blocks|key|1466959|text|你可以使用下面的代码：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1466960|bar+=+$('form').serialize();
bar+%2B=+'&foo=xyz';
console.log(bar);|code-block|syntax|javascript|1466961|目前，您正尝试将bar用作数组(或注释代码中的对象)。.serialize()实际上会生成一个URL编码的字符串，所以你可以简单地将你的值附加到它上面。|offset|length|style|CODE|1466962|entityMap|0|LINK|mutability|MUTABLE|url|http://api.jquery.com/serialize/^0|0|0|8|3|R|C|R|C|0|0^^$0|@$1|2|3|4|5|6|7|U|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|V|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|W|8|@$I|X|J|Y|K|L]|$I|Z|J|10|K|L]]|9|@$I|11|J|12|1|13]]|A|$]]|$1|M|3|-4|5|6|7|14|8|@]|9|@]|A|$]]]|N|$O|$5|P|Q|R|A|$S|T]]]]

You can just use this:

<pre><code>bar = $('form').serialize();
bar += '&amp;foo=xyz';
console.log(bar);
</code></pre>

Currently you're trying to use <code>bar</code> as an array (or an object in your commented code). <a href="http://api.jquery.com/serialize/" rel="nofollow"><code>.serialize()</code></a> actually generates a URL-ecoded string so you can simply append your value to it.

blocks|key|416307|text|bar是序列化的表单数据。它是一个字符串而不是一个对象。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|BOLD|entityRanges|data|416308|如果你想添加数据，你需要序列化数据：|416309|bar+%2B=+"&"+%2B+encodeURIComponent('foo')+%2B+"="+%2B+encodeURIComponent('xyz');|code-block|syntax|javascript|416310|(如果知道数据中没有URL特殊字符，则可以跳过encode+URI组件)。|416311|entityMap^0|0|3|4|4|0|0|0|3|Y|0^^$0|@$1|2|3|4|5|6|7|R|8|@$9|S|A|T|B|C]|$9|U|A|V|B|D]]|E|@]|F|$]]|$1|G|3|H|5|6|7|W|8|@]|E|@]|F|$]]|$1|I|3|J|5|K|7|X|8|@]|E|@]|F|$L|M]]|$1|N|3|O|5|6|7|Y|8|@$9|Z|A|10|B|D]]|E|@]|F|$]]|$1|P|3|-4|5|6|7|11|8|@]|E|@]|F|$]]]|Q|$]]

<code>bar</code> is serialized form data. It is a string not an object.

If you want to add data do it you need to serialize that data:

<pre><code>bar += "&amp;" + encodeURIComponent('foo') + "=" + encodeURIComponent('xyz');
</code></pre>

(You can skip the encode URI components if you know that the data has no URL special characters in it).

blocks|key|1556964|text|更改为：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1556965|bar+=+$('form').serializeArray();
bar["foo"]='xyz';|code-block|syntax|javascript|1556966|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

change to:

