blocks|key|2498933|text|我尝试了一种变通方法，即连接字符串并将其转换回JSON，然后更新表。这不是最优雅的方式，所以如果你们有任何建议，请告诉我！:)|type|unstyled|depth|inlineStyleRanges|entityRanges|data|2498934|BEGIN
DECLARE+var1+INT+default+-2;+//offsets
DECLARE+var2+INT+default+2;+//offsets
SELECT+StatusID+into+@statusList+FROM+UserStatusesIndex;
SET+@statusID_to_remove+=+OLD.StatusID;
SET+@startIndex+=+INSTR(@statusList,+@statusID_to_remove);
SET+@charLength+=+CHAR_LENGTH(@statusID_to_remove);

IF+@startIndex+<=+2+THEN+SET+var1=-1,+var2=2;+//If+its+the+first+index
ELSEIF+(CHAR_LENGTH(@statusList)+-+@startIndex+<=+2)+THEN+SET+var1=-3,+var2=0;++//If+its+the+last+index
ELSE+SET+var1=-2,+var2=2;
END+IF;

SET+@newJson=CAST(CONCAT(SUBSTRING(@statusList,+1,+@startIndex%2Bvar1),+SUBSTR(@statusList,+@startIndex+%2B+@charLength%2Bvar2,+CHAR_LENGTH(@statusList)+-+@startIndex+-+@charLength%2B2))+as+JSON);
UPDATE+UserStatusesIndex+SET+StatusID=@newJson+WHERE+StatusCreator=OLD.StatusCreator;
END|code-block|syntax|javascript|2498935|谢谢!|2498936|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|L|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

I have tried a workaround method, which is to CONCAT the string and cast it back to JSON and update the table. It's not the most elegant way, so if you guys have any suggestion, please let me know! :)

<pre><code>BEGIN
DECLARE var1 INT default -2; //offsets
DECLARE var2 INT default 2; //offsets
SELECT StatusID into @statusList FROM UserStatusesIndex;
SET @statusID_to_remove = OLD.StatusID;
SET @startIndex = INSTR(@statusList, @statusID_to_remove);
SET @charLength = CHAR_LENGTH(@statusID_to_remove);

IF @startIndex &lt;= 2 THEN SET var1=-1, var2=2; //If its the first index
ELSEIF (CHAR_LENGTH(@statusList) - @startIndex &lt;= 2) THEN SET var1=-3, var2=0; //If its the last index
ELSE SET var1=-2, var2=2;
END IF;

SET @newJson=CAST(CONCAT(SUBSTRING(@statusList, 1, @startIndex+var1), SUBSTR(@statusList, @startIndex + @charLength+var2, CHAR_LENGTH(@statusList) - @startIndex - @charLength+2)) as JSON);
UPDATE UserStatusesIndex SET StatusID=@newJson WHERE StatusCreator=OLD.StatusCreator;
END
</code></pre>

Thanks!

blocks|key|3768848|text|这似乎起作用了：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3768849|SET+@j+=+'[3,+2,+1]';
SELECT+JSON_CONTAINS(@j,+'3',+'$');|code-block|syntax|javascript|3768850|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This seems to work:

<pre><code>SET @j = '[3, 2, 1]';
SELECT JSON_CONTAINS(@j, '3', '$');
</code></pre>

blocks|key|595225|text|这是设计出来的，尽管我不同意mySQL团队的观点。这应该得到实现。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|595226|https://bugs.mysql.com/bug.php?id=79233已关闭|offset|length|595227|595228|+https://dev.mysql.com/worklog/task/?id=7909的规范说：“这个函数返回给定字符串的路径。返回的路径标识对象成员或字符串的数组位置。”|blockquote|595229|595230|因此，这个函数的目的似乎是搜索字符串。应该更新文档以澄清该函数用于搜索字符串标量，而不是一般的标量。|595231|entityMap|0|LINK|mutability|MUTABLE|url|https://bugs.mysql.com/bug.php?id=79233|1|https://dev.mysql.com/worklog/task/?id=7909^0|0|0|13|0|0|0|1|17|1|0|0|0^^$0|@$1|2|3|4|5|6|7|W|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|X|8|@]|9|@$D|Y|E|Z|1|10]]|A|$]]|$1|F|3|-4|5|6|7|11|8|@]|9|@]|A|$]]|$1|G|3|H|5|I|7|12|8|@]|9|@$D|13|E|14|1|15]]|A|$]]|$1|J|3|-4|5|6|7|16|8|@]|9|@]|A|$]]|$1|K|3|L|5|6|7|17|8|@]|9|@]|A|$]]|$1|M|3|-4|5|6|7|18|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]|U|$5|P|Q|R|A|$S|V]]]]

