blocks|key|404717|text|当然，只要改变它：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|404718|使用jQuery的$.each|offset|length|style|CODE|404719|$.each(foo,+function()+{
++++if+(this.bar+===+1)+{
++++++++this.baz[0]+=+11;
++++++++this.baz[1]+=+22;
++++++++this.baz[2]+=+33;
++++++++//+Or:+`this.baz+=+[11,+22,+33];`
++++}
});|code-block|syntax|javascript|404720|使用ES5的forEach|404721|foo.forEach(function(obj)+{
++++if+(obj.bar+===+1)+{
++++++++obj.baz[0]+=+11;
++++++++obj.baz[1]+=+22;
++++++++obj.baz[2]+=+33;
++++++++//+Or:+`obj.baz+=+[11,+22,+33];`
++++}
});|404722|...or你有other+looping+options+in+this+other+SO+answer。|404723|entityMap|0|LINK|mutability|MUTABLE|url|https://stackoverflow.com/questions/9329446/for-each-in-a-array-how-to-do-that-in-javascript/9329476#9329476^0|0|9|6|0|0|6|7|0|0|7|19|0|0^^$0|@$1|2|3|4|5|6|7|10|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|11|8|@$D|12|E|13|F|G]]|9|@]|A|$]]|$1|H|3|I|5|J|7|14|8|@]|9|@]|A|$K|L]]|$1|M|3|N|5|6|7|15|8|@$D|16|E|17|F|G]]|9|@]|A|$]]|$1|O|3|P|5|J|7|18|8|@]|9|@]|A|$K|L]]|$1|Q|3|R|5|6|7|19|8|@]|9|@$D|1A|E|1B|1|1C]]|A|$]]|$1|S|3|-4|5|6|7|1D|8|@]|9|@]|A|$]]]|T|$U|$5|V|W|X|A|$Y|Z]]]]

<p>Sure, just change it:</p>

<p>With jQuery's <code>$.each</code>:</p>

<pre><code>$.each(foo, function() {
    if (this.bar === 1) {
        this.baz[0] = 11;
        this.baz[1] = 22;
        this.baz[2] = 33;
        // Or: `this.baz = [11, 22, 33];`
    }
});
</code></pre>

<p>With ES5's <code>forEach</code>:</p>

<pre><code>foo.forEach(function(obj) {
    if (obj.bar === 1) {
        obj.baz[0] = 11;
        obj.baz[1] = 22;
        obj.baz[2] = 33;
        // Or: `obj.baz = [11, 22, 33];`
    }
});
</code></pre>

<p>...or you have <a href="https://stackoverflow.com/questions/9329446/for-each-in-a-array-how-to-do-that-in-javascript/9329476#9329476">other looping options in this other SO answer</a>.</p>


blocks|key|3568442|text|$.each(foo,function(index,value)
{
++++if(this.bar==1)
++++{
this.baz[0]+=+11;
++++++++this.baz[1]+=+22;
++++++++this.baz[2]+=+33;
++++}

});|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3568443|但是for循环比$.each快，所以你可以尝试使用|unstyled|3568444|for(var+i=0;+i+<foo.length;+i%2B%2B)
{

if(foo[i].bar==1)
{
//change+the+code
}
}|3568445|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$B|C]]|$1|D|3|E|5|F|7|L|8|@]|9|@]|A|$]]|$1|G|3|H|5|6|7|M|8|@]|9|@]|A|$B|C]]|$1|I|3|-4|5|F|7|N|8|@]|9|@]|A|$]]]|J|$]]

<pre><code>$.each(foo,function(index,value)
{
    if(this.bar==1)
    {
this.baz[0] = 11;
        this.baz[1] = 22;
        this.baz[2] = 33;
    }

