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社区首页 >问答首页 >无法解析字符串值"${jwt.secret}“中的占位符”“jwt.secret”“

无法解析字符串值"${jwt.secret}“中的占位符”“jwt.secret”“
EN

Stack Overflow用户
提问于 2016-10-31 23:59:20
回答 4查看 11.6K关注 0票数 2

我已经使用注释配置了属性源:

@PropertySource(value = {"classpath:application.properties"}),但我仍然收到错误提示:Could not resolve placeholder 'jwt.secret' in string value

代码语言:javascript
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@PropertySource(value = {"classpath:application.properties"})
public class JwtAuthenticationTokenFilter extends AbstractAuthenticationProcessingFilter {

    @Value("${jwt.header}")
    private String tokenHeader;

    public JwtAuthenticationTokenFilter() {
        super("/**");
    }
}

dispatcher-servlet:

代码语言:javascript
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<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:context="http://www.springframework.org/schema/context"
       xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:security="http://www.springframework.org/schema/security"
       xmlns:jpa="http://www.springframework.org/schema/data/jpa"
       xmlns:tx="http://www.springframework.org/schema/tx"
       xsi:schemaLocation="
        http://www.springframework.org/schema/beans     
        http://www.springframework.org/schema/beans/spring-beans-4.1.xsd
        http://www.springframework.org/schema/context 
        http://www.springframework.org/schema/context/spring-context-4.1.xsd
        http://www.springframework.org/schema/mvc
        http://www.springframework.org/schema/mvc/spring-mvc-4.1.xsd
        http://www.springframework.org/schema/security 
        http://www.springframework.org/schema/security/spring-security-4.1.xsd
        http://www.springframework.org/schema/data/jpa
        http://www.springframework.org/schema/data/jpa/spring-jpa.xsd
        http://www.springframework.org/schema/tx
        http://www.springframework.org/schema/tx/spring-tx.xsd">

    <context:component-scan base-package="com.rsc."/>
    <mvc:annotation-driven />

    <mvc:resources mapping="/resources/**" location="/resources/"/>

    <bean id="messageSource" class="org.springframework.context.support.ReloadableResourceBundleMessageSource">
        <property name="basenames">
            <list>
                <value>classpath:validation</value>
            </list>
        </property>
    </bean>

<!--    <bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
        <property name="locations">
            <list>
                <value>classpath:application.yml</value>
            </list>
        </property>
    </bean>-->

    <!--    <security:authentication-manager alias="authenticationManager">
        <security:authentication-provider user-service-ref="userDetailsServiceImpl">
            <security:password-encoder ref="encoder"></security:password-encoder>
        </security:authentication-provider>
    </security:authentication-manager>-->   

    <!--<bean id="userDetailsServiceImpl" class="com.rsc.service.UserDetailsServiceImpl"></bean>-->

    <bean id="JwtAuthenticationTokenFilter" class="com.rsc.security.JwtAuthenticationTokenFilter">
        <property name="authenticationManager" ref="authenticationManager" />
        <property name="authenticationSuccessHandler" ref="jwtAuthenticationSuccessHandler" />
    </bean>

    <security:authentication-manager alias="authenticationManager">
        <security:authentication-provider ref="jwtAuthenticationProvider" />
    </security:authentication-manager>

    <bean id="encoder" class="org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder">
        <constructor-arg name="strength" value="11"/>
    </bean>

    <!-- Configure the data source bean -->
    <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
        <property name="driverClassName" value="${jdbc.driverClassName}"/>
        <property name="url" value="${jdbc.url}"/>
        <property name="username" value="${jdbc.username}"/>
        <property name="password" value="${jdbc.password}"/>
    </bean>

    <!-- Configure the entity manager factory bean -->
    <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
        <property name="dataSource" ref="dataSource"/>
        <property name="packagesToScan" value="com.rsc.model"/>
        <property name="jpaVendorAdapter">
            <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"/>
        </property>
        <property name="jpaProperties">
            <props>
                <prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop>
                <prop key="hibernate.show_sql">true</prop>
                <prop key="hbm2ddl.auto">create</prop>
                <prop key="hibernate.id.new_generator_mappings">false</prop>
            </props>
        </property>
    </bean>

    <!-- Configure the transaction manager bean -->
    <bean id="transactionManager"
          class="org.springframework.orm.jpa.JpaTransactionManager">
        <property name="entityManagerFactory" ref="entityManagerFactory"/>
    </bean>

    <!-- Enable annotation driven transaction management -->
    <tx:annotation-driven/>

    <jpa:repositories base-package="com.rsc.repository"/>

    <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="prefix" value="/WEB-INF/views/"/>
        <property name="suffix" value=".jsp"/>
    </bean>
</beans>

应用程序属性:

代码语言:javascript
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jdbc.driverClassName=com.mysql.jdbc.Driver
jdbc.url=jdbc:mysql://localhost:3306/rs_education
jdbc.username=admin
jdbc.password=admin

jwt:
  header: Authorization
  secret: my-very-secret-key
logging:
  level:
    org.springframework.security: DEBUG
server:
  port: 8888
spring:
  resources:
    chain:
      enabled: true
management:
  security:
    enabled: true # set to false to disable 'default' Spring Boot security
EN

回答 4

Stack Overflow用户

发布于 2016-11-01 00:11:53

如果你想使用yaml,你的文件应该被命名为application.yml,你可以使用这种格式。

代码语言:javascript
运行
复制
jwt:
  header: Authorization
  secret: my-very-secret-key

如果您希望使用属性样式格式,则应将文件命名为application.properties,并使用以下格式:

代码语言:javascript
运行
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jwt.header=Authorization
jwt.secret=my-very-secret-key
票数 5
EN

Stack Overflow用户

发布于 2016-11-01 00:29:56

正如文档所述,您可以使用YAML,但您必须将文件命名为application.yml而不是application.properties

您还必须将snakeyaml添加到依赖项中。

票数 2
EN

Stack Overflow用户

发布于 2020-12-08 10:11:50

我发现了一个新的细节:如果你使用多模块,那么这个属性将写入主yaml/properties。不要使用模块的yaml/properties。它无法被扫描。

票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/40345927

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