Java多线程
Java多线程
提问于 2013-06-08 22:07:48
我必须使用两个线程，一个线程打印所有小于10的奇数，另一个线程打印小于10的偶数，最终输出应该是按顺序的。
我已经做到了以下几点。我想用同步的方法做同样的事情？该怎么做呢？
class printodd extends Thread{
public void run() {
super.run();
for(int i=0;i<10;i=i+2){
System.out.println("even "+i);
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
class printeven extends Thread{
public void run() {
super.run();
for(int i=1;i<10;i=i+2)
{
System.out.println("odd "+i);
try {
Thread.sleep(1050);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
public class PrintNumSeq{
public static void main(String[] args) {
printodd p=new printodd();
printeven e=new printeven();
e.start();
p.start();
}
}回答 4
Stack Overflow用户
回答已采纳
发布于 2013-06-08 23:00:38
尝尝这个
public class PrintNumSeq extends Thread {
static Object lock = new Object();
static int n;
int even;
PrintNumSeq(int r) {
this.even = r;
}
public void run() {
try {
synchronized (lock) {
for (;;) {
while ((n & 1) != even) {
lock.wait();
}
n++;
lock.notify();
if (n > 10) {
break;
}
System.out.println(n);
}
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
public static void main(String[] args) {
new PrintNumSeq(1).start();
new PrintNumSeq(0).start();
}
}输出
1
2
3
4
5
6
7
8
9
10Stack Overflow用户
发布于 2013-11-18 19:18:18
public class SequentialThreadPrinter {
public static void main(String[] args) {
AtomicInteger counter = new AtomicInteger(0);
EvenThread even = new EvenThread("even", counter);
OddThread odd = new OddThread("odd", counter);
even.start();
odd.start();
}
}
private static class EvenThread extends Thread {
private String name;
private AtomicInteger counter;
public EvenThread(String name, AtomicInteger counter) {
this.name = name;
this.counter = counter;
}
public void run() {
do {
synchronized (counter) {
if (counter.get() % 2 == 0) {
System.out.println("Thread is " + name + ", Counter is = " + counter.getAndAdd(1));
counter.notifyAll();
} else {
try {
counter.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
} while (counter.get() <= 10);
}
}
private static class OddThread extends Thread {
private String name;
private AtomicInteger counter;
public OddThread(String name, AtomicInteger counter) {
this.name = name;
this.counter = counter;
}
public void run() {
do {
synchronized (counter) {
if (counter.get() % 2 != 0) {
System.out.println("Thread is " + name + ", Counter is = " + counter.getAndAdd(1));
counter.notifyAll();
} else {
try {
counter.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
} while (counter.get() <= 10);
}
}}
Stack Overflow用户
发布于 2013-06-08 22:18:23
嗨，在这里你必须使用java同步。基本上，同步是在线程之间共享的Java机制，它会在一个线程运行时阻塞所有其他线程。在您的情况下，通过这样做，您可以按顺序打印它们。您可以阅读下面的教程来理解它
http://docs.oracle.com/javase/tutorial/essential/concurrency/syncmeth.html http://docs.oracle.com/javase/tutorial/essential/concurrency/locksync.html
但在使用它时要小心，因为不小心使用可能会造成死锁http://docs.oracle.com/javase/tutorial/essential/concurrency/deadlock.html
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/17000311
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