});
</code></pre>

<p>but for loop is faster than $.each so u can try to use </p>

<pre><code>for(var i=0; i &lt;foo.length; i++)
{

if(foo[i].bar==1)
{
//change the code
}
}
</code></pre>


blocks|key|3568484|text|没有jQuery和向后兼容性|type|unstyled|depth|inlineStyleRanges|entityRanges|data|3568485|for+(var+i+=+0;+i+<+foo.length;+i%2B%2B)+{
++++if+(foo[i].bar+===+1)+{
++++++++foo[i].baz+=+[11,12,13];
++++}
}|code-block|syntax|javascript|3568486|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>Without jQuery and backwards compatibility</p>

<pre><code>for (var i = 0; i &lt; foo.length; i++) {
    if (foo[i].bar === 1) {
        foo[i].baz = [11,12,13];
    }
}
</code></pre>


blocks|key|1445824|text|我们也可以通过使用Array的map函数来实现：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1445825|+foo.map((obj)+=>+{
+++if(obj.bar+==+1){
+++++obj.baz[0]+=+11;
+++++obj.baz[1]+=+22;
+++++obj.baz[2]+=+33;
+++}
+})|code-block|syntax|javascript|1445826|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

<p>We can also achieve this by using Array's map function:</p>

<pre><code> foo.map((obj) =&gt; {
   if(obj.bar == 1){
     obj.baz[0] = 11;
     obj.baz[1] = 22;
     obj.baz[2] = 33;
   }
 })
</code></pre>


blocks|key|3568539|text|您可以使用find并更改其属性。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|3568540|​|3568541|let+foo+=+[{+bar:+1,+baz:+[1,2,3]+},+{+bar:+2,+baz:+[4,5,6]+}];

let+obj+=+foo.find(f=>f.bar==1);
if(obj)
++obj.baz=[2,3,4];
console.log(foo);|code-block|syntax|javascript|3568542|3568543|entityMap|0|LINK|mutability|MUTABLE|url|https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/find^0|5|4|5|4|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@$9|W|A|X|B|C]]|D|@$9|Y|A|Z|1|10]]|E|$]]|$1|F|3|G|5|6|7|11|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|12|8|@]|D|@]|E|$K|L]]|$1|M|3|G|5|6|7|13|8|@]|D|@]|E|$]]|$1|N|3|-4|5|6|7|14|8|@]|D|@]|E|$]]]|O|$P|$5|Q|R|S|E|$T|U]]]]

<p>You can use <a href="https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/find" rel="noreferrer"><code>find</code></a> and change its property.</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>let foo = [{ bar: 1, baz: [1,2,3] }, { bar: 2, baz: [4,5,6] }];

let obj = foo.find(f=&gt;f.bar==1);
if(obj)
  obj.baz=[2,3,4];
console.log(foo);</code></pre>
</div>
</div>
</p>


blocks|key|1445859|text|但在选择上述任何一种技术之前，请记住与每种方法相关的性能挑战。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1445860|Object+iterate+For-In,+average:+~240+microseconds.

Object+iterate+Keys+For+Each,+average:+~294+microseconds.

Object+iterate+Entries+For-Of,+average:+~535+microseconds.|code-block|syntax|javascript|1445861|参考-+3+JavaScript+Performance+Mistakes+You+Should+Stop+Doing|offset|length|1445862|entityMap|0|LINK|mutability|MUTABLE|url|https://hackernoon.com/3-javascript-performance-mistakes-you-should-stop-doing-ebf84b9de951^0|0|0|4|1J|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|T|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|U|8|@]|9|@$I|V|J|W|1|X]]|A|$]]|$1|K|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|L|$M|$5|N|O|P|A|$Q|R]]]]

<p>But before opting any of the mentioned techniques please keep in mind the performance challenges associated with each of the approach.</p>

<pre><code>Object iterate For-In, average: ~240 microseconds.

Object iterate Keys For Each, average: ~294 microseconds.

