如何在php中替换数组中索引处的值？
如何在php中替换数组中索引处的值？
提问于 2013-05-17 01:35:03
我尝试做的是在用户名匹配的索引处替换JSON数组的值。我该怎么做呢？下面是我的试用PHP代码和JSON。使用array_replace是最好的方式，还是我应该采取不同的方式？
<?php
$user_with_game = file_get_contents("oneuser.json");//$_POST["userGames"];
//$user_with_game = stripslashes ($JSON);
$user_decoded_JSON = json_decode($user_with_game, true);
$JSON = file_get_contents("users.json");
$decoded_JSON = json_decode($JSON, true);
//print_r ($user_decoded_JSON);
foreach ($decoded_JSON['Users'] as $key => $value)
{
if ( $value['username'] == $user_decoded_JSON['username'])
{
$decoded_JSON['Users'] = array_replace($decoded_JSON['Users'], $user_decoded_JSON);
}
}
//print_r ($decoded_JSON);
$encoded_JSON = json_encode( $decoded_JSON);
echo $encoded_JSON;
?>
**users.json**
{
"Users":[
{
"password":"glass",
"gamelist":[
{
"platform":"xbox-360",
"game":"bioshock infinite"
},
{
"platform":"xbox-360",
"game":"tomb raider"
}
],
"username":"dorinayres",
"reviewerlist":[
]
},
{
"password":"happy",
"gamelist":[
{
"platform":"xbox-360",
"game":"far cry 3"
},
{
"platform":"xbox-360",
"game":"terraria"
}
],
"username":"ian",
"reviewerlist":[
]
}
]
}
**oneuser.json**
{
"password":"glass",
"gamelist":[
{
"platform":"xbox-360",
"game":"bioshock infinite"
},
{
"platform":"xbox-360",
"game":"tomb raider"
}
],
"username":"dorinayres",
"reviewerlist":[
]
}回答 2
Stack Overflow用户
回答已采纳
发布于 2013-05-17 01:44:05
PHP foreach and pass by reference
foreach($decoded_JSON['Users'] as &$user){
if($user['username'] == $user_decoded_JSON['username']){
//do something directly on $user here and it will effect the actual array
}
}Stack Overflow用户
发布于 2013-05-17 01:47:15
$decoded_JSON_tmp=$decoded_JSON;
foreach ($decoded_JSON['Users'] as $key => $value)
{
if ( $value['username'] == $user_decoded_JSON['username'])
{
$decoded_JSON_tmp['Users'] = array_replace($decoded_JSON['Users'], $user_decoded_JSON);
}
}
$decoded_JSON=$decoded_JSON_tmp;页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/16593893
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