blocks|key|409689|text|我的想法是将名字和日期分开，然后压缩两个序列，一次组合一个名字-日期对。之后，用'%7C‘符号连接每一对|type|unstyled|depth|inlineStyleRanges|entityRanges|data|409690|string[]+names+=+{"name1",+"name2"};
string[]+dates+=+{"date1",+"date2"};

var+pairs+=+names.Zip(dates,+(name,+date)+=>+name+%2B+","+%2B+date);

string+result+=+string.Join("%7C",+pairs);

Console.WriteLine(result);|code-block|syntax|javascript|409691|打印：|409692|name1,date1%7Cname2,date2|409693|entityMap^0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|N|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|O|8|@]|9|@]|A|$]]|$1|I|3|J|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|K|3|-4|5|6|7|Q|8|@]|9|@]|A|$]]]|L|$]]

Idea is to split names and dates separately, then zip two sequences, combining name-date pair one at a time. After that join each pair with '|' symbol

<pre><code>string[] names = {"name1", "name2"};
string[] dates = {"date1", "date2"};

var pairs = names.Zip(dates, (name, date) =&gt; name + "," + date);

string result = string.Join("|", pairs);

Console.WriteLine(result);
</code></pre>

prints:

<pre><code>name1,date1|name2,date2
</code></pre>

blocks|key|1453906|text|对我来说，您的代码似乎是不必要的复杂。不完全确定这将满足您的所有要求，但我会这样做；|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1453907|++//assuming+both+strings+are+comma+delimited
++string[]+nameTokens+=+nameString.Split(',');
++string[]+dateTokens+=+dateString.Split(',');
++string+result;
++if+(nameTokens.Length+==+2+&&+dateTokens.Length+==+2)
++++++result+=+String.Format("{1},{2}%7C{3},{4}",+nameTokens[0],+dateTokens[0],+nameTokens[1],+dateTokens[1]);
++else
+++++++Console.WriteLine("BAD+INPUT");|code-block|syntax|javascript|1453908|说明:我从拆分name和date字符串开始，所以我有两个字符串数组。然后我检查长度以确保每个长度都有2个元素(防止数组越界异常)。之后，我使用String.Format方法以指定的格式创建一个新字符串。然而，使用LINQ有更短的解决方案可用，这确保您不会得到超出界限的数组异常，并且不能更直接。|offset|length|style|CODE|1453909|entityMap^0|0|0|1Z|D|0^^$0|@$1|2|3|4|5|6|7|O|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|P|8|@]|9|@]|A|$E|F]]|$1|G|3|H|5|6|7|Q|8|@$I|R|J|S|K|L]]|9|@]|A|$]]|$1|M|3|-4|5|6|7|T|8|@]|9|@]|A|$]]]|N|$]]

Your code seems needlessly complex to me. Not entirely sure this will meet all of your requirements but I would do something like this;

<pre><code> //assuming both strings are comma delimited
 string[] nameTokens = nameString.Split(',');
 string[] dateTokens = dateString.Split(',');
 string result;
 if (nameTokens.Length == 2 &amp;&amp; dateTokens.Length == 2)
 result = String.Format("{1},{2}|{3},{4}", nameTokens[0], dateTokens[0], nameTokens[1], dateTokens[1]);
 else
 Console.WriteLine("BAD INPUT");
</code></pre>

Explanation; I start by splitting the name and date strings so I have two strings arrays. Then I check the lengths to make sure they each have 2 elements (prevent array out of bounds exceptions). After that I use the <code>String.Format</code> method to create a new string in the specified format. There are shorter solutions available using LINQ however, this ensures that you don't get an array out of bounds exception and could not be more straight forward.

blocks|key|409716|text|你可以使用LINQ的Select方法。其中一个重载需要Func。这将为您提供数组中当前字符串的索引。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|409717|var+result+=+string.Join("%7C",+
++++names.Select((s,+index)+=>+string.Format("{0},{1}",+s,+dates[index])));|code-block|syntax|javascript|409718|entityMap|0|LINK|mutability|MUTABLE|url|http://msdn.microsoft.com/en-us/library/bb534869.aspx^0|A|6|R|4|R|4|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]|$9|V|A|W|B|C]]|D|@$9|X|A|Y|1|Z]]|E|$]]|$1|F|3|G|5|H|7|10|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|11|8|@]|D|@]|E|$]]]|L|$M|$5|N|O|P|E|$Q|R]]]]

You could use LINQ's <code>Select</code> method. One of the overloads takes a <a href="http://msdn.microsoft.com/en-us/library/bb534869.aspx" rel="nofollow"><code>Func&lt;TSource, Int32, TResult&gt;</code></a>. This gives you the index of the current string in the array. 

<pre><code>var result = string.Join("|", 
 names.Select((s, index) =&gt; string.Format("{0},{1}", s, dates[index])));
</code></pre>

blocks|key|3576580|text|string+strCombinedString+=+strFirstStringArray.Select((S,+i)+=>+"%7C"+%2B+S+%2B+","+%2B+strSecondStringArray[i]).Aggregate((Result,+Item)+=>+Result+%2B=+Item);
strCombinedString.Remove(0,+1);|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|3576581|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>string strCombinedString = strFirstStringArray.Select((S, i) =&gt; "|" + S + "," + strSecondStringArray[i]).Aggregate((Result, Item) =&gt; Result += Item);
strCombinedString.Remove(0, 1);
</code></pre>

I want to have an string in this format 

<pre><code> name1,date1|name2,date2
</code></pre>

For that I have written a method 

<pre><code>int ifirstStringLength = strFirstStringArray.Length;
int iSecondStringLength = strSecondStringArray.Length;

if (ifirstStringLength != iSecondStringLength)
 throw new Exception("First and Second Array should be of same length");

for (int index = 0; index &lt; ifirstStringLength; index++)
{
 strCombinedString = strCombinedString + strFirstStringArray[index] + chrElementSeprator.ToString() + strSecondStringArray[index];
 if (index &lt; ifirstStringLength - 1)
 strCombinedString = strCombinedString + chrItemSeperator.ToString();
}

return strCombinedString;
</code></pre>

Question 1: 
Is this a good way or any better way?

Question 2: 
Any idea if I want to achieve this using linq/lambda expression?

Updated: 

my inputs are 

<pre><code> string[] names = {"name1","name2"};
 string[] dates = {"date1","date2"};
</code></pre>

sorry for miscommunication

String building with particular pattern using char separator

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

我想要有一个这种格式的字符串 name1,date1|name2,date2为此，我编写了一个方法int ifirstStringLength = strFirstStringArray.Length;int iSecondStringLength = strSecondStringArray.Length;if (i...

问使用字符分隔符构建具有特定模式的字符串
EN

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问使用字符分隔符构建具有特定模式的字符串EN