Object iterate Entries For-Of, average: ~535 microseconds.
</code></pre>

<p>Reference - <a href="https://hackernoon.com/3-javascript-performance-mistakes-you-should-stop-doing-ebf84b9de951" rel="nofollow noreferrer">3 JavaScript Performance Mistakes You Should Stop Doing</a></p>


blocks|key|1445875|text|你可以使用javascript的过滤功能。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1445876|​|1445877|obj+=+[
++++{inActive:false,+id:1},
++++{inActive:false,+id:2},
++++{inActive:false,+id:+3}
];
let+nObj+=+obj.filter(ele+=>+{
++++ele.inActive+=+true;
++++return+ele;
});

console.log(nObj);|code-block|syntax|javascript|1445878|1445879|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|K|$]]

<p>You can make use of filter function of javascript.</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>obj = [
    {inActive:false, id:1},
    {inActive:false, id:2},
    {inActive:false, id: 3}
];
let nObj = obj.filter(ele =&gt; {
    ele.inActive = true;
    return ele;
});

console.log(nObj);</code></pre>
</div>
</div>
</p>


blocks|key|405888|text|你可以尝试一下：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|405889|​|405890|const+tasks+=+[+{+id:+1,+done:+false+},+{+id:+2,+done:+false+}+]
const+completed_task+=+{+id:+1,+done:+true+}

const+markCompleted+=+(tasks,+task)+=>+{
++const+index+=+tasks.findIndex(t+=>+t.id+===+task.id);
++tasks.splice(index,+1);
++tasks.push(task);
++return+tasks;
}

console.log(tasks)
console.log(markCompleted(tasks,+completed_task))|code-block|syntax|javascript|405891|405892|编辑|offset|length|style|BOLD|405893|要避免索引更改：|405894|const+markCompleted+=+(tasks,+task)+=>+{
++++++const+index+=+tasks.findIndex(t+=>+t.id+===+task.id);
++++++tasks[index]+=+task;
++++++return+tasks;
++++}|405895|entityMap^0|0|0|0|0|0|2|0|0|0^^$0|@$1|2|3|4|5|6|7|V|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|W|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|X|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|Y|8|@]|9|@]|A|$]]|$1|J|3|K|5|6|7|Z|8|@$L|10|M|11|N|O]]|9|@]|A|$]]|$1|P|3|Q|5|6|7|12|8|@]|9|@]|A|$]]|$1|R|3|S|5|F|7|13|8|@]|9|@]|A|$G|H]]|$1|T|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|U|$]]

<p>you can play around: </p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>const tasks = [ { id: 1, done: false }, { id: 2, done: false } ]
const completed_task = { id: 1, done: true }

const markCompleted = (tasks, task) =&gt; {
  const index = tasks.findIndex(t =&gt; t.id === task.id);
  tasks.splice(index, 1);
  tasks.push(task);
  return tasks;
}

console.log(tasks)
console.log(markCompleted(tasks, completed_task))</code></pre>
</div>
</div>
</p>

<p><strong>EDIT</strong></p>

<p>to avoid index change: </p>

<pre><code>const markCompleted = (tasks, task) =&gt; {
      const index = tasks.findIndex(t =&gt; t.id === task.id);
      tasks[index] = task;
      return tasks;
    }
</code></pre>


blocks|key|1547128|text|带扩展(...)运算符的.map|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1547129|var+result+=+foo.map(el+=>+el.bar+==+1+?+{...el,+baz:+[11,22,33]}+:+el);|1547130|entityMap^0|4|3|C|4|0|0|20|0^^$0|@$1|2|3|4|5|6|7|J|8|@$9|K|A|L|B|C]|$9|M|A|N|B|C]]|D|@]|E|$]]|$1|F|3|G|5|6|7|O|8|@$9|P|A|Q|B|C]]|D|@]|E|$]]|$1|H|3|-4|5|6|7|R|8|@]|D|@]|E|$]]]|I|$]]

