blocks|key|335587|text|不能将元素添加到数组中-只能在数组中设置元素。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|335588|我建议你使用List<Object[]>：|offset|length|style|CODE|335589|List<Object[]>+hexgenSecurityInferenceData+=+new+ArrayList<Object[]>();
for+(String+methodName:knowGoodMap.keySet())+{
++++hexgenSecurityInferenceData.add(new+Object[]+{
++++++++knowGoodMap.get(methodName),
++++++++new+Object[]+{
++++++++++++methodPropertiesMap.get(methodName),
++++++++++++methodParametersMap.get(methodName)
++++++++}
+++++});
+}|code-block|syntax|javascript|335590|(我已经删除了这些造型，因为它们没有意义...无论如何，您都是将这些值存储在Object[]中。强制转换的唯一好处是，如果对象是意外类型，则会导致异常。)|335591|如果你真的想要，你仍然可以使用一个数组，但是你需要一开始就创建一个大小合适的数组，然后保持“当前索引”。无论如何，使用数组通常比使用列表更难。|335592|如果你真的需要一个数组，你可以从列表中创建一个：|335593|Object[][]+array+=+hexgenSecurityInferenceData.toArray(new+Object[0][]);|335594|这种方法分两个阶段完成，比直接预先填充数组要简单。|335595|实际上，我建议做两个进一步的改变：|335596|335597|不要只使用Object[]+...创建一个类型来封装此数据。使用您当前的方法，您甚至在Object[]中获得了一个嵌套的Object[]+...任何读取这些数据的代码都将是可怕的。|unordered-list-item|335598|使用entrySet()而不是keySet()，这样你就不需要通过key|335599|来获取值了|335600|entityMap^0|0|6|E|0|0|12|8|0|0|0|0|0|0|0|5|8|17|8|1O|8|0|2|A|F|8|0|0^^$0|@$1|2|3|4|5|6|7|18|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|19|8|@$D|1A|E|1B|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|1C|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|1D|8|@$D|1E|E|1F|F|G]]|9|@]|A|$]]|$1|O|3|P|5|6|7|1G|8|@]|9|@]|A|$]]|$1|Q|3|R|5|6|7|1H|8|@]|9|@]|A|$]]|$1|S|3|T|5|J|7|1I|8|@]|9|@]|A|$K|L]]|$1|U|3|V|5|6|7|1J|8|@]|9|@]|A|$]]|$1|W|3|X|5|6|7|1K|8|@]|9|@]|A|$]]|$1|Y|3|-4|5|6|7|1L|8|@]|9|@]|A|$]]|$1|Z|3|10|5|11|7|1M|8|@$D|1N|E|1O|F|G]|$D|1P|E|1Q|F|G]|$D|1R|E|1S|F|G]]|9|@]|A|$]]|$1|12|3|13|5|11|7|1T|8|@$D|1U|E|1V|F|G]|$D|1W|E|1X|F|G]]|9|@]|A|$]]|$1|14|3|15|5|6|7|1Y|8|@]|9|@]|A|$]]|$1|16|3|-4|5|6|7|1Z|8|@]|9|@]|A|$]]]|17|$]]

You can't add elements to an array - you can only set elements in an array.

I suggest you have a <code>List&lt;Object[]&gt;</code> instead:

<pre><code>List&lt;Object[]&gt; hexgenSecurityInferenceData = new ArrayList&lt;Object[]&gt;();
for (String methodName:knowGoodMap.keySet()) {
 hexgenSecurityInferenceData.add(new Object[] {
 knowGoodMap.get(methodName),
 new Object[] {
 methodPropertiesMap.get(methodName),
 methodParametersMap.get(methodName)
 }
 });
 }
</code></pre>

(I've removed the casts as they were pointless... you're storing the values in an <code>Object[]</code> anyway. The only benefit of the casts would be to cause an exception if the objects were of an unexpected type.)

You could still use an array if you really wanted, but you'd need to create it with the right size to start with, and then keep the "current index". It's then generally harder to use arrays than lists anyway.

If you really need an array, you can create one from the list:

<pre><code>Object[][] array = hexgenSecurityInferenceData.toArray(new Object[0][]);
</code></pre>

Doing it in two stages this way will be simpler than directly populating an array up-front.

