表1- tblCompanion
companionid | companionname    | who played
--------------------------------------------------- 
1           | River Song       | Alex Kingston
2           | Rory Williams    | Arthur Darvill
3           | Wilfred Mott     | Bernard Cribbins
4           | Rose Tyler       | Billie Piper
5           | Adam Mitchell    | Bruno Langley
6           | Donna Noble      | Catherine Tate
7           | Jackson Lake     | David Morrissey
8           | Sarah Jane Smith | Elisabeth Sladen
.           | .                | .
.           | .                | .
.           | .                | .表2- tblEpisodeCompanion
Episodecompanionid | EpisodeId | companionid
---------------------------------------------
1                  | 1         | 4
2                  | 2         | 4
3                  | 3         | 4
4                  | 4         | 4
5                  | 5         | 4
6                  | 6         | 4
7                  | 7         | 4
8                  | 8         | 6
9                  | 9         | 6
10                 | 10        | 6
11                 | 11        | 1
12                 | 12        | 1
13                 | 13        | 2
.                  | .         | .
.                  | .         | .
.                  | .         | .从这两个表中,我希望得到以下结果:
No | companianName | Episodes
-----------------------------
1  | Amy Pond      | 33
2  | Rose Tyler    | 32
3  | Rory Williams | 25我已经尝试了几个小时了,但是无法得到上面这样的结果集,请解释一下如何解决这个问题。
发布于 2016-11-07 22:41:45
这个查询应该会为您做到这一点:
SELECT TOP 3 
    tblCompanion.companionname, 
    Count(*) AS Episodes
FROM tblEpisodeCompanion 
    INNER JOIN tblCompanion 
        ON tblEpisodeCompanion.companionid = tblCompanion.companionid
GROUP BY tblCompanion.companionname
ORDER BY Count(*) DESChttps://stackoverflow.com/questions/40467717
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