C|$]]|$1|11|3|-4|5|6|7|29|8|@]|9|@]|C|$]]]|12|$13|$5|14|15|16|C|$17|18]]|19|$5|14|15|16|C|$17|1A]]|1B|$5|14|15|16|C|$17|Q]]|1C|$5|14|15|16|C|$17|T]]|1D|$5|14|15|16|C|$17|V]]|1E|$5|14|15|16|C|$17|X]]]]

The best method i found so far was to use <a href="https://github.com/pichillilorenzo/jackson-js" rel="nofollow noreferrer">&quot;jackson-js&quot;</a>,
jackson-js is a project that allows you to describe the class using ts-decorators
and then serialize and desirialize saving the type information.
it supports arrays,maps etc.
full tutorial:<a href="https://itnext.io/jackson-js-powerful-javascript-decorators-to-serialize-deserialize-objects-into-json-and-vice-df952454cf" rel="nofollow noreferrer">https://itnext.io/jackson-js-powerful-javascript-decorators-to-serialize-deserialize-objects-into-json-and-vice-df952454cf</a>
simple exmaple:
<pre><code>import { JsonProperty, JsonClassType, JsonAlias, ObjectMapper } from 'jackson-js';

class Book {
 @JsonProperty() @JsonClassType({type: () =&gt; [String]})
 name: string;
 @JsonProperty() @JsonClassType({type: () =&gt; [String]})
 @JsonAlias({values: ['bkcat', 'mybkcat']})
 category: string;
}

class Writer {
 @JsonProperty() @JsonClassType({type: () =&gt; [Number]})
 id: number;
 @JsonProperty() @JsonClassType({type: () =&gt; [String]})
 name: string;
 @JsonProperty() @JsonClassType({type: () =&gt; [Array, [Book]]})
 books: Book[] = [];
}

const objectMapper = new ObjectMapper();
// eslint-disable-next-line max-len
const jsonData = '{&quot;id&quot;:1,&quot;name&quot;:&quot;John&quot;,&quot;books&quot;:[{&quot;name&quot;:&quot;Learning TypeScript&quot;,&quot;bkcat&quot;:&quot;Web Development&quot;},{&quot;name&quot;:&quot;Learning Spring&quot;,&quot;mybkcat&quot;:&quot;Java&quot;}]}';
const writer = objectMapper.parse&lt;Writer&gt;(jsonData, {mainCreator: () =&gt; [Writer]});
console.log(writer);
/*
Writer {
 books: [
 Book { name: 'Learning TypeScript', category: 'Web Development' },
 Book { name: 'Learning Spring', category: 'Java' }
 ],
 id: 1,
 name: 'John'
}
*/
</code></pre>
There are a few other projects that claim to do the same thing -
<ul>
<li><a href="https://github.com/typestack/class-transformer" rel="nofollow noreferrer">https://github.com/typestack/class-transformer</a></li>
<li><a href="https://github.com/JohnWeisz/TypedJSON" rel="nofollow noreferrer">https://github.com/JohnWeisz/TypedJSON</a></li>
<li><a href="https://www.npmjs.com/package/typescript-json-serializer" rel="nofollow noreferrer">https://www.npmjs.com/package/typescript-json-serializer</a></li>
<li><a href="https://www.npmjs.com/package/ts-serializer" rel="nofollow noreferrer">https://www.npmjs.com/package/ts-serializer</a></li>
</ul>
However jackson-js is the only one that worked for me when i used a Ts Map.

Are there any means for JSON serialization/deserialization of Typescript objects so that they don't loose type information? Simple <code>JSON.parse(JSON.stringify)</code> has too many caveats.

Or I should use adhoc solutions?

Typescript objects serialization?

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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有没有办法对Typescript对象进行JSON序列化/反序列化，这样它们就不会丢失类型信息？简单的JSON.parse(JSON.stringify)有太多的警告。或者我应该使用即席解决方案？

问Typescript对象序列化？
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