I'd actually suggest two further changes:

<ul>
<li>Don't just use <code>Object[]</code> for this... create a type to encapsulate this data. With your current approach, you've even got a nested <code>Object[]</code> within the <code>Object[]</code>... any code reading this data will be horrible.</li>
<li>Use <code>entrySet()</code> instead of <code>keySet()</code>, then you don't need to fetch the value by key</li>
</ul>

blocks|key|1304638|text|你有一个对象矩阵Object[][]，所以如果你想填充这个二维数组，你必须这样做：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1304639|Object[][]+hexgenSecurityInferenceData=new+Object[10][10];
for(int+i=0;+i<10;i%2B%2B){
+++for(int+j=0;+j<10;j%2B%2B){
++++++++hexgenSecurityInferenceData[i][j]+=+new+Object();
+++}
}|code-block|syntax|javascript|1304640|Jon指出，和一样，最好有自己的实现/封装，而不是使用Object|BOLD|1304641|entityMap^0|8|A|0|0|6|1|R|6|0^^$0|@$1|2|3|4|5|6|7|P|8|@$9|Q|A|R|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|S|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|T|8|@$9|U|A|V|B|M]|$9|W|A|X|B|C]]|D|@]|E|$]]|$1|N|3|-4|5|6|7|Y|8|@]|D|@]|E|$]]]|O|$]]

You have a matrix of objects <code>Object[][]</code> so if you want to populate this 2-d array you have to do something like:

<pre><code>Object[][] hexgenSecurityInferenceData=new Object[10][10];
for(int i=0; i&lt;10;i++){
 for(int j=0; j&lt;10;j++){
 hexgenSecurityInferenceData[i][j] = new Object();
 }
}
</code></pre>

But as well pointed by Jon its better to have your own implementation/encapsulation instead of using <code>Object</code>

blocks|key|335625|text|使用List是解决这个问题的最好方法。但是，您仍然可以通过初始化数组来使用object[]。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|335626|Object[][]+hexgenSecurityInferenceData+=+new+Object[knowGoodMap.keySet().size()][];
int+i+=+0;
for+(String+methodName+:+knowGoodMap.keySet())+
{
++hexgenSecurityInferenceData[i][0]+=+new+Object[][]
++{
+++++{(KnownGoodInfoRO)+knowGoodMap.get(methodName),+
+++++++++new+Object[]{(MethodPropertiesRO)+methodPropertiesMap.get(methodName),+(List)+methodParametersMap.get(methodName)}
+++++}
++};
+++i%2B%2B;
+}|code-block|syntax|javascript|335627|entityMap^0|2|4|11|8|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]|$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|R|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|S|8|@]|D|@]|E|$]]]|L|$]]

Using <code>List</code> is the best way to resolve this. However still you can do using <code>object[]</code> by initializing array.

<pre><code>Object[][] hexgenSecurityInferenceData = new Object[knowGoodMap.keySet().size()][];
int i = 0;
for (String methodName : knowGoodMap.keySet()) 
{
 hexgenSecurityInferenceData[i][0] = new Object[][]
 {
 {(KnownGoodInfoRO) knowGoodMap.get(methodName), 
 new Object[]{(MethodPropertiesRO) methodPropertiesMap.get(methodName), (List) methodParametersMap.get(methodName)}
 }
 };
 i++;
 }
</code></pre>

How to set values for two dimension array of objects in java.

following is my for loop :

<pre><code>Object[][] hexgenSecurityInferenceData = null;
for (String methodName: knowGoodMap.keySet()) {
 hexgenSecurityInferenceData = new Object[][] {
 {
 (KnownGoodInfoRO) knowGoodMap.get(methodName), new Object[] {
 (MethodPropertiesRO) methodPropertiesMap.get(methodName), (List) methodParametersMap.get(methodName)
 }
 },
 };
}
</code></pre>

this prints only one row of data. I am sure that i make mistake when <code>adding values to Array of Object but really don't know how to fix.</code>

Kindly help me to fix this

adding multiple data to Object array at run time

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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如何在java中设置对象的二维数组的值。下面是我的for循环：Object[][] hexgenSecurityInferenceData = null;for (String methodName: knowGoodMap.keySet()) {    hexgenSecurityInferenceData = ne...

问在运行时向对象数组添加多个数据
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