It is by design, although I can not agree with mySQL team. This should be implemented.

<a href="https://bugs.mysql.com/bug.php?id=79233" rel="noreferrer">https://bugs.mysql.com/bug.php?id=79233</a> [closed]

<blockquote>
 The specification at <a href="https://dev.mysql.com/worklog/task/?id=7909" rel="noreferrer">https://dev.mysql.com/worklog/task/?id=7909</a> says:
 "This function returns path(s) to the given string. The returned
 path(s) identify object members or array slots which are character
 strings."
 
 So it seems that the intention of this function was to search for
 strings. The documentation should be updated to clarify that the
 function is for searching for string scalars, not for scalars in
 general.
</blockquote>

blocks|key|3768895|text|您可以在整数的JSON_ARRAY前面加上一个字母字符，如下所示：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3768896|SET+@trailers+:=+JSON_ARRAY(
't9'
,'t10'
,'t11'
,'t12'
,'t13'
,'t14'
);|code-block|syntax|javascript|3768897|然后，当您使用它来定位与JSON_SEARCH相关联的id时，您可以使用CONCAT在表中使用相同的值作为id的前缀，如下所示：|3768898|select+*+from+trailers.trailer+t
where+
JSON_SEARCH(@open_trailers,+'one',+concat('t',+t.trailer_id+))+IS+NOT+NULL
;|3768899|这应该是可行的，但要注意可能出现的潜在性能问题。|3768900|祝你好运！|3768901|entityMap^0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|Q|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|R|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|S|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|K|3|L|5|6|7|U|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|V|8|@]|9|@]|A|$]]|$1|O|3|-4|5|6|7|W|8|@]|9|@]|A|$]]]|P|$]]

You could prefix your JSON_ARRAY of INTEGERs with an alpha character like this:
<pre><code>SET @trailers := JSON_ARRAY(
't9'
,'t10'
,'t11'
,'t12'
,'t13'
,'t14'
);
</code></pre>
Then, when you use it to locate the associated ids with JSON_SEARCH, you can use CONCAT to prefix the id in your table with the same value like this:
<pre><code>select * from trailers.trailer t
where 
JSON_SEARCH(@open_trailers, 'one', concat('t', t.trailer_id )) IS NOT NULL
;
</code></pre>
That should work, but be aware of potential performance issues that may arise.
Best of luck!

I am looking to use json_search to get the array path that corresponds to a value. 

I have tried and this works: 

<pre><code>SET @j = '["3", "2", "1"]';
SELECT json_search(@j, 'one', '2');
</code></pre>

returns $[1];

I have tried and this doesn't work: (How do I make this work?)

<pre><code>SET @j = '[3, 2, 1]';
SELECT json_search(@j, 'one', 2);
</code></pre>

returns null;

Basically I want to store @j as an integer array instead of a string array for indexing purposes. Is there any way I can change the integer array into a string array for comparison if there is no way for json_search to work with integers?

MYSQL Triggers: JSON_SEARCH an integer value in a json array of integers

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我希望使用json_search来获取对应于某个值的数组路径。我已经尝试过了，这是可行的：SET @j = '["3", "2", "1"]';SELECT json_search(@j, 'one', '2');返回$1；我已经尝试过了，但这不起作用：(我如何使其起作用？)SET @j = '[3, 2, 1]';S...

问MYSQL触发器:在整数的json数组中JSON_SEARCH一个整数值
EN

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问MYSQL触发器:在整数的json数组中JSON_SEARCH一个整数值EN