<pre><code>bar = $('form').serializeArray();
bar["foo"]='xyz';
</code></pre>

blocks|key|415511|text|这里的其他答案谈到了如何绕过这个问题，但没有人解释为什么会发生这种情况，所以我想我会试一试。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|415512|下面是后台正在发生的事情：|415513|415514|您可以调用.serialize，它会生成一个字符串|unordered-list-item|offset|length|style|CODE|415515|415516|JavaScript中的|415517|字符串是原始值类型，因此当您向其添加属性时，它的"autoboxes“将成为该调用的String引用类型对象。|415518|415519|415520|将属性赋值给它，该属性将添加到已装箱的object|415521|中|415522|415523|console.log(bar);记录了bar对象，它已经是一个字符串，它也是一个原始值类型。这既是因为String类型的toString，也因为bar是一个原始值类型，所以您将获得相同的初始值。|415524|415525|您可以在the+secret+life+of+primitives+in+JavaScript.或the+specification中阅读有关此内容的更多信息|415526|如何修复它？|415527|参见How+to+add+a+value+to+jQuery+serialize。这个问题已经在那里得到了回答。|415528|entityMap|0|LINK|mutability|MUTABLE|url|http://javascriptweblog.wordpress.com/2010/09/27/the-secret-life-of-javascript-primitives/|1|http://es5.github.com/|2|https://stackoverflow.com/questions/6539502/this-serialize-how-to-add-a-value^0|0|0|0|5|A|0|0|0|16|6|0|0|0|0|0|0|0|H|21|3|0|0|4|18|0|1D|H|1|0|0|2|12|2|0^^$0|@$1|2|3|4|5|6|7|1I|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|1J|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|1K|8|@]|9|@]|A|$]]|$1|E|3|F|5|G|7|1L|8|@$H|1M|I|1N|J|K]]|9|@]|A|$]]|$1|L|3|-4|5|6|7|1O|8|@]|9|@]|A|$]]|$1|M|3|N|5|6|7|1P|8|@]|9|@]|A|$]]|$1|O|3|P|5|G|7|1Q|8|@$H|1R|I|1S|J|K]]|9|@]|A|$]]|$1|Q|3|-4|5|6|7|1T|8|@]|9|@]|A|$]]|$1|R|3|-4|5|6|7|1U|8|@]|9|@]|A|$]]|$1|S|3|T|5|G|7|1V|8|@]|9|@]|A|$]]|$1|U|3|V|5|6|7|1W|8|@]|9|@]|A|$]]|$1|W|3|-4|5|6|7|1X|8|@]|9|@]|A|$]]|$1|X|3|Y|5|G|7|1Y|8|@$H|1Z|I|20|J|K]|$H|21|I|22|J|K]]|9|@]|A|$]]|$1|Z|3|-4|5|6|7|23|8|@]|9|@]|A|$]]|$1|10|3|11|5|6|7|24|8|@]|9|@$H|25|I|26|1|27]|$H|28|I|29|1|2A]]|A|$]]|$1|12|3|13|5|6|7|2B|8|@]|9|@]|A|$]]|$1|14|3|15|5|6|7|2C|8|@]|9|@$H|2D|I|2E|1|2F]]|A|$]]|$1|16|3|-4|5|6|7|2G|8|@]|9|@]|A|$]]]|17|$18|$5|19|1A|1B|A|$1C|1D]]|1E|$5|19|1A|1B|A|$1C|1F]]|1G|$5|19|1A|1B|A|$1C|1H]]]]

Other answers here talk about how one might get around this, but no one is explaining why this is happening, so I figured I'll give it a shot.
<h3>Here is what is happening in the background:</h3>
<ul>
<li>You call <code>.serialize</code> which produces a string
</li>
<li>Strings in JavaScript are primitive value types, so when you add a property to it, it &quot;autoboxes&quot; becomes a <code>String</code> reference type object for that call.
</li>
<li>You assign the property to it, which is added to the boxed object
</li>
<li><code>console.log(bar);</code> logs the bar object, which is already again a string which is a primitive value type. Both because toString of the String type, and because of the <code>bar</code> being a primitive value type, you get the same initial value.
</li>
</ul>
You can read more about this in <a href="http://javascriptweblog.wordpress.com/2010/09/27/the-secret-life-of-javascript-primitives/" rel="nofollow noreferrer">the secret life of primitives in JavaScript.</a> Or in <a href="http://es5.github.com" rel="nofollow noreferrer">the specification</a>
<h3>How to fix it</h3>
See <a href="https://stackoverflow.com/questions/6539502/this-serialize-how-to-add-a-value">How to add a value to jQuery serialize</a> . That has already been answered there.

I'm using the following code in an attempt to add a new attribute to bar object:

<pre><code>$(document).ready(function(){
 $('form').on("submit",preventDefault);
});

function preventDefault(e) {
 e.preventDefault();
 $url="contact/send";
 bar = $('form').serialize();
 bar["foo"]='xyz';
 //bar.foo="123";
 console.log(bar);
}
</code></pre>

However I don't ever seem to get the value of bar.foo. If I look at the console in Chrome I always get a result similar to this: 

<pre><code>name=Grahame&amp;email=foo%40bar.com&amp;message=Hello.
</code></pre>

Why am I not getting the value/property of foo?

Why can't I append to my JSON object? (jQuery/Javascript)

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

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我使用下面的代码来尝试向bar对象添加一个新属性：$(document).ready(function(){    $('form').on("submit",preventDefault);});function preventDefault(e) {    e.preventDefault();    $url="...

问为什么我不能追加到我的JSON对象？(jQuery/Javascript)
EN

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问为什么我不能追加到我的JSON对象？(jQuery/Javascript)EN