<p><code>.map</code> with <em>spread</em> (<code>...</code>) operator</p>

<p><code>var result = foo.map(el =&gt; el.bar == 1 ? {...el, baz: [11,22,33]} : el);</code></p>


blocks|key|404841|text|您可以使用简单的for循环来修改数组|type|unstyled|depth|inlineStyleRanges|entityRanges|data|404842|​|404843|var+foo+=+[{+bar:+1,+baz:+[1,2,3]+},+{+bar:+2,+baz:+[4,5,6]+}];
for(i+=+0;i+<+foo.length;i%2B%2B){
++//Here+your+confition+for+which+item+you+went+to+edit
	if(foo[i].bar+==+1){
++++//Here+you+logic+for+update+property
		foo[i].baz=+[1,11,22]
	}
}
console.log(foo);|code-block|syntax|javascript|404844|404845|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|L|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|M|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|N|8|@]|9|@]|A|$G|H]]|$1|I|3|C|5|6|7|O|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|P|8|@]|9|@]|A|$]]]|K|$]]

<p>You can modify the array by using simple for loop</p>

<p><div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre class="snippet-code-js lang-js prettyprint-override"><code>var foo = [{ bar: 1, baz: [1,2,3] }, { bar: 2, baz: [4,5,6] }];
for(i = 0;i &lt; foo.length;i++){
  //Here your confition for which item you went to edit
	if(foo[i].bar == 1){
    //Here you logic for update property
		foo[i].baz= [1,11,22]
	}
}
console.log(foo);</code></pre>
</div>
</div>
</p>


blocks|key|3568634|text|++++const+objArr+=+[
++++++++{prop1:+'value1',+prop2:+'value11'},
++++++++{prop1:+'value2',+prop2:+'value22'},
++++++++{prop1:+'value3',+prop2:+'option33'},
++++++++{prop1:+'value4',+prop2:+'option44'}
++++]

++++const+newObjArr+=+objArr.map(obj+=>+{
++++++++++++if+(['value1',+'value2'].includes(obj.prop1))+{
++++++++++++++++return+{...obj,+prop1:+'newValue'}
++++++++++++}
++++++++++++return+obj
++++++++}
++++)
++++
++++//+const+responseGotten+=+[
++++//+++++{+prop1:+'newValue',+prop2:+'value11'+},
++++//+++++{+prop1:+'newValue',+prop2:+'value22'+},
++++//+++++{+prop1:+'value3',+prop2:+'option33'+},
++++//+++++{+prop1:+'value4',+prop2:+'option44'+}
++++//+]|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3568635|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>    const objArr = [
        {prop1: 'value1', prop2: 'value11'},
        {prop1: 'value2', prop2: 'value22'},
        {prop1: 'value3', prop2: 'option33'},
        {prop1: 'value4', prop2: 'option44'}
    ]

    const newObjArr = objArr.map(obj =&gt; {
            if (['value1', 'value2'].includes(obj.prop1)) {
                return {...obj, prop1: 'newValue'}
            }
            return obj
        }
    )
    
    // const responseGotten = [
    //     { prop1: 'newValue', prop2: 'value11' },
    //     { prop1: 'newValue', prop2: 'value22' },
    //     { prop1: 'value3', prop2: 'option33' },
    //     { prop1: 'value4', prop2: 'option44' }
    // ]
</code></pre>


<pre><code>var foo = [{ bar: 1, baz: [1,2,3] }, { bar: 2, baz: [4,5,6] }];

var filtered = $.grep(foo, function(v){
    return v.bar === 1;
});

console.log(filtered);
</code></pre>

<p><a href="http://jsfiddle.net/98EsQ/">http://jsfiddle.net/98EsQ/</a></p>

<p>Is there any way to modify a certain objects property (like the one I'm filtering out above) without creating new arrays and/or objects?</p>

<p>Desired result: <code>[{ bar: 1, baz: [11,22,33] }, { bar: 2, baz: [4,5,6] }]</code></p>


Modify object property in an array of objects

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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var foo = [{ bar: 1, baz: [1,2,3] }, { bar: 2, baz: [4,5,6] }];var filtered = $.grep(foo, function(v){    return v.bar === 1;});console.log(filtered);有没有办法在不创建新...

问修改对象数组中的对象属性
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